Problem 5Determine the magnitudes of the components of the forceacting along the axis AB of the wrench handle andperpendicular to it.Son Can toa300 mmxB9 = 128°(0,0,300)500 mmUF = COS 30%. Sin us i= -0.6124; + 0.6124jF = 80 N30545"+ Cos 30° cos 45j+ sin 30+ 0.5k(0,500, 300)UAB = -jCos 0 = UF • UAB = (-.61241 - 0.61245 +95 k) (-j)I How do we go from this= -0.6124to this?

Answered: Image /qna-images/answer/90a53ef4-c430-4bb2-b3bb-7c454344a772.jpg

Problem 5 Determine the magnitudes of the components of the force acting along the axis AB of the wrench handle and perpendicular to it. Son Can toa 300 mm x B Ⓒ = 128° (0,0,300) 500 mm UF = cos 30%. Sin 45 i = -0.6124; + 0.6124j F = 80 N 30 45" (0,500, 300) + Cos 30° cos 45j+ sin 30 + 0.5k UAB = -j Cos 0 = UF • UAB = (-.61241 +0.61245 +95 k) (-j) I How do we go from this = -0.6124 to this?

Problem 5 Determine the magnitudes of the components of the force acting along the axis AB of the wrench handle and perpendicular to it. Son Can toa 300 mm x B Ⓒ = 128° (0,0,300) 500 mm UF = cos 30%. Sin 45 i = -0.6124; + 0.6124j F = 80 N 30 45" (0,500, 300) + Cos 30° cos 45j+ sin 30 + 0.5k UAB = -j Cos 0 = UF • UAB = (-.61241 +0.61245 +95 k) (-j) I How do we go from this = -0.6124 to this?

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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