A matchbox car track begins at a height y=1.0, goes down hill to y=0, goes around a vertical loop of radius 0.2 m and then goes back up a smaller hill to end at a height y=0.3 m. The speed of the car at the end of the track is closest to which value? Question 5A matchbox car track begins at a height y=1.0, goes down hill to y=0, goes around a vertical loop ofradius 0.2 m and then goes back up a smaller hill to end at a height y=0.3 m. The speed of the car atthe end of the track is closest to which value?2 m/s2.5 m/s3.0 m/s3.5 m/s4.0 m/s4.5 m/s

We know, the centripetal force is given by F=mv2r The force on the car due to gravity is given by…

Answered: Question 5 A matchbox car track begins…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A matchbox car track begins at a height y=1.0, goes down hill to y=0, goes around a vertical loop of radius 0.2 m and then goes back up a smaller hill to end at a height y=0.3 m. The speed of the car at the end of the track is closest to which value?

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