Peptide Concentration (M) 2.5 x 104 5.0 x 104 10.0 x 104 15.0 x 104 Velocity (M/min) 2.2 x 106 5.8 x 106 5.9 x 105 7.1 x 10-6
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- The hydrolysis of a phenylalanine-containing peptide is catalyzed by a-chymotrypsin with the following results. Calculate KM and Vmax for the reaction. What is the equation of the line?
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- Protein Solubility 3.5 5.5 5 5 0.068 0.028 Absorbance 0.098 Conc.(mg/ml) 0.195 0.130 0.044 0.9% 2.786% 9.429% 11.3: % solubility 4.179% The above table indicates the concentration of protein in the diluted supernatant and the supernatant before dilution at different pH. Dilution Factor 30 22.5 15 PH 7.5 1.5 4.5 5 0.027 3 0.042 Protein Solubility Versus pH 6.5 6 4.5 pH Value The above figure shows a plot of protein solubility versus pH. 50 7.5 7.5 50 0.032 0.053 8.5 50 0.054 0.100 21.429% 9 Please provide a brief discussion and explanation of the results. (using isoelectric point and net charge to explain)Solution Absorbance mg/ml aspirin Standard solution - 1.6 mg/mL A 0.638 0.08 mg/mL B 0.504 0.064 mg/mL C 0.376 0.048 mg/mL D 0.259 0.032 mg/mL E 0.126 0.016 mg/mL A = -log T where T = %T ÷ 100 Construct a callibration curve using the above data. Absorbance should be on the vertical axis and "mg/mL of acetylsalicylic acid" on the horizontal axis. The line should go through the origin. Using the data provided, the graph you have generated, and the procedure that was used to generate the solutions which were examined by spectroscopy, calculate the amount of acetylsalicylic acid per tablet. Commercial tablet 1 labelled as 100 mg enteric coated Absorbance = 0.16 Commercial tablet 2 labelled as 300 mg Absorbance = 0.45 Student prepared tablet from practical 5 Absorbance = 0.19 Using the data provided, the graph you have generated, and the procedure that was used…80-000 A7000 MN KANAMYCIN INJECTION, USP *1 g/3 mL (333 mg/mL) For IM or IV Use 3 mL Vial Rx only 10 Vials Using the label above, how many mL of Kanamycin must be administered to a patient in which the orders read 300 mg IM stat. Give your answer to 2 decimal places. Type mL in the units box. Your Answer: Sterie "Each mL contains lenamycin sulate equiralent to 333 mg kanamycia. 0.45% sodium bisulfite added as an antioxidant, buffered with sodium citrate (2.2 %). Adjusted to pH 4.5 with H,S0, Kanamycin Injection should not be phys ically mixed with other antibaderial agents Usual Dosage: Intramuscubr 7.5 ng/ig of bady weight at 12-hour intervals. Do not axceed 1.5 grams daily. See insert for IV and other uses Vial stoppers do not contain natural nubber latex. Store at 20 to 25 C (68 to 77 F) [see USP Contrdled Room Temperature]. Avoid freezing. APP APP Pharmaceuticals, LLC Schaumburg, IL G0173 63323-359-03 42650D LOT/EXP
- A 5% dextrose in 1/2 normal saline (D5 1/2 NS) solution is commonly administered to patients needing post-operative IV fluids. How could you prepare 500 mL of this solution? Dextrose is 5% (m/v) and the NaCl is 0.45% (m/v).Your 64YO 152lb, 5ft 8in female patient daignosed with advanced bladder cancerhas been prescribed ifosamide 1500mg/m2/day IV for 5 days. You calculate the BSA using the Mosteller method as being 1.82m2. Ifosfamide is available in 60mL vials containing 3g of drugs. How many mL will you administer each day?Arginine 12 14.0 VI 12.0F 12.0 10.0F IV 10.0 8.0 8.0 pH 6.0 6.0 4.0- 4.0 2.0 2.0 0.0 0.5 1.0 1.5 2.0 2.5 3.0 Eguiyslonts of Ou Below you can find the titration curve for arginine. The pH was monitored, and the results were plotted as shown in the graph. The key points in the titration are designated I to VI. For each of the statements (a) to (f), identify the appropriate key point in the titration. (pKa (СООН): 1.82, рКa (NH2): 8.99, pKa (R): 12.48) Average net charge of +2 predominates: The predominant species is +H3N-CH-((CH2)3-NH-C-NH2-NH2+)-COO- : Average net charge of arginine is 0: d. а. b. C. The pH is equal to the pka of the carboxyl group: Half of the backbone amino groups are protonated: Average net charge of arginine is +1/2: The carboxyl group has been completely titrated: е. f. g.
