Select all the strings that are elements of the following set: {a,b}² µ{a,b}³ µ{a,b}ª (b) (ba) (bbbba) (abbba) (abaaa) (bbabb) ☐ (bbbab) ☐ (a)
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- Contact list: Binary Search A contact list is a place where you can store a specific contact with other associated information such as a phone number, email address, birthday, etc. Write a program that first takes as input an integer N that represents the number of word pairs in the list to follow. Word pairs consist of a name and a phone number (both strings). That list is followed by a name, and your program should output the phone number associated with that name. Define and call the following function. The return value of FindContact is the index of the contact with the provided contact name. If the name is not found, the function should return -1 This function should use binary search. Modify the algorithm to output the count of how many comparisons using == with the contactName were performed during the search, before it returns the index (or -1). int FindContact(ContactInfo contacts[], int size, string contactName) Ex: If the input is: 3 Frank 867-5309 Joe 123-5432 Linda…Arithmetic progression def arithmetic_progression(items): An arithmetic progression is a numerical sequence so that the stride between each two consecutive elements is constant throughout the sequence. For example, [4, 8, 12, 16, 20] is an arithmetic progression of length 5, starting from the value 4 with a stride of 4. Given a non-empty list items of positive integers in strictly ascending order, find and return the longest arithmetic progression whose all values exist somewhere in that sequence. Return the answer as a tuple (start, stride, n) of the values that define the progression. To ensure unique results to facilitate automated testing, if there exist several progressions of the same length, this function should return the one with the lowest start. If several progressions of equal length emanate from the lowest start, return the progression with the smallest stride. items expected results [42] (42, 0, 1) [2, 4, 6, 7, 8, 12, 17] (2, 2, 4) [1, 2, 36, 49, 50, 70, 75, 98,…Dictionary Walk Program Using Java, write a program which takes two words as inputs and walks through the dictionary and creates a list of words between them. Two words are “adjacent” if you can change one word into the other by adding, deleting, or changing a single letter. A “word list” is an ordered list of unique words where successive words are adjacent. Use the official Scrabble word list as your dictionary of valid words. Examples: hate → love: hate, have, hove, love dogs → wolves: dogs, does, doles, soles, solves, wolves man → woman: man, ran, roan, roman, woman flour → flower: flour, lour, dour, doer, dower, lower, flower Questions What is the shortest list between “crawl” and “run”? What is the shortest list between “mouse” and “elephant”? Does your program necessarily return the shortest list? What assumptions did you make in your program? How did you test your program? What is the Big-O complexity of your program? Additional Questions, answer three Suppose…
- def strPattern(mystr):lenght = len(mystr)mystr1 = ""for i in range(lenght - 1):mystr1 = mystr1 + mystr[i].upper() + str(i + 1)if lenght == 0:return mystr1return mystr1 + mystr[-1].upper()s = input("enter a word: ")print(strPattern(s)) s = input("enter a word: ") EOFError: EOF when reading a line HOW CAN I FIX THIS QUESTION?Count dominators def count_dominators(items): An element of items is said to be a dominator if every element to its right (not just the one element that is immediately to its right) is strictly smaller than it. By this definition, the last item of the list is automatically a dominator. This function should count how many elements in items are dominators, and return that count. For example, dominators of [42, 7, 12, 9, 13, 5] would be the elements 42, 13 and 5. Before starting to write code for this function, you should consult the parable of "Shlemiel the painter" and think how this seemingly silly tale from a simpler time relates to today's computational problems performed on lists, strings and other sequences. This problem will be the first of many that you will encounter during and after this course to illustrate the important principle of using only one loop to achieve in a tiny fraction of time the same end result that Shlemiel achieves with two nested loops. Your workload…void funi (int iist , int s) { int sum=0; for (int i = 0; iTAKE A LIST OF STRING FROM THE USER AND COUNT THE NUMBER OF UNIQUE ELEMENTS WITHOUT USING THE FOR, WHILE, Do-WHILE LOOPS. PREFERRED PROGRAMMING LANGUAGE: JAVA/C++# Initialize sets A and BA = { 'a', 'b', 'c', 'd', 'e', 'f' }B = { 'c', 'd', 'f', 'h', 'j', 'k' } print('A = ', sorted(A))print('B = ',sorted(B))print(' ') AsymdiffB = set()# put your code here to compute the symmetric difference of A and B# first add all the elements that are in A but not B# then add all the elements that are in B but not A print('Symmetric Difference of A and B = ', sorted(AsymdiffB))# define stemmer functionstemmer = SnowballStemmer('english') # tokenise datatokeniser = TreebankWordTokenizer()tokens = tokeniser.tokenize(data) # define lemmatiserlemmatizer = WordNetLemmatizer() # bag of wordsdef bag_of_words_count(words, word_dict={}): """ this function takes in a list of words and returns a dictionary with each word as a key, and the value represents the number of times that word appeared""" for word in words: if word in word_dict.keys(): word_dict[word] += 1 else: word_dict[word] = 1 return word_dict # remove stopwordstokens_less_stopwords = [word for word in tokens if word not in stopwords.words('english')] # create bag of wordsbag_of_words = bag_of_words_count(tokens_less_stopwords) Use the stemmer and lemmatizer functions (defined in the cells above) from the relevant library to find the stem and lemma of the nth word in the token list. Function Specifications: Should take a list as input and…def q5(sentence): Assumes sentence is a string. Returns a list of all the words in sentence, where a word is a token separated by white space, (you can use sentence.split()), and then for each word, make it lowercase and remove any character that is not alpha-numeric (a-z or 8-9). For example, I q5("The Plague" (French: "La Peste"), 1947, by Albert CamUs.') should return ['the', 'plague', 'french', 'la', 'peste', '1947', 'by', 'albert', 'camus'] q5('Red@Dragon....ca is great!') should return ['reddragonca', 'is', 'great'] passSaal lai The elements of the set {x: x is an integer such that x2 - 3 = 0} is { v3, v-3 } Ture O False O(a,b} u {} = {a,b} True False The order of the elements in a set is important True False The empty set is a subset of every other set True FalseSEE MORE QUESTIONS