Question 1 1 Consider the following reaction: Ce2(g) + 2NO(g) = 2NOC{(g) 1.1 Determine the estimated value of the equilibrium constant for this reaction at 158 °C by making use of the following data: kj at 25°C mol Substance at 25°C 4,H° ()a \mol. K. Cl2(g) 221.3 NO(g) 210.8 90.29 NOC? (g) 261.7 51.71 1.2 Based on your final answer in question 1.1, is the reaction reactant- or product favoured at this temperature? Use a short sentence to explain your answer. 1.3 Calculate the value of A,G for this reaction at this temperature, if Cł2 , NO and NOC? are present at 0.600 atm, 0.700 atm and 0.500 atm, respectively.

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Question 1
1
Consider the following reaction:
Ce2(g) + 2NO(g) = 2NOC{(g)
1.1 Determine the estimated value of the equilibrium constant for this reaction at 158 °C by making use
of the following data:
kj
at 25°C
mol)
Substance
S°
\mol. K
at 25 °C
C{2(g)
221.3
NO(g)
210.8
90.29
NOCE (g)
261.7
51.71
1.2 Based on your final answer in question 1.1, is the reaction reactant- or product favoured at
this temperature? Use a short sentence to explain your answer.
1.3
Calculate the value of A,G for this reaction at this temperature, if Cł2 , NO and NOC? are
present at 0.600 atm, 0.700 atm and 0.500 atm, respectively.
Transcribed Image Text:Question 1 1 Consider the following reaction: Ce2(g) + 2NO(g) = 2NOC{(g) 1.1 Determine the estimated value of the equilibrium constant for this reaction at 158 °C by making use of the following data: kj at 25°C mol) Substance S° \mol. K at 25 °C C{2(g) 221.3 NO(g) 210.8 90.29 NOCE (g) 261.7 51.71 1.2 Based on your final answer in question 1.1, is the reaction reactant- or product favoured at this temperature? Use a short sentence to explain your answer. 1.3 Calculate the value of A,G for this reaction at this temperature, if Cł2 , NO and NOC? are present at 0.600 atm, 0.700 atm and 0.500 atm, respectively.
Expert Solution
Step 1

Recall the given equation

       Cl2g + 2NOg  2NOClg

Recall the following relations

           G°=H°-TS°Here, G° is change in Gibbs free energy at standard state         H° is change in enthalpy at standard state         S° is change in entropy at standard state

Again recall the following relation

     G°=-RTlnKp

 and  rG=RTlnQKpQ is reaction quotient

 

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