A polo ball is hit with a mallet off the edge of a cliff. Its x- and y-coordinates as functions of time are given by x = 16.8t and y = 3.72t - 4.90t2, where x and y are in meters and t is in seconds. (Do not include units in your answer.) (a) Write a vector expression for the ball's position as a function of time (in m), using the unit vectors î and ĵ. (Give the answer in terms of t.) r = By taking derivatives, do the following. (b) Obtain the expression for the velocity vector v as a function of time (in m/s). (Give the answers in terms of t.) V = a = m (c) Obtain the expression for the acceleration vector a as a function of time (in m/s²). m/s² ✓ m/s (d) Next, use unit-vector notation to write expressions for the position, the velocity, and the acceleration of the polo ball at t = 2.85 s. (Assume the position is in m, the velocity is in m/s and the acceleration is in m/s2.) = m m/s m/s²

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Chapter1: Units, Trigonometry. And Vectors
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## Problem Statement

A polo ball is hit with a mallet off the edge of a cliff. Its \(x\)- and \(y\)-coordinates as functions of time are given by \(x = 16.8t\) and \(y = 3.72t - 4.90t^2\), where \(x\) and \(y\) are in meters and \(t\) is in seconds. (Do not include units in your answer.)

### (a) Position Vector Expression

Write a vector expression for the ball's position as a function of time (in m), using the unit vectors \(\hat{\imath}\) and \(\hat{\jmath}\). (Give the answer in terms of \(t\).)

\[
\vec{r} = \boxed{}
\]

### (b) Velocity Vector Expression

By taking derivatives, do the following:

Obtain the expression for the velocity vector \(\vec{v}\) as a function of time (in m/s). (Give the answers in terms of \(t\).)

\[
\vec{v} = \boxed{}
\]

### (c) Acceleration Vector Expression

Obtain the expression for the acceleration vector \(\vec{a}\) as a function of time (in m/s\(^2\)).

\[
\vec{a} = \boxed{}
\]

### (d) Vector Expressions at \(t = 2.85\) s

Next, use unit-vector notation to write expressions for the position, the velocity, and the acceleration of the polo ball at \(t = 2.85\) s. (Assume the position is in m, the velocity is in m/s and the acceleration is in m/s\(^2\).)

\[
\vec{r} = \boxed{}
\]

\[
\vec{v} = \boxed{}
\]

\[
\vec{a} = \boxed{}
\]
Transcribed Image Text:## Problem Statement A polo ball is hit with a mallet off the edge of a cliff. Its \(x\)- and \(y\)-coordinates as functions of time are given by \(x = 16.8t\) and \(y = 3.72t - 4.90t^2\), where \(x\) and \(y\) are in meters and \(t\) is in seconds. (Do not include units in your answer.) ### (a) Position Vector Expression Write a vector expression for the ball's position as a function of time (in m), using the unit vectors \(\hat{\imath}\) and \(\hat{\jmath}\). (Give the answer in terms of \(t\).) \[ \vec{r} = \boxed{} \] ### (b) Velocity Vector Expression By taking derivatives, do the following: Obtain the expression for the velocity vector \(\vec{v}\) as a function of time (in m/s). (Give the answers in terms of \(t\).) \[ \vec{v} = \boxed{} \] ### (c) Acceleration Vector Expression Obtain the expression for the acceleration vector \(\vec{a}\) as a function of time (in m/s\(^2\)). \[ \vec{a} = \boxed{} \] ### (d) Vector Expressions at \(t = 2.85\) s Next, use unit-vector notation to write expressions for the position, the velocity, and the acceleration of the polo ball at \(t = 2.85\) s. (Assume the position is in m, the velocity is in m/s and the acceleration is in m/s\(^2\).) \[ \vec{r} = \boxed{} \] \[ \vec{v} = \boxed{} \] \[ \vec{a} = \boxed{} \]
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