5. The results of a particle size analysis of a soil are given in the following table. The Atterberglimit tests yielded LL=62, PL = 20.Sieve Opening (mm)Percent Coarser by WeightSieve No.4.755.1102.0010.0200.850.42540.74070.284.890.5600.251000.15200Pan0.075100a) Draw the gradation curve for this soilb) Determine the uniformity coefficient and the coefficient of curvaturec) Classify the soil using USCS and ASSHTOd) Rate this soil as a subgrade for highway construction

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Answered: 5. The results of a particle size…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Q3- A sieve analysis on soil sample showed the following results; |Size, mm | 12 4.75 2.00 0.84 0.42 0.25 0.15 0.075 0.001 % finer 100 63 37 49 | 31 25 14 10 | 4 Plot the gradation curve and determine the weight of the gravel, sand, silt and clay if the total weight of the investigated soil mass is (1.3xN) kN. Show the plot and all calculation clearly. (N = 16 )
47.) The results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil A 4 4.760 89 6 2.380 70 10 2.000 63 20 0.840 55 40 0.420 31 60 0.250 20 100 0.149 18 200 0.074 4 LL 60 PL 40 Determine its classification using USCS. GW SP None of the above SW GP
43.) The results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil A 4 4.760 100 6 2.380 98 10 2.000 91 20 0.840 85 40 0.420 84 60 0.250 79 100 0.149 61 200 0.074 55 LL 60 PL 40 ML None of the above. CL CH MH
b. The following data was obtained from Sieve Analysis conducted at a Soil Lab. Using the data given in Table 02 determine: Table 02: Sieve analysis data of coarse- grained soil Sieve Opening (mm) 20 10 4.75 2.36 1.18 0.6 0.3 0.15 0.075 Pan Mass of Soil Retaining on each Sieve 5.23 20.23 180.23 360.23 280.13 70.13 50.23 17.23 10.13 8 1- Percentage of clay, silt, sand and Gravel in the soil sample 2- Uniformity coefficient and coefficient of curvature 3- Classify the soil according to BS soil classification system
42.) The results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil A 4 4.760 96 6 2.380 91 10 2.000 89 20 0.840 85 40 0.420 81 60 0.250 78 100 0.149 67 200 0.074 64 LL 40 PL 30 MH CH ML None of the above CL
The table shows the laboratory result of the sieve analysis of the sample. Determine the percent finer at size 0.74 and 0.004. Determine also the soil classification using AASHTO. Weight Retained 18.96 Size (mm) 0.25 0.149 0.074 0.052 0.02 33.18 45.03 54.51 42.66 0.01 11.85 0.004 0.001 Pan 4.74 4.74 21.33
2. For the given data, shows a sieve analysis of soil samples A,B, and C. Diameter Soil A Soil B Soil C Sieve No. (mm) %Passing %Passing %Passing # 4 4.760 100 90 100 a. Classify soil sample A using AASHTO Method #8 2.380 97 64 100 #10 2.000 92 54 98 b. Classify soil sample B using AASHTO Method c. Classify soil sample C using #20 0.840 87 34 92 # 40 0.420 53 22 84 #60 0.250 42 17 79 AASHTO Method #100 0.149 26 9. 70 # 200 0.074 17 4 63 LL 35 47 PL 20 24
5. The following information is obtained from a sieve analysis to determine the range of particle sizes in a granular soil sample. Sieve Size Sieve Opening (4.76) Percent Finer #4 4.76 96 #10 2.00 80 #20 0.84 51 #40 0.42 38 #60 0.25 25 #100 0.149 12 #200 0.074
a .l zain IQ elearning7.uokufa.edu.iq CHAPTER SEVEN STERSSES WITHIN SOIL MASS Н.W The detailed results of a standard Proctor test on a soil classified as CL-ML and group name silty clay with sand are shown in the table below. Determine the maximum dry unit weight and optimum water content. Diameter of mould = 4 in. Height of mould 4.584 in. Volume of mould = 1/30 ft3. Weight of mould, M = 4.45 lb. Unit weight data Water content data Weight of wet soil and mold (Ibs) Mass of can and wet soil (grams) Mass of can and dry soil (grams) Mass of can (grams) M. M. M. 7.32 114.92 111.48 7,57 163.12 155.08 7.68 190.43 178.64 46.20 193.13 178.24 46.50 7.65 188.77 171.58 46.10 II
dys.mu MSKÜ-LMS 016 ŞB: 1 ÖRGÜN Soil Mechanics Mühendislik Fakültesi Mac Atterberg limits of a soil sample are given: LL:55% and PL:25%. Give the name of the soil typle considering the chart given below? Remember PI=LL-PL 60 U-line PI - 0.9 (LL -8) 50 Z 40 CH or OH A-line PI0.73 (LL - 20) 30 CL OH 20 or OL MH CL- ML 10 ML& OL 10 20 30 40 50 60 70 80 90 100 Liquid limit (%) O a. CL or OL O b. CH OR OH O c. OH or ML O d. GL or ML O e. M ail E AR .ill lenovo Plasticity index (%)
The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Sieve No. Diameter Soil A 4 4.760 96 8 2.380 80 10 2.000 78 20 0.840 61 40 0.420 56 60 0.250 48 100 0.150 39 200 0.075 33 Characteristics of No. 40 Fraction LL 46 PL 31
Find the value of Cc of the following soil data sample Weight Percentage Cumulative Percentage Sieve Weight retained (gm) percentage retained (C) retained finer S.NO Select one: O a. 10.85 size (gm) N = (100 - C) {W,/ W,} x 100 1 75mm 100 O b. 7.36 63mm 100 O c. 18.34 50mm 100 O d. 2,96 4 37.5mm 454 22.7 22.7 77.30 5 28mm 285 14.25 36.95 63.05 6 20mm 207 10.35 47.30 52.70 7 14mm 318 15.90 63.20 36.80 8 10mm 206 10.30 73.50 26.50 6.3mm 118 5.90 79.40 20.60 10 5.0mm 102 5.10 84.50 15.50 11 3.35mm 64 3.20 87.70 12.30 12 2.0mm 88 4.40 92.10 7.90 13 1.18mm 35 1.75 93.85 6.15 14 600µ 42 2.10 95.15 4.85 15 300µ 33 1.65 97.60 2.40 16 150µ 18 0.90 98.50 1.50 17 75µ 22 1.10 99.6 0.40 18 Pan 8 0.40 100 In the pan we have = 100 W,= 2000 2 -99.6 = 0.4 % of material 2. 3.

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