EAMMANTESİMSKŪ-LMSHydrometer and sieve analysis were conducted on a soil sample.amadıFind D10, D60, uniformity coefficient (Cu), coefficient of curvature (CC) considering the chart given below.erindenHint: Cu=D60/D1o and CC=(D30)2 / (D10XD60)miş100908070605040302010SILTSANDGRAVEL1000,001 CLAY0,1100,01DANE ÇAPI / PARTICLE SIZE (mm)D20: (in mm)SeςSeç.Cu14.280.1Deo: (in mm)5.140.007CCConsolidation test results are provided below, (Hint: C, or Ce = Ae/log(of/ai') ):nmadizerindennmişAR21lenovGEÇEN DANE YÜZZDESİ / PERCENT FINER THAN D

Answered: Image /qna-images/answer/7faff084-83d5-4a71-8da9-e78527b050a6.jpg

LEXAM MAN TESİ MSKŪ-LMS Hydrometer and sieve analysis were conducted on a soil sample. amadı Find D10, D60, uniformity coefficient (Cu), coefficient of curvature (CC) considering the chart given below. erinden Hint: Cu=D60/D1o and CC=(D30)2 / (D10XD60) miş 100 90 80 70 60 50 40 30 20 10 GRAVEL 100 SILT 0.1 SAND 10 0,001 CLAY 0,01 DANE ÇAPI / PARTICLE SIZE (mm) D10: (in mm) Seς Seç. Cu 14.28 0.1 Deo: (in mm) 5.14 0.007 CC Jeç Consolidation test results are provided below, (Hint: C, or Ce = Ae/log(of/ai') ): nmadi zerinden nmiş AR 21 lenov GEÇEN DANE YÜZZDESİ /PERCENT FINER THAN D

LEXAM MAN TESİ MSKŪ-LMS Hydrometer and sieve analysis were conducted on a soil sample. amadı Find D10, D60, uniformity coefficient (Cu), coefficient of curvature (CC) considering the chart given below. erinden Hint: Cu=D60/D1o and CC=(D30)2 / (D10XD60) miş 100 90 80 70 60 50 40 30 20 10 GRAVEL 100 SILT 0.1 SAND 10 0,001 CLAY 0,01 DANE ÇAPI / PARTICLE SIZE (mm) D10: (in mm) Seς Seç. Cu 14.28 0.1 Deo: (in mm) 5.14 0.007 CC Jeç Consolidation test results are provided below, (Hint: C, or Ce = Ae/log(of/ai') ): nmadi zerinden nmiş AR 21 lenov GEÇEN DANE YÜZZDESİ /PERCENT FINER THAN D

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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SHOW COMPLETE SOLUTION PLS VALUES: A= 5B = 5C = 1Y = 25
A sample of a dry coarse grained material of 500 grams was shaken through a nest of sieves and the following results are obtained: 20 | 200 40 0.425 Sieve No. 10 2.00 4 60 100 Pan Opening (mm) % Passing 4.75 0.85 0.25 0.15 0.075 -- 94 60 30 10 7 5 3 31. Determine the uniformity coefficient. b. 4.424 32. Determine the coefficient of curvature. a. 4.706 C. 1.250 d. 0.85 а. 4.706 b. 4.424 C. 1.250 d. 0.85 33. Given that the soil is non-plastic, classify the soil by using the Unified Soil Classification System. a. GW b. GP C. Sw d. SP
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