Phosphorus pentachloride decomposes at high temperatures. An equilibrium mixture at some temperature consists of 3.56 g of PCl5, 4.86 g of PCl3, and 3.59 g of Cl2 in a 1.00-L flask. a    Question Content AreaWhat will the concentration of PCl5 be when equilibrium is reestablished after addition of 1.31 g Cl2?

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Steam reforming of methane ( CH, ) produces "synthesis gas," a mixture of carbon monoxide gas and hydrogen gas, which Is the starting point for many 4 Important Industrial chemical syntheses. An Industrial chemist studying this reaction fills a 50.0 L tank with 3.7 mol of methane gas and 4.9 mol of water vapor, and when the mixture has come to equilibrium measures the amount of hydrogen gas to be 7.8 mol. Calculate the concentration equilibrium constant for the steam reforming of methane at the final temperature of the mixture. Round your answer to 2 significant digits. K =] x10 Check Explanation 2021 McGraw-Hill Education. All Rights Reserved. Terms of Use | Privacy Accessib 6. M9 hp

Consider the following equilibrium: CO (g) + Br2 (g) = COBr2 (g) K=12.0 at 85C Initially, the concentration of CO is 0.10M and Br2 is 0.40M. What are all the equilibrium concentrations?

If this reaction is taking place in a 1.0L container, and 1.5 mol of SO2 were added to the reaction, whatwill the new concentrations of all fours gases be when equilibrium is reestablished?

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Consider the reaction. PCI, (g) = PCI, (g) + Cl,(g) Ke = 0.0420 The concentrations of the products at equilibrium are [PC13] = 0.100 M and [Cl2] = 0.260 M. What is the concentration of the reactant, PCI5, at equilibrium? [PCI5] = M

Phosphorus pentachloride decomposes at higher temperatures. PC15 (8) PCl3(g) + Cl₂(g) An equilibrium mixture at some temperature consists of 5.81 g PCI, 208.23 g/mol 4.86 g PC3, 137.33 g/mol 3.59 g Cl₂, 70.91 g/mol in a 1.00-L flask. If you add 1.31 g of Cl₂, how will the equilibrium be affected and what will the concentration of PCI, be when equilibrium is reestablished? O shift left O shift right Ono shift will occur [PCI5] = mol/L