Simplify the following expression using Karnaugh map and implement. Draw simplified logic diagram as well. Implement on Multisim software. (a) Y=A.B.C'.D+A.B'.C'.D+A'.B'.C'.D+A'.B.C'.D+A'.B'.C'.D'+A'.B.C'.D'+A'.B.C.D'+A'.B.C.D+A'.B'.C.D
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Simplify the following expression using Karnaugh map and implement. Draw simplified logic diagram as well. Implement on Multisim software.
(a)
Y=A.B.C'.D+A.B'.C'.D+A'.B'.C'.D+A'.B.C'.D+A'.B'.C'.D'+A'.B.C'.D'+A'.B.C.D'+A'.B.C.D+A'.B'.C.D
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- ii) For the circuit shown in Figure B9, a. Find logic functions for Y and Z. b. Simplify function Z using Boolean algebra. Y Figure B9 ABQ5: Determine the output boolean expression for logic circuit as shown in figure below. x- y- D z-Q1/ Draw the logic circuit after simplify the circuit show below using K. map: A Y. C- Add filo B.
- Design the following combinational logic circuit with a four-bit input and a three-bit output. The input represents two unsigned 2-bit numbers: A1 A0 and B1 B0. The output C2 C1.C0 is the result of the integer binary division A1 A0/B1 B0 rounded down to three bits. The 3-bit output has a 2-bit unsigned whole part C2 C1 and a fraction part CO. The weight of the fraction bit CO is 21. Note the quotient should be rounded down, i.e. the division 01/11 should give the outputs 00.0 (1/3 rounded down to 0) not 00.1 (1/3 rounded up to 0.5). A result of infinity should be represented as 11.1. A minimal logic implementation is not required. (Hint: start by producing a truth table of your design).A three input logic functipn will provide a logic high output only when twp (and two only) of the inputs are logic highs. For all other input possibilities, a logic zero is provided on the output. What is the logic expression? A. Y=A'B'C+A'BC'+AB'C' B. Y=AB'C+A'BC+ABC' C. Y=AB'C+ABC+A'B'C' D. Y=ABC'+AB'C+A'B'C'answere fast please question from DIGITAL LOGIC DESIGN TOPIC : Designing Combinational Logic You are designing a water level circuit using 74ALS151 (8 to 1 Multiplexer IC)* When input is 0000 that means tank is empty.* When input is 1111 that means tank is full.* When input is below 5, that means water level is low.* So, make a circuit using 74ALS151 Multiplexer IC that shows a "low water" indicator light(by setting an output L to 1) when the water level drops below level 5.
- Draw logic diagram for half adder and full adder circuit using Logisim SoftwareH.W :- 1) A four logic-signal A,B,C,D are being used to represent a 4-bit binary number with A as the LSB and D as the MSB. The binary inputs are fed to a logic circuit that produces a logic 1 (HIGH) output only when the binary number is greater than 01102-610. Design this circuit. 2) repeat problem 1 for the output will be 0 (LOW) when the binary input is less than 01112-710- Saleem LateefDesign a logic circuit for decoder that accepts 3-bit input and displays alphabet “048” at the seven- segment as illustrated at Figure 1 (a). The input-output mapping shown in Table 1 (a). Refer Figure 1(b) and Figure 1(c) for seven-segment display format showing arrangements of segments using common anode connection. Show each steps clearly to produce the expressions and required design. [Rekabentuk litar logik untuk penyahkod yang menerima input 3-bit dan paparkan abjad "048" di tujuh-segmen seperti digambarkan pada Rajah 1(a). Pemetaan masukan-keluaran ditunjukkan dalam Jadual 1(a). Rujuk Rajah 1(b) and Rajah 1(c) untuk format paparan tujuh-segmen yang menunjukkan susunan segmen menngunakan sambungan 'common anode'. Tunjukkan setiap langkah dengan jelas untuk menghasilkan ungkapan dan reka bentuk yang dikehendaki.] Xs X6 X7 DECODER Figure 1(a) [Rajah 1(a)] a b с d e f g a 80123456789 Figure 1(c) [Rajah 1(c)] g Figure 1 (b) [Rajah 1(b)] b с DP
- Design a combinational circuit with 3-inputs and 1-output. The output is equal to logic-1 when the binary value of the input is less than 3. And the output is logic-0 otherwise.Basic Combinational Logic Circuits 2. Write the output expression for logic circuit: A B B XUSE DIGITAL LOGIC AND DESIGN Part 1: In Figure_4; we have 4-bit Comparator using 2-bit Comparators block. You have to satisfy given condition by applying all data on figure 4. At the end, given condition should produce HIGH output and other two should be LOW. A3 A2 A1 A0 = 1101 and B3 B2 B1 B0 = 1110 Figure_4 Part 2: The serial data-input waveform (Data in) and data-select inputs (S0 and S1) are shown in Figure_5. Determine the data-output waveforms from D0 through D3. Figure_5 Part 3: Decoder can be useful when we have to decode some specific numbers from their equivalent code. Figure 6 has a concept of 3 to 8 line decoder from which you have to generate output waveform from D0 to D7 with proper relationship to input. Figure_6 Part 4: The data-input and…