SITUATION II: Calculate the permissible tensile load P 50 under the following conditions: Fy3248 MPa; Fu=600 MPa. The diameter of the bolts is 16 mm. V16 A 50 100 50 50 100 100 50 50 Allowable stresses: Tensile stresses on gross area: 0.6Fy Shear stress of the bolts: Fv=130 MPa Bearing stress of the bolts: Fp=1.2Fu 7. Based on shear capacity of bolts. a. 156.83 kN b. 1105.92 kN C. 475.21 kN d. 450.78 kN 8. Based on the bearing capacity of bolts. a. 156.83 kN C. 475.21 kN b. 1105.92 kN d. 450.78 kN 9. Based on the yielding of plates. b. 1105.92 kN d. 450.78 kN a. 156.83 kN C. 475.21 kN

SITUATION II: Calculate the permissible tensile load P 50 under the following conditions: Fy3248 MPa; Fu=600 MPa. The diameter of the bolts is 16 mm. V16 A 50 100 50 50 100 100 50 50 Allowable stresses: Tensile stresses on gross area: 0.6Fy Shear stress of the bolts: Fv=130 MPa Bearing stress of the bolts: Fp=1.2Fu 7. Based on shear capacity of bolts. a. 156.83 kN b. 1105.92 kN C. 475.21 kN d. 450.78 kN 8. Based on the bearing capacity of bolts. a. 156.83 kN C. 475.21 kN b. 1105.92 kN d. 450.78 kN 9. Based on the yielding of plates. b. 1105.92 kN d. 450.78 kN a. 156.83 kN C. 475.21 kN

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Subject: Steel design- Bolted Steel Connection - Bolted Subjected to Eccentric Loads *Use NSCP 2015 formula/guide to solve this problem *Use Handwritten
An A36 tension member shown in the figure is connected with three 19 mm diamter bolts. Diameter of hole = 22mm. Properties of 150 mm x 100 mm x 12.5 mm angle A = 3065 mm2 y = 50.55 mm Fy = 248 MPa Fu = 400 MPa Determine the design strength due to yielding in the gross section. (kN)
Please answer asap with clear and complete solutions .thank you
How
Plate connection with bolts with shear strength value T=200 MPA is given in the figure. Determine the minimum required bolt diameter for the safe transfer of the P=70 kN load.
Determine the capacity of the details shown below.A992: Fy=50ksi, Fu=65ksiA36: Fy=36ksi, Fu=58ksieffective bolt hole diameter = bolt hole + 1/16"beam properties: tw=0.38 in., bf=7.07 in., tf=0.63 in.Fexx=70ksip) what is the tensile yielding capacity of flange plate of the flange connection in kips? (2 decimal places)
Use ASD to determine the width of the 5/8 inch thick A36 plate subjected to tension as shown below. The dead load effect is PD=85 kip while the live load effect is PL=80 kip. Two rows of 5/8 inch standard bolts will be used for the connection and the plate width can be manufactured in 1 inch increments. Assume that the larger connected plate does not fail. Consider the limit states of gross tensile yield and tensile rupture. Find the required tension strength, Pa, for the controlling ASD load combination. Determine the width necessary for the plate to resist gross tensile yield. Determine the width necessary for the plate to resist tensile rupture. Report the required plate width.
2. For the figure shown, calculate the net area of the 10 x 200 mm plate. The plate is connected at its end with two lines of 20 mm bolts. Using LRFD, determine the load P that the plates can carry against tensile yielding in the gross section and the tensile rupture in the net section. Use A-36 steel. PL 5x200mm PL 5x200mm Pu PL 10x200mm Pu
Please use NSCP 2015.
A butt joint is bolted using A325 bolts with a diameter of 22mm, with threads excluded from shear plane. Allowable shear stress FT = 207 MPa. Use A36 steel with yield strength Fy = 248 MPa and a minimum tensile strength Fu = 400 MPa. Assume diameter of bolt hole to be 25 mm. Compute the block shear capacity of the butt joint. (in kN) 22mm A325 balt 12.5mm x 300 T/2 22mm x 300 mm 50 Ti0o T2 l001 100 100
Please solve
Determine the design strength of an UNP300 with four lines if 20 mm diameter bolts in standard holes, as shown in the Figure below. 1= 20 mm 60 60 60 60 60 60, 60, 60, 60,60 UNP 300 F, = 370MPA F = 240MPa o o оо o o o o