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A student weighed out 0.150 g of protein powder and dissolved it in 100 mL of water (Solution 1). The student then diluted this solution by transferring 1 mL into a 25 mL flask and diluting with water (Solution 2). Finally, 1 mL of that solution was transferred to a test tube and combined with 4 mL Bradford reagent. The absorbance of the solution in the test tube was 0.187. Assuming that the best fit linear line of the standard curve was y = 0.04144 x + 0.01521 (μ g mL), calculate the percent protein by mass in the original protein powder.

S $24 CHEM 107-02 Exam 1: Ju x → A ALEKS - Julianna Graham - L x + www-awu.aleks.com/alekscgi/x/Isl.exe/10_u-lgNslkr7j8P3jH-IQUHIQg6bJxmeSyVpHOEB1plef9xyC5Ca9QlyULO-QdKyW_57MDR1Qpi-ijkNcyRp81fjPxufK3ckTA8G12 Td... O Acids and Bases Calculating the pH of a strong acid solution 0/3 Julianna A chemist dissolves 855. mg of pure perchloric acid in enough water to make up 250. mL of solution. Calculate the pH of the solution. Round your answer to 3 significant decimal places. 0 Explanation Check G MacBook Air olo 2024 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility

A student weighed out 0.150 g of protein powder and dissolved it in 100 mL of water (Solution 1). The student then diluted this solution by transferring 1 mL into a 25 mL flask and diluting with water (Solution 2). Finally, 1 mL of that solution was transferred to a test tube and combined with 4 mL Bradford reagent. The absorbance of the solution in the test tube was 0.11. Assuming that the best fit linear line of the standard curve was y = 0.04144 x + 0.01521 (μ g mL), calculate the percent protein by mass in the original protein powder.

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