(exam prep fluids 3) The head developed by the 250mm impeller diameter pump (from annexure A) rotating at 2900rev/min in the system below at its operating point was found to be 72m of water (p=1000kg/m²; 4=1.14x10-3Pa.s; y=9.81kN/m²; Pvapor-1.7kPa abs). The total length of the 77.9mm diameter pipe (e=0.000046m) is 20m. The elbows are 90° standard (Le/D=30). Take atmospheric pressure as 100kPa (abs) and the gauge pressure above the fluid surface in the sealed tank is 25kPa below atmospheric. 3.1 Obtain an expression for the NPSH, to the pump in the system from the energy equation. 3.2 Obtain the pipe friction factor 3.3 Suggest a suitable position for the pump if a 10% tolerance between NPSH and NPSHr is to be achieved to avoid cavitations. 3.4 Calculate the output power of the pump. 3.5 Obtain the power required to drive the pump.
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- For a 6.25-inch Model 4075 pump operated at 1160 rpm, if 450 GPM of water is to be delivered, what will be the estimated pump head in ft? HEAD IN FEET 30 25 0 0 0 10 O 6 ft 7.25" (184mm) 20 7.00" (178mm). 6.75" (171mm). 6.50" (165mm)] 15 6.25" (159mm). 5 O 16 ft O 20 ft O 12 ft aco® L/SEC 5 OT 10 Model 4075 FI & CI Series 15 -6-6 ⁰ dº 20 ANA 888 778 25 REQUIRED NPSH do 1160 RPM November 1, 2010 K ・dº- [M 90 do 30 8800 81 1HP(.75KW) DeJ kin do 60% 35 do 50 Curve no. 2175 Min. Imp. Dia. 6.25" Size 5 x 4 x 7.0 40 45 3HP(2.2KW), 2HP(1 5KW) 5HP(1 1KW)> CURVES BASED ON CLEAR WATER WITH SPECIFIC GRAVITY OF 1.0 L 75 150 225 300 375 450 525 600 675 FLOW IN GALLONS PER MINUTE NOWONG FEET 15 12 7 6 2 1 NPSH 758 50 5 HEAD IN METERS 45 586888 KPO 60 40 20 10 LO HEAD IN KILOPASCALSarrow_forward5.19 Consider the piping system shown in the following diagram. The pump operates at 1750 rpm. El 1475' L= 8000'; D = 12";f=0.026 El 1200' Pump 106 Turbomachinery: Concepts, Applications, and Design The pump curve is given by h,=350-24Q² where h, is given in ft. and Q in cfs. What would the head and flow rate delivered be under these conditions? Ans: Q=160 cfs; h,=288 ft 5.20 Solve the previous problem for two identical pumps connected in (a) series and (b) parallel. Ans: a) Q=2.83 cfs, h,=315 ft; b) Q=2.58 cfs; h,=310 ft %Darrow_forwardExample (6-1): At the best efficiency point a centrifugal pump, with impeller diameter D=8 in, produces H= 21.9 ft at Q=300 gpm with N=1170 rpm. Compute the corresponding specific speed using a) U.S. customary units. B) SI units (rad/sec, m/sec, m'/sec").c) European units (rev/sec, m/sec, m/sec?). Develop conversion factors to relate the specific speeds.arrow_forward
- Figure below shows the performance curve family of Model 5009 Centrifugal pumps of Taco Pump Inc., running at a fixed speed of N = 1160 rpm. For the pump with the impeller diameter D = 8.625 in., you are asked to determine the best efficiency point (BEP) of the given pump. What is the pump efficiency at BEP? HEAD IN FEET 50 0 0 0 0 40 20 10 O 81% 8.625" 30 (219mm). O 51% O 71% ○ 61% O Taco L/SEC 5 9.25" (235mm) 8.00" (203mm) 7.375" (187mm) 6.75" (171mm) 0 10 15 125 Model 5009 FI & CI Series 20 25 CURVES BASED ON CLEAR WATER WITH SPECIFIC GRAVITY OF 1.0 8 8 52 75% 77% 30 79% 1160 RPM FEBRUARY 19. 2002 35 40 45 REQUIRED NPSH olº 1.5HP (1.1KW) dot 17% Curve no. 2140 Min. Imp. Dia. 6.75" Size 6 x 5 x 9.0 50 55 60 75% 72% 250 375 500 625 FLOW IN GALLONS PER MINUTE 8% 2HP(1.5KW) 750 %09. 55% (2.2KW) 3HP 7.5HP(5.6KW) 2015 do 35% 875 FEET 15 12 -9 6 SHP(3.7KW) 3 0 10 8 NPSH 1000 HEAD IN METERS 5 KPo 45 -36 27 18 9 -0 100 -80 60 -40 2 -20 8 HEAD IN KILOPASCALSarrow_forwardFigure below shows the performance curve family of Model 5009 Centrifugal pumps of Taco Pump Inc., running at a fixed speed of N = 1160 rpm. For the pump with the impeller diameter D = 8.625 in., calculate the power coefficient (Cp*) of the given pump at BEP if water is the fluid. HEAD IN FEET 0000 50 40 20 10 8.625" 30 (219mm). 