Q1/ Find lo for the circuit shown 200,260 502 -130 HE e 120 127 140 I 1022
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Q: Determine the value current supply (IT) in figure (1). Fig.1 lon. lons 55 n ·lon Slove IT 24V VT
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Q: Determine the value current supply (IT) in figure (1). Fig.1 lon} lon: 55 ·lon Slove IT 24V VT
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Q: Apply Norton theorem to calculate the current in 62 resistance for the circuit in figure 3 2001 + 55…
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- Provide drawing or FBD. Determine the Equivalent Resistance ofterminals a &d. (Use Delta-Wye)How you have find the value of k, Pls expalin in detailCalculate the output for the given circuit. R2 R2 Voo ww R1 Let the values are R1=250.6ohm,R2%=978.86 ohm .The error voltage is =74 Volt and he initial value of output is 4.9 Volt. Vout = volt.
- Calculate the output for the given circuit . R2 ww R2 R Voa R R1 Let the values are R1=617ohm,R2=807.15 ohm .The error voltage is =5.6 Volt and the initial value of output is 2.5 Volt. Vout = volt.Calculate the output for the given circuit. R2 ww R2 Voo ww Veo R1 Let the values are R1=303.5ohm, R2=835.21 ohm „The error voltage is =5.1 Volt.and the initial value of output is 3 Volt. Vout = volt. %3DID 62200072 Please solve right now
- An LM317 is connected between two decoupling capacitors. There is a 220ohm resistor between the output pin and the adjust pin. Note the voltage drop between the output and adjust pins is 1.25V. Find the resistor needed between the Adjust pin and ground to ensure 5 V is dropped across the load. Enter your answer in ohms: _ohmsDraw the outputs Q1, Q2 AND X in the system given in the figure CLK- CLK D Q1 Q2 X U O a Q1 Q2 HAL LO L1 MUX SO XTo solve the letter e.) problem the next picture is the guide follow the process example
- Reset WED W=O W =l EhD DII W=0 Derive the following state-table Present state Next state output z2zlz0 W=0 W=1 A 000 B 001 C 010 D 011 E 100this is electric circuit questin ...plz solve it early .plz solve earlySubject: CircuitsGivenRt = 37.9529 ohm..Rcd = 3.6 ohm.Rab=2.3529ohmIt=1.58APt=94.85WV2=3.16VV4=6.32VVab=3.7175vVcd=5.688VI10=0.372AI5=0.7435AI8=0.465AI9=0.632AI6=0.348AP2=4.9928WP4=9.9856WPab=5.88WP14=34.95WPcd=8.99WP12=29.96W