roblem 3: Diameters of small commercially available steel rods vary by sixteenths of an inch. Select the required ommercial size of the rod required to support a tensile load of 35,000 lb if the tensile stress cannot exceed 20,000 psi.
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- The data in Table 1.5.3 were obtained from a tensile test of a metal specimen with a rectangular cross section of 0.2011in.2 in area and a gage length (the length over which the elongation is measured) of 2.000 inches. The specimen was not loaded to failure. a. Generate a table of stress and strain values. b. Plot these values and draw a best-fit line to obtain a stress-strain curve. c. Determine the modulus of elasticity from the slope of the linear portion of the curve. d. Estimate the value of the proportional limit. e. Use the 0.2 offset method to determine the yield stress.A steel rod with length equal to 7.5 ft, has a diameter of 0.78 inches in quarter of its length and a diameter of 0.38 inches the rest. If it is subjected to a tensile load of 6,000 lbs, what will be the tótal deformation of the bar if it has a modulus of elasticity E= 28.5 x 10^6 psi. %3D O 0.1378 inches O 0.1338 inches O 0.1352 inches O 0.1364 inches O 0.1423 inchesAn alloy steel having a diameter of 0.45 in. extends 0.002 in. over a gage length of 2.2 in. due to a tensile load of 3900 lb. What is the modulus of elasticity of this alloy steel? A)29,010 ksi B)27,000 ksi C)30,000 ksi D)28,000 ksi
- Three steel bars have a diameter of 25 mm and carbon contents of 0.2, 0.5, and 0.8%, respectively. The specimens were subjected to tension until rupture. The load versus deformation results were as shown in Table P3.19. If the gauge length is 50 mm, determine the following: a. The tensile stresses and strains for each specimen at each load increment. b. Plot stresses versus strains for all specimens on one graph. TABLE P3.19 Specimen No. Carbon Content (%) 1 3 0.2 0.5 0.8 Deformation (mm) Load (kN) 0.00 0.07 133 133 133 0.10 137 191 191 0.15 142 196 285 0.50 147 201 324 1.00 140 199 383 2.50 155 236 447 5.00 196 295 491 (Rupture) 7.50 226 336 10.00 241 341 12.50 218 304 (Rupture) 13.75 196 (Rupture) c. The proportional limit for each specimen. d. The 0.2% offset yield strength for each specimen. e. The modulus of elasticity for each specimen. f. The strain at rupture for each specimen. g. Comment on the effect of increasing the carbon content on the following: Yield strength ii.…Determine the maximum tensile strength of the steel bar described by the following data Initial diameter = 12 mm Final diameter = 6.5 mm Initial length = 60 cm Final length = 86 cm Ultimate load = 5000 kgfA round aluminum alloy bar with a 0.25-in. diameter and a 1-in. gauge length was tested in tension to fracture according to ASTM E-8 method. The load and deformation data were as shown in Table P4.8.Using a spreadsheet program, obtain the following: a. A plot of the stress–strain relationship. Label the axes and show units. b. A plot of the linear portion of the stress–strain relationship. Determine modulus of elasticity using the best fit approach. c. Proportional limit. d. Yield stress at an offset strain of 0.002 in/in. e. Initial tangent modulus. f. If the specimen is loaded to 3200 lb only and then unloaded, what is the permanent change in gauge length? g. When the applied load was 1239 lb, the diameter was measured as 0.249814 in. Determine Poisson’s ratio.
- 2.) Answer the following: a.) a 22 ft long solid steel rod is subjected to a load of 15,000 lb. This load causes the rod to stretch 0.435 in. The modulus of elasticity of the steel is 30,000,000 psi. Determine the diameter of the rod. b.) A solid circular titanium control rod must support an axial tension force of 12,000 lb. Assume that the modulus of elasticity of the titanium in 16,500,000 psi. If the rod must elongate no further than 0.35 in. when the normal stress of the rod is 68,000 psi, determine the minimum rod diameter AND the maximum rod length.Determine the ductility of the following steel samples that undergo tensile strength test. All dimensions in millimeter.As shown in the figure below, a bronze bar is affixed between a steel bar and an aluminum bar. Axial loads are applied at the positions indicated. If the largest value of P that will not exceed an overall deformation of 4.0 mm, or the following stresses: 150 MPa in the steel, 130 MPa in the bronze, and 90 MPa in the aluminum. Assume that the assembly is suitably braced to prevent buckling. Use Est = 200 GPa, Eal = 70 GPa, and Ebr = 83 GPa. determine the stress in the bronze, steel, and aluminum
- On the stress-strain diagram of a steel bar, show and explain the following: proportional limit, yield stress, ultimate stress, yield strain, and modulus of elasticity.A high-yield-strength alloy steel bar with a rectangular cross section that has a width of 37.5 mm, a thickness of 6.25 mm, and a gauge length of 203 mm was tested in tension to rupture, according to ASTM E-8 method. The load and deformation data were as shown in Table Using a spreadsheet program, obtain the following:a. A plot of the stress–strain relationship. Label the axes and show units.b. A plot of the linear portion of the stress–strain relationship. Determine modulus of elasticity using the best-fit approach.c. Proportional limit.d. Yield stress.e. Ultimate strength.f. If the specimen is loaded to 155 kN only and then unloaded, what is the permanent deformation?g. In designing a typical structure made of this material, would you expect the stress applied in (f) safe? Why?1. For the 15 foot copper bar shown in the figure below, find the total elongation (or shrinkage). The bar has a square cross section of 2" x 2" ( 16,000 lbs 4000 lbs 12' Punch Force 12000 lbs 2. A metal plate is 125 inch thick. What force is required to punch out a square piece 1" x 1"? The ultimate shear stress of the metal is 37,000 psi, and the ultimate tensile stress is 60,000 psi.