Shelly and Kelly Macdonald met up with Sarah and Tara MacNeill to go fishing in Cape Breton. They found two pools in a stream containing speckled trout (assume equal variance), with the Macdonalds at one pool and the MacNeills at the other, and at the end of the day each team had caught (and released unharmed) 5 fish. For each fish they recorded the length and weight, and the data on length (in cm) is summarized below (Give the answers to 2 places past decimal) Team Macdonald MacNeill Mean 18.1 20.43 a.) To test whether or not the fish have the same mean size in the two pools, the null hypothesis will be: Incorrect H0: & 1-X 2 = -2.33 Incorrect H0: p1-µ2 = -2.33 Incorrect H0: & 1-8 2 = 0 Correct: H0: p1-p2 Computer's answer now shown above. Incorrect. Tries 1/1 Previous Tries b.) The alternative hypothesis for this test will be: Ha: & 1-8 2# -2.33 Ha: u1-u2 -2.33 Ha: X 1-8 2 #0 Ha: p1-µ2 0 Submit Answer Tries 0/1 c.) What is the pooled estimate of the variance? Submit Answer Tries 0/5 d.) Compute the value of the test statistic. [ Submit Answer Tries 0/5 Std.Dev 1.8 2.2 Find bounds on the P value for the test. P < .001 .01 < P < .05 .05 < P < .1 P>.1 Submit Answer Tries 0/2 f) Is there statistically significant evidence against HO at a = 0.05? Yes No Not enough information to decide Submit Answer Tries 0/1

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Shelly and Kelly Macdonald met up with Sarah and Tara MacNeill to go fishing in Cape Breton. They found two
pools in a stream containing speckled trout (assume equal variance), with the Macdonalds at one pool and the
MacNeills at the other, and at the end of the day each team had caught (and released unharmed) 5 fish. For
each fish they recorded the length and weight, and the data on length (in cm) is summarized below (Give the
answers to 2 places past decimal)
Team
Macdonald
MacNeill
Mean
18.1
20.43
Incorrect H0: p1-µ2 = -2.33
Incorrect H0: & 1-8 2 = 0
Correct: HO: p1-p2 = 0
a.) To test whether or not the fish have the same mean size in the two pools, the null hypothesis will be:
Incorrect H0: & 1-8 2 = -2.33
Std.Dev
1.8
2.2
Computer's answer now shown above. Incorrect. Tries 1/1 Previous Tries
b.) The alternative hypothesis for this test will be:
Ha: & 1-X 2 # -2.33
Ha: p1-p2 -2.33
Ha: & 1-8 2 # 0
Ha: p1-µ2 0
Submit Answer Tries 0/1
c.) What is the pooled estimate of the variance?
Submit Answer Tries 0/5
d.) Compute the value of the test statistic.
Submit Answer Tries 0/5
e.) Find bounds on the P value for the test.
P < .001
.01 < P < .05
.05 < P < .1
P>.1
Submit Answer Tries 0/2
f) Is there statistically significant evidence against HO at a = 0.05 ?
Yes
No
Not enough information to decide
Submit Answer Tries 0/1
g.) Calculate the 95% confidence interval for the difference in mean length
Lower:
Upper:
Submit Answer Tries 0/5
Transcribed Image Text:Shelly and Kelly Macdonald met up with Sarah and Tara MacNeill to go fishing in Cape Breton. They found two pools in a stream containing speckled trout (assume equal variance), with the Macdonalds at one pool and the MacNeills at the other, and at the end of the day each team had caught (and released unharmed) 5 fish. For each fish they recorded the length and weight, and the data on length (in cm) is summarized below (Give the answers to 2 places past decimal) Team Macdonald MacNeill Mean 18.1 20.43 Incorrect H0: p1-µ2 = -2.33 Incorrect H0: & 1-8 2 = 0 Correct: HO: p1-p2 = 0 a.) To test whether or not the fish have the same mean size in the two pools, the null hypothesis will be: Incorrect H0: & 1-8 2 = -2.33 Std.Dev 1.8 2.2 Computer's answer now shown above. Incorrect. Tries 1/1 Previous Tries b.) The alternative hypothesis for this test will be: Ha: & 1-X 2 # -2.33 Ha: p1-p2 -2.33 Ha: & 1-8 2 # 0 Ha: p1-µ2 0 Submit Answer Tries 0/1 c.) What is the pooled estimate of the variance? Submit Answer Tries 0/5 d.) Compute the value of the test statistic. Submit Answer Tries 0/5 e.) Find bounds on the P value for the test. P < .001 .01 < P < .05 .05 < P < .1 P>.1 Submit Answer Tries 0/2 f) Is there statistically significant evidence against HO at a = 0.05 ? Yes No Not enough information to decide Submit Answer Tries 0/1 g.) Calculate the 95% confidence interval for the difference in mean length Lower: Upper: Submit Answer Tries 0/5
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