curve is 10°. The curve has 7 intermediate stations between P.C. (10 + 300m) and P.T. After laying out the curve, it was found out that the P.T. falls in a property lot and it should be moved in a way that the P.T. will be free from crossing the lot. Co

Q: is having a radius of 120m and design speed as 80km find the total widening on the curve

A: According to given data  Mechanical Widening of the  Curve = 1.5 mCurve having a radius of =…

Q: The highway engineer of a certain road construction decided to use a radius of 100 m. in laying out…

A: Introduction- Highway engineering is a field of construction management that focuses on the…

Q: A parabolic vertical curve with a grade in of 2.1%, a grade out of - 3.2%, a curve length of…

A: (Note: Since part C is asked to solve, the solution for the c part is given below.) Given: Grade in,…

Q: Problems 9.2 A cross-over occurs between two parallel B.G. Tracks of same crossing number of 1 in 8½…

A:

Q: 3. Given a simple horizontal curve with A-8 00 00" and Pl at station 104450, calculate: a. R b. T d.…

A: a) Radius R = 1720 / D                    = 1720 /8                  = 215 m b) T = Radius x  tan…

Q: 3.)  A -4% grade meets a 7% grade at station 2 + 185 of elevation 150 m. The lengths are L1 = 70 m.…

A: Downward gradient=-4% Upward gradient=7% Elevation=150 m L1=70 m, L2=50 m.

Q: What is the length of the curve, G1, highest point of curve, and the elevation of the highest point…

A: To find : Length of the curve, G1, highest point of curve, and the elevation of the highest point on…

Q: B-Unequal-Tangent Parabolic (Vertical) Curve: Example: A grade g1 of -2% intersects g2 of +1.6% at a…

A: Solution: Point A STA 85 + 00: Elev. = 743.24+2(2) = 747.24' Point B STA 90 + 00: Elev. =…

Q: A reverse curve has a radius of the curve passing through the P.C. equal to 200m and that of the…

A: Given : Radius of the curve passing through the P.C., R1 = 200 mRadius of the curve passing through…

Q: PI sta = 18+00, PI elev = 300.00, L = 20 stations, incoming grade = +2%, outgoing grade = -3%   The…

A: Data given Sta PI = 18+00 Elevation of PI = 300  L = 20 stations G1 = +2% G2 = -3% To find: -…

Q: A grade of -5% grade intersects a grade of 0%. P.C. has a STATION of 10 + 110.00 which has an…

A: Given that   Sag vertical curve   g1 = -5%   g2 = 0   A = G1-G2   A = -5   PC station = (10+110)…

Q: An equal-tangent crest curve connects a +2.0% and a-1.0% grade. The PVC is at station + 670 and the…

A: The curve length will be: Lm=2×100station2 of PVI-station1 of PVCLm=200(1+790-1+670)      =240 ft

Q: A forward tangent of +6% was designed to intersect a back tangent of  -3% at a proposed underpass…

A: GIVEN DATA:- L1 = 200m L2 = 100m g1 = -3% g2= +6% VPI 12+ 530.20 Bridge Elevation = 117.48m VPI…

Q: Q6. A -2.5% grade is connected to a +1.0% grade by means of a 180 m vertical curve. The P.I. station…

A:

Q: A symmetrical parabolic summit curve is to connect two roads with grades of +4% and -2.5% that meet…

A: G1 = 4%  G2 = -2.5%

Q: A +4% grade line intersects a -2 % grade line at station 6+800, where the elevation is 642.40 m. as…

A: When a route changes direction from right to left or its alignment changes from up to down, curves…

Q: Q-5 The mechanical widening of a curve is 1.5m, the curve is having a radius of 120m and design…

A: given- mechanical widening=1.5 mradius of curve=120 mdesign speed=80 kmph

Q: An equal tangent vertical curve is to be constructed between grades of -6.75% (initial) and 4.75%…

A: G1= -6.75% G2= 4.75%PVI station = 12+000.000 PVI elevation = 319m Station = 12 + 071.00 Elevation =…

Q: 1. IN A CERTAIN ROAD CONSTRUCTION IS UNDERTAKEN DPWH, IT VWAS DECIDED TO CONNECT A FORWARD TANGENT…

A:

Q: A grade ascending at the rate of 6% meets another grade descending at the rate of 4% at the vertex…

A: Given  G1= 6%  G2= -4 %

Q: EXAMPLE A -2% grade meets a +8% gradę near an underpass. In order to maintain the minimum clearance…

A:

Q: A horizontal curve is designed with a 1800 ft radius. The curve has a tangent of 1000 ft and the PT…

A: Schematic diagram of the given problem: Radius of the curve (R) = 1800 ft tangent length (T) = 1000…

Q: Two parallel roads 400 m. apart were to be connected by equal turnouts. The intermediate tangent is…

A: In this question the basic thing is to draw the diagram since the radius of both the curves are same…

Q: A -6% grade is followed by a 2% grade intersecting at Sta. 15+750, with an elevation of 372.25 m.…

A:

Q: between those two rc a. The required le b. Stationing and c. Location and el

A:

Q: Please help me solve this problem and also, please do make some Illustrations and sketches. I need…

A: Solution-Curvature Point  The position of curvature is the starting point of a circular curve. At…

Q: Vertical highway curve: Given PVI at 128 + 00, L = 1,000 ft, g1 = -5%, g2 = +4%, and PVI elevation =…

A:

Q: Two tangents intersect at V with back tangent having a grade of -2.75% and forward tangent of 6.25%.…

A: PI: PI means Point of Intersection. The point origin where the back and forward tangents intersect…

Q: A +1.512% grade meets a -1.785% grade at PVI Station 31+50, elevation 562.00. The Equal Tangent…

A: Given:- The initial grade of the curve = +1.512% The final grade of the curve = -1.785% The station…

Q: Grades of gl=-2.50% and g2=+1.50%. the intersecti elevation 2560.00 ft. Fixed elevation 2567.00 ft…

A: BVCsta=PVI-L2=31500-L2BVCelv=PVI-g1L2=2560--0.025L2=2560+0.0125L

Q: A-3% grade us connected to a +1.0% grade by means of 180m vertical curve. The point of intersection…

A: Length of curve= 180m Grades: g1 =-3%, g2=1%

Q: A -6% grade and a +2% grade intersect at STA 12 + 200 whose elevation is at 25.632 m. The two grades…

A:

Q: 3. A -4% grade line (400 ft length) intersects a -2% grade line (200 ft length) at station 63+00,…

A: Given:- The grade of line 1 (g1) = -4% The length of line 1 = 400 ft The grade of line 2 (g2) = -2%…

Q: Design the curve, of An equal tangent vertical curve is to be constructed between grades of -2.0%…

A: Initial Grade = -2.0%Final Grade = +1.0%PVI1 (Point of Vertical Intersection 1): Station 11+000.000,…

Q: Grades of gl=-2.50% and g2=+1.50%, the intersection of grade line at elevation 2560.00 ft. Fixed…

A: BVCsta=PVI-L2=31500-L2BVCelv=PVI-g1L2=2560--0.025L2=2560+0.0125L

Q: It is desired to connect two intersecting roadways, the centerlines of which have bearings N 40°30'E…

A:

Curve setting

A curve is a turn that is provided horizontally or vertically in the design of highways, railways, and runways. A curve connects two straight lines that are separated by the deflection angle. It helps to change the direction and alignment of the highways, railway tracks, and runways. Therefore, the gradual change in their alignment is made by using a curve to provide comfort to the passengers and this also provides an easy turn to change the direction of the moving vehicle.