Solute S has a distribution constant of 5.1 between water (phase 1) and hexane (phase 2). A 71.0 mL solution of S in water is extracted three times with 12.0 mL of hexane. Calculate the fraction of S remaining in the aqueous phase.
Solute S has a distribution constant of 5.1 between water (phase 1) and hexane (phase 2). A 71.0 mL solution of S in water is extracted three times with 12.0 mL of hexane. Calculate the fraction of S remaining in the aqueous phase.
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter12: Solutions
Section: Chapter Questions
Problem 12.19QE
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![Solute S has a distribution constant of 5.1 between water (phase 1) and hexane (phase 2). A 71.0 mL solution of S in water is
extracted three times with 12.0 mL of hexane. Calculate the fraction of S remaining in the aqueous phase.
fraction remaining:
0.0575
Incorrect](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faf8dd5bb-1368-4a10-9929-9294802d0b74%2Fad321e67-fc40-4432-8807-cd62be3e703f%2Fhubfnso_processed.png&w=3840&q=75)
Transcribed Image Text:Solute S has a distribution constant of 5.1 between water (phase 1) and hexane (phase 2). A 71.0 mL solution of S in water is
extracted three times with 12.0 mL of hexane. Calculate the fraction of S remaining in the aqueous phase.
fraction remaining:
0.0575
Incorrect
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