#Q3.W/C0.450.50.55fc (MPa)212423Then,1. Fit a polynomial and find fc @ W/C=0.522. Find the max compression strength (fc) and the corresponding w/c ratio. (Findthe optimum w/c ratio)3. Graph the polynomial.

Answered: Image /qna-images/answer/28b2156b-8416-468a-8b1e-14480fe86f62.jpg

Answered: #Q3. W/C 0.45 0.5 0.55 fc (MPa) 21 24…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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SN= 93
78.75 мра 33.61 MPa 22.11 MPG Determine @ Omax Omin Tmax (@s, @p) sketch the result JLULL e pain wel, w un pipar places an B , (b) the stress components exerted on the element obtained by rotating the given element clockwise through 30°. Sketch the result
Please answer parts A to C with legible and complete solutions.
3= The state of strains at a point are defined as follows. Find X and Y such that the normal and tangantial component of the strain vector on a plane with normal unit vector of n=(n,n2,n3) is equal to En Et. 80 Y-50 [ε] = Y X 20 (*10 m/m) 50 4 n₁ n₂ n3 &*10 0.4 0.2 0.894 37.57 -50 20 En *10 28.58
Determine the state of stress acting at point D. Take P₁ = 50 kN and P2 = 10 kN. OD= B ANSWER: P₁ TD= -1.5 m 1.5 m--1.5 m- 0.5 m 40 mm 100 mm 60 mm T D E P₂ 80 mm Part A Find o D. Express your answer to three significant figures and include the appropriate units. Enter negative value in the case of compression and positive value in the case of tension. ANSWER: C Q Tap image to zoom Part B Find TD- Express your answer to three significant figures and include the appropriate units.
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Vn = 6*36*1/(4*1.1) = 49.09 am I wrong? I believe in the calculation in the solution the coefficient m was not taken into account. And Pn is not 54 kips either, with the given formula it comes up as 6*36*0.5/(4*1.25) = 21.6 and in which case the design strength would be 21.6 kips. Please let me know if there's something I'm missing from the formulas.
For the stress case given in the figure, approximate the principal plane (in degrees).
Two dimensional stress tensor at a point is given by a matrix *][* [100 30 30 20 The maximum shear stress is MPa MPa.
UPVOTE WILL BE GIVEN. WRITE THE COMPLETE SOLUTIONS LEGIBLY. NO LONG EXPLANATION NEEDED. SOLVE IN 2 DECIMAL PLACES. BOX THE FINAL ANSWERS.
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A thin rectangular plate is uniformly deformed, as shown. Determine the shear strain yy at P. Assume a = 111o mm, b = 620 mm, c = 0.8 mm, and d = 0.9 mm. Answer: Shear strain yy = prad.

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#Q3. W/C 0.45 0.5 0.55 fc (MPa) 21 24 23 Then, 1. Fit a polynomial and find fc @ W/C=0.52 2. Find the max compression strength (fc) and the corresponding w/c ratio. (Find the optimum w/c ratio) 3. Graph the polynomial.