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- Which of the following is not a requirement for an electric circuit? a. a source b. a path c. a load d. a signal lightDiodes and rectifiers allow current to _________. flow in one direction only flow in both directions divide paths of flow none of the above//sketch the output wave form of the below. The input voltage circuit shown varies from "0" to "150V" linearly, Assame the diodes are ideal. D₂ Vi gül DI * + 300 - look 3200K. I+ I 10ου + vo.
- 2. Draw the graph of the voltage across the 10K resistor (calculate the values for the different voltages across the 10K resistor) of the circuit in the figure, knowing that the voltage source V is sinusoidal. And the diodes are siliconQ*: Calculate the current through 48 Q resistor in the circuit shown in Figure(i).Assume the diodes to be of silicon and forward resistance of each diode is 1 Q. D D2 48 2 ww 10 V= D4 D3 (i)Diodes Are Connected In Series To Share A Total... 21 Question • Two diodes are connected in series to share a total reverse voltage of VD=D 5 KV. Reverse leakage currents of the diodes are ID1=30 mA and Ip2=35 mA. - Find Vp1 and Vp2 for R,=R2=100 k2 - Find R, and R2 for VD1=VD2 R1 VD1 Hint: Is=L,+IRj= I,2+IR2 VD R2 VD2
- Two germanium diodes are connected in series and have a load resistance of 10 kQ and a forward supply voltage of 5 V. Calculate the voltage across the load resistor. * O 4.7 V O 4.4 V O 0.3 V 0.6 VFor the diode circuit shown below, indicate the ON/OFF condition for all the diodes given VA and VB values. Calculate Vout, Vx and all the currents that flow through the diodes. Summarize your result using a table. +4V VA VB VA OV OV 4V D₁ D₂ X 5ΚΩ D3 VB OV 4V 4V -2V 5ΚΩ VOUTIn the circuit below, Vi = 6sin (wt) and diodes are considered ideal diodes. Describe the working principle in detail by drawing the output signal. 10KO D2 10KO V. VaC D1 4V 2V
- A clipper circuit based on diodes are simple way to modify waveform in mechatronics. Assume that the two diodes shown in the circuit below are ideal diodes. If the input voltage in the circuit is a 1 kHz sinusoid with peak amplitude of 8V, sketch the Va.. (t) 10 kO 8V 10 kO Vin Vin(t) D2 Vout(t) RL Ims D1 6V -8V 4V Page | 1The anode of a diode is connected to one terminal of a 1-KΩ resistor. The other terminal of the resistor is connected to the ground and the negative terminal of a 12-volt DC source is also grounded. The three components are connected in series. How much is the load current with the ideal diode?4 1.0 k VS2 VSI 25 V 8 V Diodes D1 and D2 in the figure are assumed ideal, what is the current through the diodes? * D₁ B R www C