Answer 4 and 5 only PROBLEM 3: Consider the following cable system: cables AE, BE, CE, and DE intersect at point E. The coordinates of A, B, C and E are given:A (-2, 3, 2) mB (0, -2,5) mC (-3, 3, -1) mE (4, Y, 1) mProjection angles of D are 0 = 24°, and a = 10⁰, and distance L = 6 m. The length of cable AE is 4.8 m. Note the at D is on plane x-z.The forces in each cable are:EA = 122 KNEB = 111 KNEC = 95 KNED = 108 KN NBAYEJaLс8DXRequired: DO NOT INCLUDE (-) NEGATIVE SIGN IN ANY OF YOUR ANSWERS FOR ITEMS BELOW.1. Calculate the x-component of force EA =KN use 2 decimal places2. Calculate the y-component of the resultant =3. Calculate the magnitude of the resultant =4. Calculate the spatial angle of the resultant from x-axis =5. Calculate the spatial angle of the resultant from y-axis =KN use 2 decimal placesKN use 2 decimal placesuse 2 decimal placesuse 2 decimal places

To determine:- 4) Spatial angle of resultant from x-axis 5) Spatial angle of resultant from y-axis

PROBLEM 3: Consider the following cable system: cables AE, BE, CE, and DE intersect at point E. The coordinates of A, B, C and E are given: A (-2, 3, 2) m B (0, -2,5) m C (-3, 3, -1) m E (4, Y, 1) m Projection angles of D are 0 = 24°, and a = 10°, and distance L = 6 m. The length of cable AE is 4.8 m. Note the at D is on plane x-z. The forces in each cable are: EA = 122 KN EB = 111 KN EC = 95 KN ED = 108 KN

PROBLEM 3: Consider the following cable system: cables AE, BE, CE, and DE intersect at point E. The coordinates of A, B, C and E are given: A (-2, 3, 2) m B (0, -2,5) m C (-3, 3, -1) m E (4, Y, 1) m Projection angles of D are 0 = 24°, and a = 10°, and distance L = 6 m. The length of cable AE is 4.8 m. Note the at D is on plane x-z. The forces in each cable are: EA = 122 KN EB = 111 KN EC = 95 KN ED = 108 KN

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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