Situation 8. A sample of dry soil was shaken through a nest of sieves and thefollowing results were obtained.Mass Retained(grams)15.80SieveDiameter_(mm)4.7502.360No.485.102.0000.8501013.0054.8020400.42571.0031.400.2500.1800.15060804.901002.302000.0756.70Pan1.80Grain Size Curve100908070605040n.3020100,0010.010.1110Particle Size, mm21. Which of the following most nearly gives the effective size of the sample?a. 0.22 mmb. 0.27 mmc. 0.34 mmd. 0.39 mm22. Which of the following most nearly gives the uniformity coefficient of thesample?a. 4.07b. 3.78c. 4.38d. 3.4423. Which of the following most nearly gives the coefficient of concavity of thesample?a. 0.96b. 0.81с. 1.16d. 1.05Percent Passing. %

ASKED: To determine - effective size uniformity coefficient coefficient of concavity Given,…

Situation 8. A sample of dry soil was shaken through a nest of sieves and the following results were obtained. Sieve Mass Retained (grams) 15.80 Diameter (mm) 4.750 2.360 No. 4 8 10 5.10 2.000 13.00 20 0.850 54.80 40 0.425 71.00 60 0.250 0.180 0.150 31.40 80 4.90 2.30 100 200 Pan 0.075 6.70 1.80 Grain Size Curve 100 90 80 70 60 50 40 30 20 10 0.001 0.01 0.1 10 Particle Size, mm 21. Which of the following most nearly gives the effective size of the sample? c. 0.34 mm d. 0.39 mm a. 0.22 mm b. 0.27 mm 22. Which of the following most nearly gives the uniformity coefficient of the sample? a. 4.07 b. 3.78 c. 4.38 d. 3.44 23. Which of the following most nearly gives the coefficient of concavity of the sample? a. 0.96 b. 0.81 с. 1.16 d. 1.05 Percent Passing. %

Situation 8. A sample of dry soil was shaken through a nest of sieves and the following results were obtained. Sieve Mass Retained (grams) 15.80 Diameter (mm) 4.750 2.360 No. 4 8 10 5.10 2.000 13.00 20 0.850 54.80 40 0.425 71.00 60 0.250 0.180 0.150 31.40 80 4.90 2.30 100 200 Pan 0.075 6.70 1.80 Grain Size Curve 100 90 80 70 60 50 40 30 20 10 0.001 0.01 0.1 10 Particle Size, mm 21. Which of the following most nearly gives the effective size of the sample? c. 0.34 mm d. 0.39 mm a. 0.22 mm b. 0.27 mm 22. Which of the following most nearly gives the uniformity coefficient of the sample? a. 4.07 b. 3.78 c. 4.38 d. 3.44 23. Which of the following most nearly gives the coefficient of concavity of the sample? a. 0.96 b. 0.81 с. 1.16 d. 1.05 Percent Passing. %

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Problem A: For questions 1 to 7. In the given results of the sieve analysis of a soil. Calculate the following; U.S. Opening Mass Sieve (mm) Retained, grams 4 4.75 10 2.00 21.6 20 0.850 49.50 40 0.425 102.60 60 0.250 89.10 100 0.150 95.60 200 0.075 60.4 Pan 31.2 Sum 1) For the problem above the most probable value for D10=. a) 0.15 mm 2) For D30 =_ a) 0.17 mm 3) For Dso = ? a) 0.27 mm 4) The Uniformity coefficient will be ? a) 4.56 5) The Coefficient of Gradation is? a) 0.90 6) The particle size distribution curve is what type? a) Gap-graded 7) Using the AASHTO system what is the percentage of sand? a) 6.90 b) 0.25 mm c) 0.67 mm d) 0.09 mm b) 0.27 mm c) 0.185 mm d) 0.03 mm b) 0.41mm c) 1.05 mm d) 0.21 mm b) 4.78 c) 3.98 d) 4.21 b) 0.93 c) 0.96 d) 1.15 b) Poorly Graded c) Well-graded b) 4.88 c) 72.90 d) 88.30
Given below is the result of a sieve analysis done on a soil sample. Sieve No. Diameter Percent Passing % 4 4.750 95 10 2.000 88 20 0.850 70 40 0.425 50 60 0.250 21 100 0.150 13 200 0.075 5 Pan --- 0 Determine the value of the coefficient of uniformity. Round off to three decimal places.
Q.2) Answer the following question. 1- The sieve analysis below was done for which type Weight of sample = 2000gm Sieve size in. (mm) 3/8" 9.5 mm No.4 4.75 mm No.8 2.36 mm No.16 1.18 mm No.30 0.6 mm No.50 0.3 mm No.100 0.15 mm Pan Percent Weight retained (g) retained 0 2000*100 94 →0 Klcc→ -2000 4032000X100 358-2009 08 72 2212000x100 Percent cumulative @ 4.7 20 i 75 982 57 360 72000 Alco isies 39 492-20000 24.614 · 100 > 95 3 of aggregate. Percent passing 0 5 25 уз 61 86 97 317 ASTM Limit 100 95_100 80_100 40 85 25_60 10_30 2_10
SG is 2.66 and temperature is 18 degrees celcius
From the picture below, please identify if it is well graded, gap graded or poorly graded. Please explain. Thank you.
2. For the given data, shows a sieve analysis of soil samples A,B, and C. Diameter Soil A Soil B Soil C Sieve No. (mm) %Passing %Passing %Passing # 4 4.760 90 100 100 a. Classify soil sample A using USCS Method b. Classify soil sample B using USCS Method c. Classify soil sample C using # 8 2.380 64 90 100 #10 2.000 54 77 98 #20 0.840 34 59 92 # 40 0.420 22 51 84 #60 0.250 17 42 79 USCS Method #100 0.149 9. 35 70 #200 0.074 4 33 63 LL 46 47 PL 29 24
A sieve analysis is performed for a soil sample. The data are tabulated as shown. Solve Cu
Given below is the result of a sieve analysis done on a soil sample. Sieve No. Diameter Percent Passing % 4 4.750 96 10 2.000 81 20 0.850 72 40 0.425 50 60 0.250 27 100 0.150 14 200 0.075 5 Pan --- 0 Determine the value of the coefficient of gradation/curvature.
Given below is the result of a sieve analysis done on a soil sample. Percent Passing % 96 83 67 46 Sieve No. 4 10 20 40 60 100 200 Pan Diameter 4.750 2.000 0.850 0.425 0.250 0.150 0.075 26 13 8 0 Determine the value of the coefficient of uniformity.
Given below is the result of a sieve analysis done on a soil sample. Sieve No. Diameter Percent Passing % 4 4.750 95 10 2.000 83 20 0.850 69 40 0.425 50 60 0.250 27 100 0.150 13 200 0.075 7 Pan --- 0 Determine the value of the coefficient of uniformity. ROUND OFF TO THREE DECIMAL PLACES. USE STORED VALUES.
The given data sohws a sieve analysis of a soild sample. Classify the soild using AASHTO Method. Sieve No. Diameter (mm) Percent Passing No. 4 4.760 96 No. 8 2.380 80 No. 10 2.000 78 No.20 0.840 61 No.40 0.420 56 No. 60 0.250 48 No. 100 0.150 39 No. 200 0.075 33 Characteristics of No. 40 Fraction LL 38 PL 29
Given below is the result of a sieve analysis done on a soil sample. Sieve No. Diameter Percent Passing % 4 4.750 97 10 2.000 82 20 0.850 71 40 0.425 42 60 0.250 27 100 0.150 13 200 0.075 8 Pan --- 0 Determine the value of the coefficient of gradation/curvature. Round off to three decimal places.