Q47 In the circuit shown below, the initial capacitor voltage is 4 V. Switch S1 is closed at t=0. The charge (in µC) lost by the capacitor form t= 25 µs to t= 100 µs is
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Q: E = 245 V | R1 = 74 kΩ | R2 = 15 kΩ | R3 = 47 kΩ The capacitor in this circuit initially has no…
A: The given circuit with node markings can be drawn as:
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A: Given: C1=2 μFC2=4 μFC3=6 μFC4=8 μFCeq=4.2 μF
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Q: R = 50 kN , = 10 V C = 0.04 µF
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A: Bartleby has policy to solve only first 3 subparts of a question so please reupload the question.
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- 4. In what form is the energy of a capacitor stored?Three capacitors having capacitance values of 20F,40F, and 50F are connected in parallel to a 60 - Hz power line. An ammeter indicates a circuit current of 8.6 amperes. How much current is flowing through the 40F capacitor?The figure displays two circuits with a charged capacitor that is to be discharged through a resistor when a switch is closed. In figure (a) below, R₁ = 23.32 and C₁ = 5.04 μF. In figure (b) below, R2 = 10.82 and C₂ = 8.10 μF. The ratio of the initial charges on the two capacitors is 902/901 = 1.61. At time t = 0, both switches are closed. At what time t do the two capacitors have the same charge? 0.0 (a) (b) Number i Units
- A 20-ohm resistor and a capacitor are connected in series with a battery of 60 volts. At t = 0, there is no charge on the capacitor. Find the capacitance if the current at t = 5 seconds is 3/e^s amperes. Ans. 0.05 FaradsWhen the switch is in position 2, the circuit will discharge the capacitor. Draw the circuit for the discharge phase. (without any of the charge phase components). and determine the time constant for the discharge phase and the equations for v(t) and i(t) for the discharge phase.a) With switch J2 open, close switch J1. Estimate the time it takes to do it. Obtain the equations for the voltage and current of the capacitor. Determine the energy stored by the capacitor. b) Open switch J1, close switch J2. Estimate the time it takes to do it. Obtain the equations for the voltage and current of the capacitor.
- In the figure R1 When the switch is opened after having been closed for a long time, the current in the inductor drops from 1.00 A to 0.250 A in 0.200 s. What is the inductance of the inductor in mH? = 4.00 N , and R2 = 1.00 N. The inductor is ideal. %3D Şekildeki devrede R1 = 4.00 N , ve R2 = 1.00 N olarak verilmişlerdir. Solenoidin iç direnci yoktur. Anahtar uzun süre sonra kapalı kaldıktan sonra açılırsa solenoidden geçen akım 0,200 s içinde 1,00 A değerinden 0,250 A değerine düşmektedir. Solenoidin indüktansı mH cinsinden nedir? R1 S R2 L lehow do i calculate the inverse capacitance and its uncertainty if the capacitance value 1.8748+/- 0.0006. please show steps im using this example to do my other values.A thin metallic foil is placed between the plates of a flat capacitor parallel to them. How does this affect capacity? What if you join a plate with a wire?
- . In the adjacent figure each of the two capacitors mounted in parallel has a value C,the resistor has a value R, and the power supply has value ɛ= 25 V. Upon closing thekey S the charging process of the two capacitors starts. The initial value of the electriccurrent was I0 = 25 mA, as shown in the table below, then the electric currentdecreased until it vanished at . The table below shows the values of the electriccurrent every two seconds as measured by the ammeter A.a) Determine the value R of the resistor in k ohm units.b)Plot the I-t graph (electric current versus time).c)Determine the circuit constant time from the I-t graph.d)Determine the value C of each capacitor in micro F units.e)Complete the table by evaluating the electric charge q(t) on eachcapacitor at the moments .a. As capacitor charges, describe the behavior of: i.current with time ii. the voltage across the resistor with time iii. capacitor voltage withtime Explain the reason for each behavior.Find the current through the inductor shown in Figure lb. (i/p is AC, consider results upto one decimal place). 1. 100 V 100 Hz 500 L=60H Figure lb