Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Can you please double check my work for #2?
**Transcription for Educational Website**

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**Title: Understanding pH and Concentration Calculations**

**Question 2: Calculate the pH of a 6.73 x 10^-4 M H3PO4 (phosphoric acid) solution.**

- **Formula:** pH = -log[H+]
- **Molar mass of H3PO4:** 97.994 g/mol
- **Density of H3PO4:** 1.88 g/mL

**Solution:**

The dissociation of phosphoric acid is shown as:
\[ 3 \times 6.73 \times 10^{-4} \rightarrow 3H^+ + PO_4^{3-} \]

This implies:
\[ \text{pH} = -\log[ \text{H}^+] = -\log(2.019 \times 10^{-3}) \]

The calculated pH is 2.69.

**Question 3: Calculate the [H+] (concentration of the H+) of an HCl solution when the pH = 2.88.**

- **Hint to solve Q3:** Use the antilog function (inverse log).
  
- **Molar mass of HCl:** 36.458 g/mol
- **Density of HCl:** 1.18 g/mL

For HCl, when pH = 2.88:
\[ \text{[H}^+\text{]} = 10^{-\text{pH}} = 10^{-2.88} \]

The calculated concentration \([H^+]\) is approximately:
\[ 1.318 \times 10^{-3} \, \text{M} \approx 1.3 \times 10^{-3} \, \text{M} \]

The values calculated show important applications of the logarithmic and exponential functions in chemistry, specifically in calculating the acidity of solutions. Understanding these concepts is crucial for accurately gauging the properties of acidic or basic solutions.

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End of Transcription
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Transcribed Image Text:**Transcription for Educational Website** --- **Title: Understanding pH and Concentration Calculations** **Question 2: Calculate the pH of a 6.73 x 10^-4 M H3PO4 (phosphoric acid) solution.** - **Formula:** pH = -log[H+] - **Molar mass of H3PO4:** 97.994 g/mol - **Density of H3PO4:** 1.88 g/mL **Solution:** The dissociation of phosphoric acid is shown as: \[ 3 \times 6.73 \times 10^{-4} \rightarrow 3H^+ + PO_4^{3-} \] This implies: \[ \text{pH} = -\log[ \text{H}^+] = -\log(2.019 \times 10^{-3}) \] The calculated pH is 2.69. **Question 3: Calculate the [H+] (concentration of the H+) of an HCl solution when the pH = 2.88.** - **Hint to solve Q3:** Use the antilog function (inverse log). - **Molar mass of HCl:** 36.458 g/mol - **Density of HCl:** 1.18 g/mL For HCl, when pH = 2.88: \[ \text{[H}^+\text{]} = 10^{-\text{pH}} = 10^{-2.88} \] The calculated concentration \([H^+]\) is approximately: \[ 1.318 \times 10^{-3} \, \text{M} \approx 1.3 \times 10^{-3} \, \text{M} \] The values calculated show important applications of the logarithmic and exponential functions in chemistry, specifically in calculating the acidity of solutions. Understanding these concepts is crucial for accurately gauging the properties of acidic or basic solutions. --- End of Transcription
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