A solution is prepared by dissolving 40.00 g of NaCl (f.w. = 58.44 g mol–1), a non-volatile solute, in enough water (m.w. = 18.02 g mol–1) to result in exactly 1 L of solution at 25 °C. Assume the density of the solution is that of pure water (dsolution = 1.000 g mL–1).The ebullioscopic constant (Kb) for water is 0.513 °C m–1.The cryoscopic constant (Kf) for water is 1.86 °C m–1.The vapor pressure of pure water is 0.0313 atm.Determine the boiling point of the solution(in C to 2 decimal places)

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Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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A solution is prepared by dissolving 40.00 g of NaCl (f.w. = 58.44 g mol^–1), a non-volatile solute, in enough water (m.w. = 18.02 g mol^–1) to result in exactly 1 L of solution at 25 °C. Assume the density of the solution is that of pure water (d_solution = 1.000 g mL^–1).

The ebullioscopic constant (K_b) for water is 0.513 °C m^–1.
The cryoscopic constant (K_f) for water is 1.86 °C m^–1.
The vapor pressure of pure water is 0.0313 atm.

Determine the boiling point of the solution(in C to 2 decimal places)

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Step 1

Given :

Mass of solute = 40g

Density = 1.000g/ml

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