Show how the following values would be stored by byte-addressable machines with 32-bit words, using little endian and then big endian format. Assume that each value starts at address 1016. Draw a diagram of memory for each, placing the appropriate values in the correct (and labeled) memory locations. a) 0×456789A1 b) OX0000058A c) Ox14148888

Show how the following values would be stored by byte-addressable machines with 32-bit words, using little endian and then big endian format. Assume that each value starts at address 1016. Draw a diagram of memory for each, placing the appropriate values in the correct (and labeled) memory locations. a) 0×456789A1 b) OX0000058A c) Ox14148888

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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The memory location at address of 0X003FB01 contains 1-byte memory variable J (0010_0001), and the memory location at the address of 0X003FB02 contains 1-byte memory variable K (0001 0010), see figure below. There is a 2-byte variable M which hold binary information M (1110 0101 0000 1i11). What is the address in hexadecimal format for 2-byte memory variable M, following little Endian computer? 7 Address in Data in Hex. Format Hex. Format 0X003FBF04 1110 0101 M OX003FBF03 0000 1111 0X003FBF02 0001 0010 0X003FBF01 0010 0001 J Its address in hexadecimal is 0X003FBF02. а. Its address in hexadecimal is 0×003FBF03. O b. Its address in hexadecimal is 0X003FBF04. Its address in hexadecimal is 0×003FBF01. d.
Show how the following values would be stored by byte addressable machines with 32- bit words, using the little endian and then big endian. Assume each value starts at address 10 base 16. Draw a diagram of memory for each, placing the appropriate values in the correct (and labeled) memory locations. a. 456789A116 b. 0000058A16
Consider the following table that represents part of the memory of a 16-bit address space that has an addressability of 2 bytes (like LC-3): ADDRESS OxFFFF OXOCOE OXOCOD Ox0C0C OXOCOB OXOCOA 0x0C09 0x0000 CONTENTS 1111 1111 1111 1111 1111 1110 1101 1100 0001 1011 1100 0101 0110 0101 1000 0111 1100 0000 0100 0000 0011 0001 0101 0010 0000 1100 0000 1101 0000 0000 0000 0000 The table above shows the addresses in hex (base 16) and the contents at the corresponding address in binary (base 2). A.) What are the contents in hex of the memory location at following address in binary: 0000 1100 0000 1110? (Enter hex like the following example: Ox2A3F)
QUESTION 9 What is the hexadecimal representation of the memory variable location at address 003FBA03H in the Little Endian format from the 32-bit binary quantity represented by 10100111 110111100101101100001100b? Address in hexadecimal format 003FBA00H 003FBA01H 003FBA02H 003FBA03H 003FBA04H Data in hexadecimal format O a. The hexadecimal representation for the variable located at memory address 003FBA03 is A8. Ob. The hexadecimal representation for the variable located at memory address 003FBA03 is A5. OC. The hexadecimal representation for the variable located at memory address 003FBA03 is A3. Od. The hexadecimal representation for the variable located at memory address 003FBA03 is A7.
Show how the decimal value 2019111310 would be stored by byte-addressable machines with 32-bit words, using little endian format and then big endian format. Assume the value starts at address 201916. Draw a diagram of memory and place the appropriate values in the correct (and labeled) memory locations.
Consider a memory implemented for 8086 microprocessor Draw the memory block diagram. Determine the values for A0 , /BHE ,address lines(A1..A19) and data lines(D0.. D15) in order to access: A byte at odd address [01FF3H] A byte at even address [01FFCH] A word at even address [01FFEH] A word at odd address [01ABFH]
Show how the value Oxabcdef12 would be arranged in memory of a little-endian machine. Place commas between each byte of hexadecimal data, and begin with the byte at the lowest address with addresses going up as you add bytes to the right. The word size is 4 bytes. O 12, ef, cd, ab O 21, fe, dc, ba O ab, cd, ef, 12 O ba, dc, fe, 21
Memory address Data According to the memory view given below, if RO = Ox20008002 then LDRSB r1, [r0, #-4] is executed as a result of r1 = ?(data overlay big endian)? Øx20008002 ØXA1 Øx20008001 ØXB2 Øx20008000 Øx73 ØX20007FFE ØXD4 ØX20007FFE Lütfen birini seçin: O A. R1 = 0X7F O B. R1 = Oxffffffd4 O C. R1 = Oxffffff7F O D. R1=0XD4000000 O E. R1 = 0XD4
1. Show how the following values would be stored bybyte-addressable machines with 32- bit words, using little endianand then big endian format. Assume each value starts at address301816. Draw a diagram of memory for each, placing the appropriatevalues in the correct (and labeled) memory locations. a. 56789ABC16 b. 2014111910 2. The memory unit of a computer has256K words of 32 bits each. The computer has an instruction formatwith 4 fields: an opcode field; a mode field to specify 1 of 7addressing modes; a register address field to specify one of 16registers; and a memory address field. Assume an instruction is 32bits long. Answer the following: a. How large must the mode field be? b. How large must the register field be? c. How large must theaddress field be? d. How large is the opcode field? 4. (bonus question, 5 points) In a computerinstruction format, the instruction length is 12 bits and the sizeof an address field is 4 bits. Is it possible to have: 13 2-address instructions 45…
Suppose r0 = ox300010A0, r2 = 0x00000011, and the memory layout is as follows Address: Data: 0x300010A7 0x72 0x300010A6 0XA5 0x300010A5 0x9F 0x300010A4 0x00 0x300010A3 0x50 0x300010A2 0x2B 0x300010A1 0XA5 0x300010A0 0x01 -What is the Value of r0 and r1 after executing LDR r1, [r0, #2] -What are the values of r0 and r1 after executing the following code? Illustrate your process in a memory map. LDR r1, [r0], #3 ADD r1, r1, r2 STR r1, [r0, r#4]
Suppose r0 = ox300010A0, r2 = 0x00000011, and the memory layout is as follows Address: Data: 0x300010A7 0x72 0x300010A6 0XA5 0x300010A5 0x9F 0x300010A4 0x00 0x300010A3 0x50 0x300010A2 0x2B 0x300010A1 0XA5 0x300010A0 0x01 -What are the values of r0 and r1 after executing the following code? Illustrate your process in a memory map. LDR r1, [r0], #3 ADD r1, r1, r2 STR r1, [r0, r#4]
Show how the following values would be stored by machines with 32-bit words, using little endian and then big endian format. Assume each value starts at address 1016. Draw a diagram of memory for each, placing the appropriate values in the correct (and labeled) memory locations. 1234567816 ABCDEF1216 8765432116