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Please complete table by each gram (Linear Acceleration, Angular acceleration, Tension, Torque) with given data and formulas on the papers. There isn’t anything else that goes with this except for the stuff in the pictures

Please complete table by each gram (Linear Acceleration, Angular acceleration, Tension, Torque) with given data and formulas on the papers. There isn’t anything else that goes with this except for the stuff in the pictures

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Please complete table by each gram (Linear Acceleration, Angular acceleration, Tension, Torque) with given data and formulas on the papers. There isn’t anything else that goes with this except for the stuff in the pictures
Mass of (kg) Radius of 0.3924 kg (m) 0.00925m Shaft |Shaft Mass of Length of (kg) 0.0628 (m) .34m Threaded Threaded 0.1 (kg) Distance d (m) 1625m Mass of 0.1-kg mass Center ot from to Distance d (m) (kg) 8.0234ng Mass of Th.25cm 1425m from 4 Wing nuts
Transcribed Image Text:Mass of (kg) Radius of 0.3924 kg (m) 0.00925m Shaft |Shaft Mass of Length of (kg) 0.0628 (m) .34m Threaded Threaded 0.1 (kg) Distance d (m) 1625m Mass of 0.1-kg mass Center ot from to Distance d (m) (kg) 8.0234ng Mass of Th.25cm 1425m from 4 Wing nuts
Show your calculations for each moment and record the values in the provided table. Then compute the M= mass R= Radius PHY 1152 - Principles of Physics I Laboratory Mp=mass Thrad L= Lenglh dadsance Gom obet to Centr The equation for the rotational inertia of the 4 wing nuts is: I wingnuts = M all_wingnuts d" total moment inertia of the apparatus. 4- heign of tabu hop hofleer Iapparans = Ishaft + I phrended_rod +Io.g masses +I wingnuts Ishaft MR2 Chg-me) |(Ag.me) 2:(.11g)-d²yimit) 0.00528125 kg m² Mwingauts:de Mymt ) Threaded Rod1 0.0000 1678 O.00378012 Ky.mt ŽM Rodi? Io.1-kg masses I4 wing nuts 0.000166 (ngmi) O.00969605 kg.m2 (m) ITotal Add all H 4om Average Linear Mass Angular Acceleration Acceleration Tension a (rAd/s?) Torque Time Time (kg) (s) T (N) (m N) t (s) US th a (m/s?) H 53A1 |25.94 |25.68 37-88 0.050 (50 grams) 0.100 19.04 2.211 25.75 (100 grams) l17.39 13.55 l 1.64 13.65 18.365 www 10.94 M53 6424 0.150 (150 grams) 18.63 0.200 (200 grams) lu.18 2264 19.36 415 R.56 1429 .250 (250 grams) mlg-s T= T-R g-9.60 a= 2H R
Transcribed Image Text:Show your calculations for each moment and record the values in the provided table. Then compute the M= mass R= Radius PHY 1152 - Principles of Physics I Laboratory Mp=mass Thrad L= Lenglh dadsance Gom obet to Centr The equation for the rotational inertia of the 4 wing nuts is: I wingnuts = M all_wingnuts d" total moment inertia of the apparatus. 4- heign of tabu hop hofleer Iapparans = Ishaft + I phrended_rod +Io.g masses +I wingnuts Ishaft MR2 Chg-me) |(Ag.me) 2:(.11g)-d²yimit) 0.00528125 kg m² Mwingauts:de Mymt ) Threaded Rod1 0.0000 1678 O.00378012 Ky.mt ŽM Rodi? Io.1-kg masses I4 wing nuts 0.000166 (ngmi) O.00969605 kg.m2 (m) ITotal Add all H 4om Average Linear Mass Angular Acceleration Acceleration Tension a (rAd/s?) Torque Time Time (kg) (s) T (N) (m N) t (s) US th a (m/s?) H 53A1 |25.94 |25.68 37-88 0.050 (50 grams) 0.100 19.04 2.211 25.75 (100 grams) l17.39 13.55 l 1.64 13.65 18.365 www 10.94 M53 6424 0.150 (150 grams) 18.63 0.200 (200 grams) lu.18 2264 19.36 415 R.56 1429 .250 (250 grams) mlg-s T= T-R g-9.60 a= 2H R
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