
Structural Analysis
6th Edition
ISBN: 9781337630931
Author: KASSIMALI, Aslam.
Publisher: Cengage,
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Transcribed Image Text:PROBLEM 1
The results of a standard Proctor test are given in the following table.
Mass of moist
Moisture
soil in the
mold (kg)
Trial
Content (%)
1
1.47
10.0
2
1.83
12.5
3
2.02
15
1.95
17.5
5
1.73
20.0
1.69
22.5
After compaction the field unit weight of the soil is determined by means of the sand
cone method, the following are the results:
O Calibrated dry density of Ottawa sand = 1731 kg/m3
O Mass of Ottawa sand to fill the cone = 0.118 kg
O Mass of jar + cone + sand (before use) = 6.08 kg
O Mass of jar + cone + sand (after use)= 2.86 kg
O Mass of moist soil from the hole = 3.34 kg
O Moisture content of moist soil = 12.1%
%3D
Determine the maximum dry unit weight (kN/m3) of compaction and the optimum
moisture content. Given mold volume
943.3 cm3. Note: Check the maximum
dry unit weight of compaction and the optimum moisture content using the
graphical method and by means of the equation of the line.
b.
Determine the relative compaction in the field.
a.
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- The results of a standard Proctor test are given in the following table. Determine the maximum dry density (kg/m3) of compaction and the optimum moisture content. Volume of Proctor mold (cm3) Mass of wet soil in the mold (kg) Moisture content (%) 943.3 943.3 943.3 943.3 943.3 943.3 943.3 943.3 1.6 1.71 1.77 1.83 1.86 1.88 1.87 1.85 9.9 10.6 12.1 13.8 15.1 17.4 19.4 21.2arrow_forwardA liquid limit test on a clay was performed with the following results. The natural water content of the clay is 38% and plastic limit is 21%. Number of Blows 6 12 20 28 32 Water content (%) 52.5 47.1 42.3 38.6 37.5 What is the plasticity index of this clay? (Use Interpolation) Group of answer choices 15.74% 18.99% 18.85% 17.63% Please answer this asap for upvote. thanksarrow_forward
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