Problem 2: A sample of giant reed is shaped into a beam with a square cross section of 15.5 mm by 15.5 mm. Two supports placed 22.1 mm apart support the sample and a load is applied halfway between the support points in order to test the force required to fracture the sample. If ultimate tensile strength is 912 MPa, what would be the force F (newtons) required to cause failure?
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- The data in Table 1.5.3 were obtained from a tensile test of a metal specimen with a rectangular cross section of 0.2011in.2 in area and a gage length (the length over which the elongation is measured) of 2.000 inches. The specimen was not loaded to failure. a. Generate a table of stress and strain values. b. Plot these values and draw a best-fit line to obtain a stress-strain curve. c. Determine the modulus of elasticity from the slope of the linear portion of the curve. d. Estimate the value of the proportional limit. e. Use the 0.2 offset method to determine the yield stress.A tensile test was performed on a metal specimen having a circular cross section with a diameter 0. 510 inch. For each increment of load applied, the strain was directly determined by means of a strain gage attached to the specimen. The results are, shown in Table: 1.5.1. a. Prepare a table of stress and strain. b. Plot these data to obtain a stress-strain curve. Do not connect the data points; draw a best-fit straight line through them. c. Determine the modulus of elasticity as the slope of the best-fit line.2. A steel bar, whose cross section is 0.55 inch by 4.05 inches, was tested in tension. An axial load of P = 30,500 lb. produced a deformation of 0.105 inch over a gauge length of 2.05 inches and a decrease of 0.0075 inch in the 0.55-inch thickness of the bar. * Determine the lateral strain. Your answer Determine the axial strain. Your answer Determine the Poisson's rati v. Your answer Determine the decrease in the 4.05-in. cross-sectional dimension (in inches). * Your answer
- 2. A steel bar, whose cross section is 0.55 inch by 4.05 inches, was tested in tension. An axial load of P = 30,500 lb. produced a deformation of 0.105 inch over a gauge length of 2.05 inches and a decrease of 0.0075 inch in the 0.55-inch thickness of the bar. Determine the lateral strain. * Your answer Determine the axial strain. Your answer Determine the Poisson's ratio v. * Your answer Determine the decrease in the 4.05-in. cross-sectional dimension (in inches). * Your answerThe (G-E) diagram obtained in the tensile test performed on a metal sample with a diameter of 16 mm is as follows. The loads at points A, B and C and the elongation measured on l. 16 cm gauge length were determined as follows: B A B C Load (kgf) 4800 8400 7200 Elongation (mm) 0.192 28.8 38.4 a) Calculate the proportionality limit, modulus of elasticity, tensile strength, maximum uniform elongation, and contraction-elongation ratio of the metal. b) Since the measured diameter of the metal at break is 12 mm, find the constriction ratio and the actual stress at break.The information in the photo attached shows elastic properties of a human tibula bone. If you were to take a small cuboidal cross section of the tibula bone and apply the ultimate shear stress, what would be the resulting strain? (a) 1.0 % (b) 6.7 % (c) 10 % (d) 15 % (e) None of the above.
- A brass alloy rod having a cross sectional area of 0.24 in.2and a modulus of 16 * 106 psi is subjected to a tensile load. Plastic deformation was observed to begin at a load of 8,944 lb.a. Determine the maximum stress that can be applied without plastic deformation.b. If the maximum length to which a specimen may be stretched without causing plastic deformation is 3.28 in., what is the original specimen length?2. Shown below are pieces of unsaid material. They are combined and locked in each other and a force P is pulling each side. Assuming that the Shear stress for the material is 38 MPa, Determine the force P needed to fracture the materials in shear. 30 mm 30 mm 80 mm Section A-A1.5-7 The data shown in the table were obtained from a tensile test of a metal specimen with a rectangular cross section of 0.2 in.² in area and a gage length (the length over which the elongation is measured) of 2.000 inches. a. Generate a table of stress and strain values. b. Plot these values and draw a best-fit line to obtain a stress-strain curve. c. Determine the modulus of elasticity from the slope of the linear portion of the curve. Load (kips) 0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0 5.5 50 6.0 6.5 Elongation × 10³ (in.) 0 0.160 0.352 0.706 1.012 1.434 1.712 1.986 2.286 2.612 2.938 3.274 3.632 3.976 Load (kips) 7.0 7.5 8.0 8.5 9.0 9.5 10.0 10.5 11.0 11.5 12.0 12.5 13 Elongation × 10³ (in.) 4.386 4.640 4.988 5.432 5.862 6.362 7.304 8.072 9.044 11.310 14.120 20.044 29.106
- A tensile test was performed on a metal specimen having a circular cross section with a diameter of 1/2 inch. the gage lenght ( the lenght over which the elongation is measured ) is 2 inches. for a load 13.5 kips, the elongation was 4.66x10^-3 inches. if the load is assumed to be with in the linear elastic range of the material , determine the modulus of elasticity2.7 The following readings were recorded during a tensile test of a mild steel specimen 24 mm wide by 10 mm thick and with a gauge length of 200 mm. Force (kN) 16 32 48 64 68 72 76 79 Elongation (mm) 0,066 0,133 0,198 0,264 0,281 0,304 0,355 1,125 Force (kN) 76,8 83,7 103,8 111 112,8 108 96 Elongation (mm) 3,75 6,66 15,00 25,00 36,5 45,0 50,0 The test piece fractured at a 50-mm elongation. Plot the load-extension dia- gram using the following scales: 10 divisions on the x-axis = 5-mm exten- sion; 10 divisions on the y-axis = 10 kN. On the same graph paper and using the scale 10 divisions on x-axis = 0,5-mm extension, and 10 divisions on y-axis = 10 kN, replot the elastic portion of the graph. Using the graphs, determine the (a) modulus of elasticity for mild steel; (b) yield stress; (c) ultimate tensile stress; and (d) percentage elongation.A steel bar, whose cross section is 0.60 inch by 4.10 inches, was tested in tension. An axial load of P = 31,025 lb. produced a deformation of 0.115 inch over a gauge length of 2.10 inches and a decrease of 0.0080 inch in the 0.60-inch thickness of the bar. a. Determine the lateral strain. b. Determine the axial strain. c. Determine the Poisson’s ratio v. d. Determine the decrease in the 4.05-in. cross-sectional dimension (in inches).