The slope of the log K vs 1/T graph is 1.352·104K. How about value can be used to calculate the reaction ΔH°? What is correct: a) ΔH° = Slope·R b) ΔH° = - Slope c) ΔH° = - Slope/R d) ΔH° = - Slope·R

I am confused by only K value. I think it is  Substituting the values: ln(K) = -(-3.9 × 105 J/mol) / (8.314 J/K.mol × 298 K)  = 157.41 Taking the exponential of both sides gives: K = e^157.41  K =  2.3 X 10^68

I want solutions of all parts... Otherwise I will downvote

Identify the reactions that are exothermic. ) Multiple answers: Multiple answers are accepted for this question Select one or more answers and submit. For keyboard navigation... SHOW MORE V C(graphite)C(diamond) AH° = 2 kJ b. CaCO3 (s) CaO(s) + CO2(g) AH° = 178 kJ CuO(s) + H2 (g) → Cu(s) + H2 0(g) AH° = -85 kJ 2H2 (g) + 02(g) - 2H20(g) AH = -484 kJ 3H2 (g) + N2(g) 2NH3 (g) AH - 92 kJ Unanswered

[Review Topics] [References] Use the References to access important values if needed for this question. Consider the following system at equilibrium where AH=-108 kJ, and K. 77.5, at 600 K. CO(g) + C,(g) COCI,(g) When 0.22 moles of Cl,(g) are added to the equilibrium system at constant temperature: The value of K The value of Qe K. The reaction must O run in the forward direction to restablish cquilibrium. O run in the reverse direction to restablish cquilibrium. O remain the same. It is already at cquilibrium. The concentration of CO will Submit Answer Retry Entire Group 1 more group attempt remaining

What is the effect of equilibrium when heat is removed (cooled) from the system? CO + H2O ⟷ CO2 + H2 ΔH = +41.4 kJ Group of answer choices Neither reactant nor products would be produced. Shift left. Both reactants and products would be produced. Shift right. This equation does not represent an equilibrium system.

Ammonia (NH3) decomposes to form nitrogen gas and hydrogen gas with an enthalpy of 89.4kJ/mol. Aclosed container is charged with 6.0 atm ammonia and heated to 25.0°C. At equilibrium the pressure of H2 is3.60atm. a. Write the balanced reaction.

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6. Consider the reaction noitos to 38H HCI + NaOH → NaCl + H,O 2noiteonO ded-teo1 Which you also performed in the experiment Stoichiometry of Two Reactions. Given the information below: Initial temperature °C maa HCl solution 22 NaOH solution 22 o oulsd 10 s Final temperature °C 26.1 madovs o oitoson or os W Temperature Change °C А. Calculate the amount of heat evolved when 15 mL of 1.0M HCl was mixed with 35 mL of 1.0 M NAOH. n 1g ieodl ni agnerto sd es bonlhal d welsto sYT В. Calculate AH° per mole of water formed from this data: Heat evolved Joules kilojoules/mole

What is AG for the reaction l2(g) → 2 1(g) at 25.0 °C if K = 6.1 x 10-2²? (R = 8.314 J/mol.K)