- pH 3.5 4.5 5.5 6.5 7.5 8.5 Absorbance 0.098 0.027 0.068 0.028 0.032 0.054 Concentration in diluted supernatant (mg/ml) 0.196 0.054 0.136 0.0056 0.0064 0.0108 Concentration in undiluted supernatant (mg/ml) 0.98 0.27 0.68 0.28 0.32 0.54 Formula for the amount (g) of soluble proteins in the soy flour extract: In 15 ml of soy flour extract (with 1/50 dilution), Soluble protein (g) = (C x V x F) / 1000 C = concentration (mg/ml); F = dilution factor; V = volume of solution (ml) Calculate the amount of soluble protein (in grams) in the soy flour extractpH 3.5 4.5 5.5 6.5 7.5 8.5 Absorbance 0.098 0.027 0.068 0.028 0.032 0.054 Concentration in diluted supernatant (mg/ml) 0.196 0.054 0.136 0.0056 0.0064 0.0108 Concentration in undiluted supernatant (mg/ml) 0.98 0.27 0.68 0.28 0.32 0.54 % solubility Formula for % solubility of proteins: % solubility = [(C x V x F) / (1000 x 35%)] x 100% C = concentration (mg/ml); F = dilution factor; V = volume of solution (ml) Calculate the % solubility of protein in the soy flour (Assume the soy flour contains 35% protein (w/w))pH 3.5 4.5 5.5 6.5 7.5 8.5 Absorbance 0.098 0.027 0.068 0.028 0.032 0.054 Concentration in diluted supernatant (mg/ml) 0.196 0.054 0.136 0.0056 0.0064 0.0108 Concentration in undiluted supernatant (mg/ml) 0.98 0.27 0.68 0.28 0.32 0.54 Formula for the amount (g) of soluble proteins in the soy flour extract: In 15 ml of soy flour extract (with 1/50 dilution), Soluble protein (g) = (C x V x F) / 1000 C = concentration (mg/ml); F = dilution factor; V = volume of solution (ml) Calculate the % solubility of protein in the soy flour (Assume the soy flour contains 35% protein (w/w))
- KCI for injection contains 40 mEq in 20 mL. An order requires 15 mEq, how many mL are needed?PRACTICE CONVERSION SHEET in scie 1. 5.5µg/mL 2. 750mL 3. 29μL 4. 1.55g 5. 0.045mg 6. 9.5mg/L 7. 850g 8. 3.5 x 10-8mL 9. 4.50 x 10³g/mL EXER 10. 9.5mg/L USIN 11. 4.50 x 107mg/mL= 12. 3.5 x 10 g/mL 13. 6.5 x 106mg/mL 14. 9.5 x 10ỏng 15. 3.5 x 10 μL ng/mL L mL _mg g/L ug μL µg/μL μg/μL g/L g/L µg/μL μg xxiiipH 7.54 PaCO2 28 mm Hg PaO2 45 mm Hg HCO3- 22 mEq/L. Please provide an IPAP, EPAP and FiO2 in ( values not words) Desired FiO2 = [PaO2 (desired) x FiO2 (known)] PaO2 (known)