Rewrite the program segment 7. that follows, using a for loop and do-while loop:
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Types of Loop
Loops are the elements of programming in which a part of code is repeated a particular number of times. Loop executes the series of statements many times till the conditional statement becomes false.
Loops
Any task which is repeated more than one time is called a loop. Basically, loops can be divided into three types as while, do-while and for loop. There are so many programming languages like C, C++, JAVA, PYTHON, and many more where looping statements can be used for repetitive execution.
While Loop
Loop is a feature in the programming language. It helps us to execute a set of instructions regularly. The block of code executes until some conditions provided within that Loop are true.
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- CFG: Example 1 • Draw the CFG for the following code: int f(int n){ } int m = n* n; if (n < 0) else return 0; return m;Consider the following function: void fun_with_recursion(int x) { printf("%i\n", x); fun_with_recursion(x + 1); } What will happen when this function is called by passing it the value 0?Recursive function: Writing the recursive case. Write code to complete PrintFactorial()'s recursive case. Sample output if input is 5: 5! = 5 * 4 * 3 * 2 * 1 = 120 #include <stdio.h> void PrintFactorial(int factCounter, int factValue){int nextCounter;int nextValue; if (factCounter == 0) { // Base case: 0! = 1printf("1\n");}else if (factCounter == 1) { // Base case: Print 1 and resultprintf("%d = %d\n", factCounter, factValue);}else { // Recursive caseprintf("%d * ", factCounter);nextCounter = factCounter - 1;nextValue = nextCounter * factValue; /* Your solution goes here */ }} int main(void) {int userVal; scanf("%d", &userVal);printf("%d! = ", userVal);PrintFactorial(userVal, userVal); return 0;}
- The function ver() is defined as follows: void ver(char "pc) { char c; if( "pc == "\O' ) return; c = "pc; ++pc; ver(pc); putchar(c); Show the output when function ver() is called as follows: ver("recursion");#include #include #include int main() { int i, j; printf("Columns | JIn"); for (i = 1; i< 4; ++i) { printf("Outer %6d\n", i); for (j = 0; j< i; ++j) { printf(" Inner%10d\n", j); } } /* heading of outer for loop */ /* heading of inner loop */ %3D return (0); } Create a new code modifying it to use "while loop" instead of the "for loop"Question 1 Not complete Marked out of 1.00 Flag question Write a recursive function named count_non_digits (word) which takes a string as a parameter and returns the number of non-digits in the parameter string. The function should return 0 if the parameter string contains only digits. Note: you may not use loops of any kind. You must use recursion to solve this problem. You can assume that the parameter string is not empty. For example: Test Result print(count_non_digits ('123')) print(count_non_digits ('2rPTy5')) print(count_non_digits ('hello world')) 11 Precheck Check 0 4 Answer: (penalty regime: 0, 0, 5, 10, 15, 20, 25, 30, 35, 40, 45, 50 %) 1
- c++ PLEASE TRACE THE FUNCTION Given the code:void d(int n) { if(n<2) { cout << n << " "; return; } cout << n << " "; d(n/3);} 1. Trace the function when n is 12.Programming Assignment:Here is a loop that starts with an initial estimate of the square root of a, x, and improves it until itstops changing:while True: y = (x + a / x) / 2 if abs(y - x) < epsilon: break x = ywhere epsilon has a value like 0.0000001 that determines how close is close enough.Encapsulate this loop in a function called square_root that takes a as a parameter, chooses areasonable value of x, and returns an estimate of the square root of a.To test the square root algorithm in this chapter, you could compare it with math.sqrt. Write afunction named test_square_root that prints a table like this:1.0 1.0 1.0 0.02.0 1.41421356237 1.41421356237 2.22044604925e-163.0 1.73205080757 1.73205080757 0.04.0 2.0 2.0 0.05.0 2.2360679775 2.2360679775 0.06.0 2.44948974278 2.44948974278 0.07.0 2.64575131106 2.64575131106 0.08.0 2.82842712475 2.82842712475 4.4408920985e-169.0 3.0 3.0 0.0The first column is a number, a; the second column is the square root of a computed with the[your…#include using namespace std; bool isPalindrome(int x) { int n=0,val; val = x; while(x > 0) { n = n * 10 + x % 10; x = x / 10; } } int main() { int n; cin >>n; if(isPalindrome(n)) { cout <
- A/ find code optimization method to this code and then find type to this code 1- For(i=1;i#include using namespace std; const int y = 1; int main () { int static y = 2; int i = 3, j = 4, m = 5, n = 6; %3D int a = [] (int x, int i = 1) { return x * i; } (y, 3) ; %3D int b = [=] (int x) { return [=] (int b) { return b + j; } (x) % 7; } (a); int c = [=] (int x) mutable ->int { m = 6; return [6] (int j) mutable { y = a * b; return y / j; } (x) -m; } (b) ; cout << a << endl; cout << b << endl; cout << c << endl; cout << m << endl; cout << y < endl; return 0; This program outputs 5 lines. What are they? Please explain your work and your answer.int func(int a, int b) { return (aSEE MORE QUESTIONSRecommended textbooks for youC++ Programming: From Problem Analysis to Program…Computer ScienceISBN:9781337102087Author:D. S. MalikPublisher:Cengage Learning
C++ for Engineers and ScientistsComputer ScienceISBN:9781133187844Author:Bronson, Gary J.Publisher:Course Technology PtrC++ Programming: From Problem Analysis to Program…Computer ScienceISBN:9781337102087Author:D. S. MalikPublisher:Cengage LearningC++ for Engineers and ScientistsComputer ScienceISBN:9781133187844Author:Bronson, Gary J.Publisher:Course Technology Ptr