Read the question carefully and give me right solution according to the question. Station 10+00.00 has an elevation of 110.00 and a grade of -3%. Station 20+00.00 has an elevation of 105.00 and a grade of +2%. What is the stationing at the two grade intersections? options

Read the question carefully and give me right solution according to the question. Station 10+00.00 has an elevation of 110.00 and a grade of -3%. Station 20+00.00 has an elevation of 105.00 and a grade of +2%. What is the stationing at the two grade intersections? options

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: What would be the admissible gradient for a BG track when the grade resistance coupled with a urve…

A: Given- 4 degree curve, Ruling gradient=1 in 200,

Q: PROBLEM 6: A highway engineer must stake a symmetrical vertical curve where an entering grade of…

A: PVCELV=PVIELV-g1L2PVCelv=140.36-0.008×1202PVCelv=139.88mPVTELV=PVIELV+g2L2PVTelv=140.36-0.4×1202PVTe…

Q: A parabolic vertical curve with a grade in of 2.1%, a grade out of - 3.2%, a curve length of…

A: (Note: Since part C is asked to solve, the solution for the c part is given below.) Given: Grade in,…

Q: 3. Given a simple horizontal curve with A-8 00 00" and Pl at station 104450, calculate: a. R b. T d.…

A: a) Radius R = 1720 / D = 1720 /8 = 215 m b) T = Radius x tan…

Q: Referring to the following illustration, a -4% grade meets a +5% grade at the point of vertical…

Q: A −2.50% grade meets a +1.75% grade at station 44+25 and elevation 3388.42 ft, 400-ft curve,…

A: The elevations and grades at the beginning and end of the curve need to be determined. g1= -2.5%…

Q: An equal-tangent crest curve connects a +2.0% and a-1.0% grade. The PVC is at station + 670 and the…

A: The curve length will be: Lm=2×100station2 of PVI-station1 of PVCLm=200(1+790-1+670) =240 ft

Q: In Idaho Spring, Colorado, an existing tunnel on I-70 (Veterans Memorial Tunnel, Figure 1) is to be…

A: Data given Elevation tunnel floor = 1500 ft Elevation of bridge deck = 1540 ft Station PVC of sag…

Q: The gradients of two intersected grade line are -3% and 3%, the radius of vertical curve is 3000m,…

A: Given:- The gradients of two intersected grade lines are:- g1 = -3% g2 = 3% The radius of the…

Q: A +3.0 percent grade intersects a - 2.0 percent grade at station 3 + 20 and at an elevation of…

A: The expression to calculate the station of the PVC is given by, Station of PVC=Station of PVI-L2…

Q: ngent vertical curve c -3.2% and a -1.1 % g e PVI is at station 10 d elevation 950 ft an T is at…

Q: A +2.50% grade sets a -1.75% grade at station 44+25 and elevation 386.96 ft, 400ft curve, stakeout…

A: Solution: Computation of grades and distances in stations perpendicular…

Q: 7.5% grade is followed by a 1.225% grade intersecting at Sta. 15+750, with an elevation of 395.5 m.…

Q: A four-lane undivided highway (two lanes per direction) has a segment of horizontal curve with the…

A: Given Data: The data for a four-lane undivided highway is given as: Radius of curve (r)=440ftLane…

Q: An upwards grade of 4.6% and a down-grade of -2.8% were connected with a vertical curve of 400m. The…

A: PVCSTATION=PVISTA-L2PVCsta=600-4002=400PVCELV=PVIELV-g1L2PVCelv=100-0.046×4002PVCelv=90.8m

Q: Compute and tabulate full-station elevations for an unequal-tangent vertical curve to fit the…

A: Based on the given data let us draw the below figure

Q: If a vertical curve's incoming grade (g₁) is -5%, the outgoing grade (g₂) is 5%, the station at the…

A: Given, g1 = -5% g2 = 5% L = 3000 ft PVI = 25+00 PVI (El) = 450 ft

Q: A 3% ascending grade meets a descending grade at the vertex at sta. 20+100 and at elevation 120 m.…

A: Given:- Ascending grade = 3% Station of vertex = 20 + 100 Elevation of vertex = 120 m Elevation of…

Q: D] Calculate the centerline elevations for PVC, VPI, PVT, station 32+00, and turning point (highest…

A: Consider the free body diagram,;

Q: NEED ASAP SOLUTION. PLOT CURVE A vertical summit curve is having tangents which intersects at point…

A: PVCSTATION=PVISTA-L212500.65=12609.84-L2L=218.38mPVCELV=PVIELV-g1L2115.52=139.82-g1×218.382g1=22.254…

Q: A -6% grade is followed by a 2% grade intersecting at Sta. 15+750, with an elevation of 372.25 m.…

Q: curve is 10°. The curve has 7 intermediate stations between P.C. (10 + 300m) and P.T. After laying…

A: Given:- 5m full station curve=10 degree 7 intermediate stations P.C.(10+300m) To find:- Compute all…

Q: The angle between a 5-m full station of a certain curve is 10°. The curve has 7 intermediate…

A: Answer We can either relocate the centreline of the curve to above the property lot or below the…

Q: between those two rc a. The required le b. Stationing and c. Location and el

Q: PROBLEM 6: A highway engineer must stake a symmetrical vertical curve where an entering grade of…

Q: A +2.50% grade sets a -1.75% grade at station 44+25 and elevation 386.96 ft, 400ft curve, stakeout…

A: Given :

Q: 103+51.05 103+53.01 103+47.56 103+49.89

A: 103 + 51.05

Q: owed by a 1.25% grade intersecting at Sta. 15+750, with an elevation of 374.5 m. The change of grade…

