Pure-breeding ancient varieties of chickpeas can be black, brown, green or red in color. A new tan colored chickpea was isolated and shown to be pure-breeding. To determine the genetic basis of color inheritance in chickpea many crosses were made between the various varieties. The results are shown in the table below. Cross F2 offspring ratio % red % brown F1 phenotype F2 offspring ratio Cross F1 phenotype black x brown all black % black % brown all red brown x red % green % black % black % red all green brown x tan all tan % tan % brown black x green black x red all green all green % green % red % green % tan % red ¼ pink % all black green x red black x tan all black % black % tan green x tan brown x green all green % green % brown red x tan all pink tan A. Analysis of the F2 offspring indicates that a single gene locus determines skin color in chickpea. Explain why? B. From the choices below, determine which mode of inheritance controls chickpea skin color in the ancient varieties? Complete dominance Incomplete dominance series Codominance Dominance series Lethal genes Recessive epistasis Dominant epistasis C. List the dominance relationship between the alleles of the ancient varieties of chickpea (black, brown, green, and red)

We have crossed true-breeding flies today. Wild type to mutant. Their phenotypes were wt and vg se. (Let’s not worry about males and females for now, just assume both genes are autosomal, which is normal in a Mendelian experiment). The results of a cross are phenotypes. I will be asking you for numbers or a ratio of phenotype numbers you expect to see in the offspring from this cross. To answer this, you’ll need to start with the genotypes of parents, then write their gametes, then write the offspring genotypes, then get the phenotypes based on them. Predict the results of this cross: In case both mutations are recessive; In case both mutations are dominant; In case vestigial wings are recessive and the sepia eyes are dominant.

Continuing his experiments, in Miles Morales' genome, the Goblin found similar genes, including one for invisibility which also seems to be dominant. To determine if they were linked to agility, the Goblin set up another cross and got the following results: Phenotype Agility and Invisibility Agility Invisibility No Powers Number of Progeny 121 52 55 125 What is the chi-square value for this?

Tomato Plants In tomato plants, round fruit (R) is dominant to oval fruit (r). Pure breeding plants with red and round fruit (FFRR) were crossed to pure breeding plants with yellow and oval fruit (ffrr). The red and round F1 progeny were then testcrossed to plants that were homozygous recessive for both genes (ffrr) with the following results: Phenotypes Number of Offspring Red and round 2 255 Red and oval 290 Yellow and round 310 Yellow and oval 2 145 Convert the expected phenotypic ratio from Part A into the expected probability for each of the four phenotypes and record them in the table below. Calculate the probability for each of the four phenotypes observed in the cross from the data presented at the beginning of the question by dividing the number of progeny in each class by the total number of progeny and record these in the table below. Probability = Number of Progeny in Phenotype Class ÷ Total Progeny  Compare the expected probabilities of each phenotype to…

An insect from a strain breeding for white eyes (RRww) was crossed to an insect from a strain breeding for cream eye (rrWW). The F1 all had red eyes. The F1s were intercrossed to produce F2 generation that consisted of 175 red eyed:81 white eyed. Provide the genetics of inheritance of this trait. Provide the genotypes for the F1s and F2s of this cross.

Tomato Plants In tomato plants, round fruit (R) is dominant to oval fruit (r). Pure breeding plants with red and round fruit (FFRR) were crossed to pure breeding plants with yellow and oval fruit (ffrr). The red and round F1 progeny were then testcrossed to plants that were homozygous recessive for both genes (ffrr) with the following results: Phenotypes Number of Offspring Red and round 2 255 Red and oval 290 Yellow and round 310 Yellow and oval 2 145   Convert the expected phenotypic ratio from Part A into the expected probability for each of the four phenotypes and record them in the table below. Calculate the probability for each of the four phenotypes observed in the cross from the data presented at the beginning of the question by dividing the number of progeny in each class by the total number of progeny and record these in the table below. Compare the expected probabilities of each phenotype to the observed probabilities. Are the gene for fruit colour and…

A variety of opium poppy with lacerate leaves was crossed with a variety that has normal leaves. All the F1 plants had lacerate leaves. Two F1 plants were then interbred to produce the F2. Of the F2 plants, 249 had lacerate leaves and 16 had normal leaves. What are the genotypes of the plants in the P (parental), F1, and F2 generations? How are lacerate leaves determined in the opium poppy? Note: You can use the symbols A and B to represent the two genes involved. (How do we know there are two?)

The image shows a pair of homologous chromosomes from a single parent before gamete production. M1 and M2 are maternal chromosomes, while P1 and P2 are paternal chromosomes. Two traits are shown: D represents seed color (D – green, d – yellow), while F represents flower color (F – purple, f – white). These two traits follow the patterns of basic Mendelian genetics. During crossing-over between the M2 F allele and the P1 f allele, a mutation occurred and the portion of P1 did not reattach to the chromosome. Which of the following explains what would happen to the proportion of white flowers in a population resulting from this mutation? A - There would be an increase in the proportion of white flowers because the f allele is distributed to more gametes. B - There would be a decrease in the proportion of white flowers because the f allele is not distributed to as many gametes. C - There would be an increase in the proportion of white flowers because the f allele would not be masked by the…

You have two true-breeding strains of coneflower. One strain has purple flowers and purple stems. The other strain has white flowers and green stems. When you cross these strains the F1 generation has purple flowers and purple stems. From this information you know that purple flowers is dominant to white flowers and that purple stems is dominant to green stems. In terms of genetic mechanisms, there could be two explanations: (1) flower color and stem color are each controlled by separate, independently segregating genes, and (2) there is one gene controlling both flower color and stem color. A. If explanation #1 is correct what would you see if the F1 generation were self-crossed to produce an F2 generation. Make up appropriate genetic symbols for this model and work out the cross to the F2 generation. B. If explanation #2 is correct what would you see if the F1 generation were self-crossed to produce an F2 generation. Make up appropriate genetic symbols for this model and work out the…

In mice, albinism (g) is recessive to grey coat colour (G). A grey mouse mated with an albino mouse. Over the course of several months, 38 pups were born. Out of 38 pups, 17 had a grey coat, and 21 were albino. Which of the following rows correctly identifies the parental and F1 generation genotypes? Select one: a. Parental Cross F1 Genotypes Gg x Gg GG, Gg and gg b. Parental Cross F1 Genotypes Gg x GG GG and Gg c. Parental Cross F1 Genotypes GG x gg Gg d. Parental Cross F1 Genotypes Gg x gg Gg and gg