PROBLEMS 8.1 An enzyme-catalysed reaction was found to be affected by two inhibitors A and B. The following results were obtained at fixed total enzyme concentration: Substrate conc" Initial velocity (absorbance units per minute) (mmol l-) Uninhibited With 1 mmol I-A With 1 mmol I-B 50 20 10 0.684 1.08 1.43 1.02 0.798 0.657 0.549 0.653 0.468 0.363 1.01 3.3 2.5 2.0 0.649 0.476 0.374 0.311 0.296 0.250 Comment on these results.

Question #2: Consider the following data for Cell G run in 1 L chemostat, with a feed containing 30 g/L substrate: Feedrate (ml/hr) (c) Calculate 27.5 24.2 22.1 18.8 Steady State Cell Mass Concentration (g/L) 12.0 14.7 15.8 16.7 Steady State Substrate Concentration (g/L) 10.0 5.56 (d) Using the calculated kinetic parameters, 3.70 (a) Determine the kinetic parameters for growth (b) At each dilution rate, calculate Yx/s. Is it constant with dilution rate and substrate concentration? 2.23 (i) the critical dilution rate, D. (ii) the dilution rate corresponding to maximum productivity, Dm (iii) the maximum cell productivity (cells/L/hr) (i) Generate a plot of X and S vs D for a feed concentration of 25 g/L. (ii) What is the critical dilution rate for this condition? (iii) What is the dilution rate corresponding to maximum productivity at this condition? (iv) What is the maximum cell productivity at this condition? (v) For a reactor operating at this maximum productivity, what would be the…

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Enzyme Kinetics question Enzyme used is 10uL of a 10 ng/uL solution  to a reaction mix in a final volume of 2.0 mL. (Enzyme used is 20kDa monomeric enzyme if matters) Based off lineweaver burk where 300 uM of inhibitor is used noninhibited formula is y= 4x + 0.1 (x axis is 1/S 1/mM) (y axis is 1/Vo sec/mM) inhibited formula is y = 4x + 1   I found Km as 1 mM for inhibited Vmax as 1mM/sec for inhibited   How would I find Kcat? How would I find Ki?