small stone is kicked from the edge of a cliff. Its x- and y-coordinates as functions of time are given by x = 19.4t and y = 3.76t - 4.90t2, where x and y are in meters and t is in seconds. (Do not include units in "our answer.) (a) Write a vector expression for the stone's position as a function of time (in m), using the unit vectors i and j. (Give the answer in terms of t.) r= y taking derivatives, do the following. b) Obtain the expression for the velocity vector v as a function of time (in m/s). (Give the answers in terms of t.) V= a= m c) Obtain the expression for the acceleration vector a as a function of time (in m/s2). m/s2 V= m/s d) Next, use unit-vector notation to write expressions for the position, the velocity, and the acceleration of the stone at t= 3.18 s. (Assume the position is in m, the velocity is in m/s and the acceleration is in m/s².) a = m m/s m/s² 4
small stone is kicked from the edge of a cliff. Its x- and y-coordinates as functions of time are given by x = 19.4t and y = 3.76t - 4.90t2, where x and y are in meters and t is in seconds. (Do not include units in "our answer.) (a) Write a vector expression for the stone's position as a function of time (in m), using the unit vectors i and j. (Give the answer in terms of t.) r= y taking derivatives, do the following. b) Obtain the expression for the velocity vector v as a function of time (in m/s). (Give the answers in terms of t.) V= a= m c) Obtain the expression for the acceleration vector a as a function of time (in m/s2). m/s2 V= m/s d) Next, use unit-vector notation to write expressions for the position, the velocity, and the acceleration of the stone at t= 3.18 s. (Assume the position is in m, the velocity is in m/s and the acceleration is in m/s².) a = m m/s m/s² 4
Related questions
Question
Expert Solution
Step 1u
Step by step
Solved in 2 steps with 2 images