0 O 0.821 O 0.731 O 0.467 aco 10 O 0.235 L/SEC 5 9.25" (235mm) 8.00" (203mm) 7.375" (187mm) 6.75" (171mm) 125 Model 5009 FI & CI Series 25 15 20 -do CURVES BASED ON CLEAR WATER WITH SPECIFIC GRAVITY OF 1.0 72% 75% 30 79% 1160 RPM FEBRUARY 19. 2002 40 3,5 45 REQUIRED NPSH 1.5HP (1.1KW) 79% 1⁰⁰ of 15² Curve no. 2140 Min. Imp. Dia. 6.75" Size 6 x 5 x 9.0 50 55 60 250 375 500 625 FLOW IN GALLONS PER MINUTE 72% 2HP(1.5KW) colo & 2⁰. It & SC- 09. 55% 5% 3HP (2.2KW) 7.5HP(5.6KW) 45% de 750 875 NGFEET 15 12 -9 -6 3 0 10 8 50 SHP(3.7KW) NPSH HEAD IN METERS 1000 r45 36 F27 18 -9 0 -100 --80 4 -40 -60 2 -20 -O HEAD IN KILOPASCALSarrow_forwardShow schematic diagram and complete solutions.arrow_forward
- A manufacturer tested one of its pump models at 2133.5 rpm and derived the characteristics as shown in the figure on the left. Being satisfied with the model, the manufacturer decided to make a prototype that is 4 times larger than the model for one of its clients. The prototype pump is going to be operated at a shaft speed of 100 rpm to deliver 6000 GPM of water. What will most approximately be the pump efficiency of the prototype when it is on duty? Head, m; power, kW oooo 250 200 150 100 O 62% O 22% O 42% 50 O 82% 0 Efficiency 0.05 Head (AH), m N=2133.5 rpm n = 35.6 rps D = 37.1 cm 0.10 0.15 Discharge, m³/s Power input, kW 0.20 0.25 100 80 60 40 20 Efficiency, percent 5 4 CH 3 2 H 1 0 0 Efficiency, n 0.04 C 0.08 Co CH 0.12 1.00 0.75 0.50 0.25 0 0.16 Cp and efficiencyarrow_forwardProblem-4: The characteristics for a pump are given in the table below. The pump is required to left water against static head Az = EN" m. The pipe arrangement has a total length L the pump discharge, head, efficiency and power for the given pipe system. 200, d = 0.1 m and f= 0.016. Find %3D Q (L/s) 10 20 30 35 42 50 Hp (m) efficiency % 210 201 180 150 129 93 48 30 58 80 85 86 74 EN=62 Hp = Az + h, = Az + 12.1 d P = 757arrow_forwardRefer to the “composite performance chart” for a Goulds 3x4-10centrifugal pump operating at 1750 rpm. It shows the pump performance curve for 5 differentimpeller sizes, but also shows the HP required, efficiency, and NPSH required at differentoperating points.Describe the performance of this pump, using an 8 inch impeller and a required flow rate of175 gpm. Give head available, power required (BHP), efficiency, and NPSH req’d. What is the water horsepower (WHP)?arrow_forward
- Analyze to select the type of the turbine when its diameter is 600 mm, rotational speed is 600 rpm and working under a water head of 120 meters. The buckets deflect the 100 mm diameter jet through an angle of 165°. Take the coefficient of velocity for the nozzle as 0.97. Use Table given below for selection of turbine. Sr. # Specific speed (rpm) Type of turbine 1 8-30 Pelton wheel with one nozzle 30 - 50 Pelton wheel with 2 or more nozzles 50-250 Francis turbine 4 250-1000 Kaplan turbine 2. 3.arrow_forwardDisplacement (c): 0.2 in3/revShank diameter (d) = 0.625 in.Piston diameter (D) = 1.5 in.Rotation speed (n): 1725 RPMPressure (P): 600 PSIStroke (L) = 18in. a) Calculate the theoretical flow rate of the pump in in3/min and US GPM.Theoretical flow (Q) = Theoretical displacement (C) x Speed of revolution (n)Theoretical flow (Q) = 0.2 in3/rev x 1725 rpmTheoretical flow (Q) = 345 in3/min = 1.49 US GPM b) Calculate the cylinder output speed in in/s.Cylinder output speed (VS) = Piston side flow (Q) / Piston area (Ap)Cylinder output speed (VS) = (Displacement x Speed of revolution) / Piston area (Ap)Cylinder output speed (VS) = (0.2 in3/rev x 1725 RPM) / 1.77 in2Cylinder output speed (VS) = (0.2 in3/rev x 1725 RPM) / 1.77 in2Cylinder output speed (VS) = 196.02in/s = 196.02 / 60s = 3.20 in/s Questions: c) Knowing the output velocity (ram speed), calculate the rod side flow in GPM when the ram is extending. d) Calculate the piston exit time in seconds. e) Calculate the piston entry time in…arrow_forwardKindly answer with complete solution please. Subject: Fluid Mechanicarrow_forward
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