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sembly consisting of two inclined bars, as shown in the figure.  The cross-sectional area of bar (1) is 1.30 in.2, and the cross-section

sembly consisting of two inclined bars, as shown in the figure.  The cross-sectional area of bar (1) is 1.30 in.2, and the cross-section

Mechanics of Materials (MindTap Course List)
Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter2: Axially Loaded Members
Section: Chapter Questions
Problem 2.3.2P: A long, rectangular copper bar under a tensile load P hangs from a pin that is supported by two...
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A horizontal load P is applied to an assembly consisting of two inclined bars, as shown in the figure.  The cross-sectional area of bar (1) is 1.30 in.2, and the cross-sectional area of bar (2) is 1.75 in.2.  The normal stress in either bar may not exceed 24 ksi.  Determine the maximum load P that may be applied to this assembly.  Assume dimensions of a=14.5 ft, b=9.0 ft, and c=14.5 ft. 

Find the ratio, (F1/F2), where F1 is the force in member (1) and F2 is the force in member (2).  Both bars are in tension, so these forces are both positive according to the sign conventions.

A horizontal load P is applied to an assembly consisting of two inclined bars, as shown in the figure. The cross-sectional area of bar (1) is 1.30 in.?, and the cross-sectional area of bar (2) is 1.75 in.?. The normal stress in either bar may not exceed 24 ksi. Determine the maximum load P that may be applied to this assembly. Assume dimensions of a = 14.5 ft, b = 9.0 ft, and c = 14.5 ft. (1) a B P b (2)
Transcribed Image Text:A horizontal load P is applied to an assembly consisting of two inclined bars, as shown in the figure. The cross-sectional area of bar (1) is 1.30 in.?, and the cross-sectional area of bar (2) is 1.75 in.?. The normal stress in either bar may not exceed 24 ksi. Determine the maximum load P that may be applied to this assembly. Assume dimensions of a = 14.5 ft, b = 9.0 ft, and c = 14.5 ft. (1) a B P b (2)
Find the ratio, (F1 IF2), where F1 is the force in member (1) and F2 is the force in member (2). Both bars are in tension, so these forces are both positive according to the sign conventions. F1/F2 = i
Transcribed Image Text:Find the ratio, (F1 IF2), where F1 is the force in member (1) and F2 is the force in member (2). Both bars are in tension, so these forces are both positive according to the sign conventions. F1/F2 = i
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