Q-2: A singie phase full-wave controlled reetifier is connected to RL load (R-15 ohm and 1-20mH). Vs-240 and 50 Hz supply When the firing angle is a=55. Deternine: A} the average voltage and average current in the load. B) The form factor and ripple factor. C) Peak inverse voltage of the thyristor.
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- What is the difference between a diode and rectifier?A single-phase half wave uncontrolled rectifier circuit is operating with a purely inductive load and a source voltage of 100 sin (277t) V. An ideal PMMC ammeter is connected in series with the inductive load reads 20 A. Calculate the distortion factor of the rectifier. Answer Choices: a. 0.866 b. 0.707 c. 0.577 d. 0.816A three phase full wave rectifier is shown below along with peak phase voltage Vm-169.7V. The load is purely resistive. The rectifier delivers Ipc = 100 A and the source frequency is 60 Hz. The DC output voltage is %3D VDc=280.7V and the output RMS voltage is equal to VRMS=280.93V. The efficiency, FF and RF are respectively equal to: Secondary D D D, R AD. Z D. D, Select one: O a. 99.83%, 100.08%, 4% O b. 99.83%, 55.08%, 4% O C. 99.83%, 100.08%, 16% O d. 87.83%, 100.08%, 4%
- Single phase diode bridge rectifier is connected to 220 V, 50 Hz supply to feed 5-ohm resistor in series with 10 mH inductor. Calculate and draw the load current during the first two periods of supply voltages waveform.92) For three - phase half-wave Controlleed rectifier Shown in he figure: 1. Derive a fomu la for mean load Voltage. 2. praw the wave form of vo, i,,i, iy and voltage across thyristor 1 (r.) assuming highly inductive load and d = 120Q5. For the following center tapped transformer, show the waveform across each half of the secondary winding and across Ri, when a 100 V peak sine wave is applied to the primarywinding. What is the PIV rating must the diode have? (Use constant voltage drop model for the Silicon diode) IN4001 Ry OV 10k) D IN4001
- In the given Full Wave Center tapped Rectifier circuit, a step down transformer gives an RMS voltage as 110v/11-0-11 V is used with R1-1 Kn. Assume diode as Germanium. a) Find Input Voltage D, Vin b) Find Peak Output Voltage. c) Find Average Output Voltage. d) Find Current through the load resistor. eeleeCIRCUIT DIAGRAM : D1 IÑ4001 AC Source RL 1K Q VOUT PROCEDURES : 1. Construct the half-wave rectifier circuit as shown. 2. Monitor the input voltage using the oscilloscope. Adjust the oscilloscope to show at least two complete cycles of the input signal. Draw the input waveform in Graph 1 and measure the peak-to-peak value. Record this in Table 1. Convert this value into RMS value using the formula: 3. 4. Vp-p Vp-p P-P VRMS 2.828Design a single-phase full wave bridge rectifier with input voltage of 100v and inductive load of 10ohm and 40mH a. Show the waveform relation between the I/P and O/P b. Calculate the average O/P voltage c. Calculate the rms current
- A full wave bridge rectifier is supplied from 230V, 50Hz and uses a transformer of turns ration 15:1. It uses load resistance of 50 ohms. Calculate load voltage and ripple voltage. Assume ideal diode and transformer. Assume ripple factor equals to 0.482. a.Load Voltage= 13.8 V; Ripple Voltage=6.652 V b.Load Voltage= 15.6 V; Ripple Voltage=7.611 V c.Load Voltage= 21.3 V; Ripple Voltage=8.410 V d.Load Voltage= 25.1 V; Ripple Voltage=10.442 VFor the full wave rectifier circuit shown in Figure 1, calculate: 1) The maximum current through the load. 2) The average current through the load. 3) The average voltage across the load. 4) The rms value of the current. 5) The rectification efficiency. Vms = 280V Vin RL= 12ks2 Vrms = 280V Figure 1Full wave rectifier normally produces A.unpredicted waveforms B.both polarities of input waveform to DC voltage C.positive phases of sinusoidal waveform D.pure sinusoidal waveform