Q: The angle between a 5-m full station of a certain curve is 10°. The curve has 7 intermediate…

A: Point of Curvature Point of curvature is the point where the circular curve begins . The back…

Q: A-3% grade us connected to a +1.0% grade by means of 180m vertical curve. The point of intersection…

A: Length of curve= 180m Grades: g1 =-3%, g2=1%

Q: A highway engineer must stake a symmetrical vertical curve where an entering grade of +0.80% meets…

Q: Grades of g₁ = -1.00% and g2 = +3.00 %, VPI elevation 750.00 ft at station 30+00. Fixed elevation…

A: g1= -1%g2= +3%PVI Elevation = 750 ft and station = 30+00Fixed elevation, y = 753 ft and station…

Q: A+4.5% grade on rural free way intersects with a-2.5% grade at chainage of 67+500 at an elevation…

A: Given; g1=+4.5%g 2=−2.5% Chainage = 67+500 Elevation = 75 Design speed = 100 km/h

Q: Situation I: A 6' simple curve connects two tangents that intersect at an angle of 42". If the PC…

A: Given Degree of curve 1 = 6° Shift=20 m

Q: For the curve above, (an equal- tangent vertical curve connects a +3.2 % and a -1.1 % grade. The PVI…

Q: Q5. Grades of gl=-2.50% and g2=+1.50%, the intersection of grade lines at station 315-00 is at…

A: Calculation of vertical Curve and finding of Curve length and stations and elevations of BVC and EVC

Q: Given a crest vertical curve of length 523, with a PVC at elevation 1,016, connecting a grade 1% to…

A: The elevation of PVC = 1016The vertical curve consists of grades 1% and -0.5%The length of the curve…

Q: If a vertical curve's incoming grade (gl) is 5%, the outgoing grade (g2) is -5%, the station at the…

A: Vertical Curve: Vertical curves are used for highway alignment analysis. A vertical curve determines…

Q: A+5.00% grade meets a +1.50% grade at station 4+200 and elevation 605.568 m, 180-m curve, stakeout…

A: Given:- The grades of the two curves are given g1 = +5.00% g2 = +1.50% The stationing of the point…

Q: Given: L = 25 stations, PT station = 50+00, G1=-3%, G2=+1%; What is the stationing at zero % grade…

Q: A 16% grade meets a 7% grade at station 2 + 265 of elevation 250 m. The lengths are L1 = 115 m. and…

A: The grades are, g1=16%g2=7% The lengths are, L1=115 mL2=90 m The elevation is 250 m.

Q: A 3% ascending grade meets a descending grade at the vertex at sta. 20+100 and at elevation 120 m.…

A: Given data Ascending grade =n1 = 3%descending grade =- n2vertical point of inteersection = VPI =…

Question

Read the question carefully and give me right solution according to the question.

Station 10+00.00 has an elevation of 110.00 and a grade of -3%. Station 20+00.00 has an elevation of 105.00 and a grade of +2%. What is the stationing at the two grade intersections?

options

A) 14+00,

B) 15+00,

C) 16+00,

D) 17+00)

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Similar questions

A grade of -3.0% is followed by a grade of +2.1% which intersects at station 10+250 and elevation of 110 m. If the maximum change in grade per 20 m station is 0.20%, determine the following A. Length of parabolic curve that shall connect these two gradelines. B. Elevation of PC. C. Elevation of a point on the curve @ Sta.10+250.
B. A Highway curve will pass through a railway at grade. The crossing must be at Sta. 4 + 310 and at elevation 220.82 m. the initial grade is +2% and meets a -3% grade at Sta. 4 + 235 at an elevation of 223.38 m. the rate of change must not exceed at 2%. Compute the length of curve, station and elevation of highest point also check if the condition of rate of change is meet.
A highway curve will pass through a railway and grade. The crossing must be at station 4 + 310 and at elevation 220 3.38 m. the initial grade is + 2% and meets a -3% grade at station 4 + 235 at an elevation of 223.38 m. the rate of change must not exceed at 2%. Compute the length of curve, station and elevation of highest point also check if the condition of rate of change is meet.
Sketch only no need for solutions
Please answer number 4 and 5 only. Round off the answer to two decimal places
solve using grade diagram
Grades of g1= -2.00% and g2= +2.00%, VPI elevation 750.00 ft at station 30 + 00. Fixed elevation 753.00 ft at station 30 + 00.Field conditions require a highway curve to pass through a fixed point. Compute a suitable equal-tangent vertical curve and full-station elevations. Give the elevations in order of increasing X. Please give 6 elevations.
A -1% grade meets a +3% grade at sta. 12+00 and elevation 520 ft. by a vertical curve of length 200 ft. Calculate the following: i. K and r ii. Station of PVC and PVT iii. Elevation of point at a distance, L/4, from PVC and PVT iv. station of turning point v. elevation of turning point vi. elevation of mid-point of the curve
3. A grade of-8% id followed by a grade of 3%, the grade intersecting at station 11+ 020 of elevation 423. 10 m. The change of grade is restricted to 0.5% in 25 meters. a. Compute the length of vertical parabolic curve b. Solve the lowest point of the curve from the P.T. c. Calculate the elevation at station 11+ 000.
A -4% grade line meets another line of +3.2% grade at station 11+ 4O. If a 225-ft parabolic curve connects these grade lines, at what station is the lowest point along the curve located? Your answer
I need correct solution
A vertical summit curve is having tangents which intersects at point Pl at Station 12+618.37 and 133.75 meters elevation. The grade for the forward tangent is -513%. Station PC is at station 12+515.99 and having an elevation of 116 26 meters. What is the elevation of point A along the curve with Station 12+548.27? cs Seanned with CamScanner