A dentist using a dental drill brings it from rest to maximum operating speed of 360,000 rpm in 4.0 s. Assume that the drill accelerates at a constant rate during this time. (a) What is the angular acceleration of the drill in rev/s2? rev/s2 (b) Find the number of revolutions the drill bit makes during the 4.0 s time interval. rev

A dentist's drill starts from rest. After 3.40 s of constant angular acceleration it turns at a rate of 2.30 x 10 rev/min. (a) Find the drill's angular acceleration. rad/s2 (b) Determine the angle (in radians) through which the drill rotates during this period. rad

The figure shows a graph of the angular velocity of a rotating wheel as a function of time. Although not shown in the graph, the angular velocity continues to increase at the same rate until t = 8.9 s. What is the angular displacement of the wheel from 0 to 8.9 s? +6.0 7 +3.0- 3.0 Time (s) 1.0 5.0 -3.0- -6,아 -9.0k Number Units the tolerance is +/-2% Click if you would like to Show Work for this question: Open Show Work Angular velocity (rad/s)

A phonograph record accelerates from rest to 36.0 rpm in 4.53 s. (a) What is its angular acceleration in rad/s²? rad/s² (b) How many revolutions does it go through in the process? rev

A rotating wheel requires 6.00 s to rotate 28.0 revolutions. Its angular velocity at the end of the 6.00-s interval is 95.0 rad/s. What is the constant angular acceleration (in rad/s) of the wheel? rad/s2

4. A skater has a moment of inertia of 105.0 kg.m² when his arms are outstretched and a moment of inertia of 64.0 kg.m² when his arms are tucked in close to his chest. If he starts to spin at an angular speed of 80.0 rpm (revolutions per minute) with his arms outstretched, what will his angular speed be when they are tucked in? rpm

A dentist's drill starts from rest. After 3.50 s of constant angular acceleration it turns at a rate of 2.30 x 104 rev/min. (a) Find the drill's angular acceleration. rad/s2 (b) Determine the angle (in radians) through which the drill rotates during this period. rad

A grinding wheel 0.33 m in diameter rotates at 2900 rpm . a) What is the linear speed of a point on the edge of the grinding wheel? b) What is the acceleration of a point on the edge of the grinding wheel?

A rotating wheel requires 7.00 s to rotate 30.0 revolutions. Its angular velocity at the end of the 7.00-s interval is 99.0 rad/s. What is the constant angular acceleration (in rad/s) of the wheel? rad/s²

The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 3.0 rev/s in 11.0 s. At this point, the person doing the laundry opens the lid, and a safety switch turns off the washer. The tub slows to rest in 10.0 s. Through how many revolutions does the tub turn during this 21 s interval? Assume constant angular acceleration while it is starting and stopping. Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. rev Need Help? Read It