Q3: Determine the maximum positive moment and the maximum negative moment at B caused by the moving load. (15 Marks) B 2m 2m C A 2 m Internal Hinge DV 2 m E 3 m 30 kN 11 kN 10 kN 1m 2m + 2m 20kN

3 For the beam shown, find the reactions at the supports and plot the shear-force and bending-moment diagrams. V = 9 kN, V2 = 9 kN, V3 = 200 mm, and V4 = 1100 mm. ATAT-V3 Provide values at all key points shown in the given shear-force and bending-moment diagrams. X (mm) B A = B = C = D = E= F= P = Q = E * KN * KN * KN × KN KN x KN ✩ kN.mm *kN.mm D 0.00 Reaction force R₁ (left) = In the shear-force and bending-moment diagrams given, +V 0.00 X (mm) 6.3 kN and reaction force R2 (right) = P 11.7 kN. Q 0.00

Finding the bar forces by the nodal point method

What are the magnitude (F) and the location measured from end A (d) of the equivalent resultant force of the triangular distributed load in the figure below 3m в Select one O a F 9 KN: de 6 m O b F 18 KN: d 6 m O c F6 KN: d= 6.5 m O d. F-6 KN:d1m

QUESTION 1 Determine the reaction moment at x = 0 in kN-m. QUESTION 2 Determine the vertical reaction force at x = 0 in kN. QUESTION 3 (1-3) Determine the horizontal reaction force at x = 0 in kN. The distributed load, f(x), is equal to 100 kN/m. /// f(x) 3 m

Q3

Solve For the sum of moment oF all Forces dockwise direction is pasitive at point A, B, I D. Include all moments. 2m ES J0ON A 100 N-m G=8ON 2m 2m 55N.m R= 90N 2m 2m P= 120N 2m 2m 2m 2m

Please

The column shown is fabricated from two C250 x 30 standard steel shapes (see Appendix B for its cross-sectional properties) that are oriented back-to-back with a gap of 33 mm between the two channels. The column is fixed at its base and free to translate in the y direction at its upper end. Translation in the z direction, however, is restrained at its upper end. A load P is applied at an offset distance of 430 mm from the channel flanges. Use the AISC equations given in Section 16.5, and assume that L = 4.1 m, s = 33 mm, E = 200 GPa, oy = 275 MPa, and (Gallow); = 145 MPa. Offset - distance e P Lateral bracing in z direction C250 x 30 L C250 x 30 Cross section.

Use the graphical method to construct the bending-moment diagram and identify the magnitude of the largest moment (consider both positive and negative). The ground reactions are provided. MB = 143 kN-m Mc = 51 kN-m Ay = 16.17 kN (down) Dy = 16.17 kN (up) 1997 4 m 5 m O 80.9 kN-m O 74.1 kN-m O 94.5 kN-m O 50.4 kN-m O 60.6 kN-m 3 m D X