Part 3: 09 Average absorbance prorhande Flask 8 Flask 9 Flask 10 Flask 11 Part 3: Q Flask 8 Flask 9 Flask 10 Flask Part 3: Q 10 Flask 8 Flask 9 Flask 10 Flask 11 Part 3 0.146 [Fe] -0.002mol/L 0.166 volume 5.00m 0.215 0.294 [FESCNmol/L) 4.59*10* 5.18*10* ✪ 6.6410 9.08*10 [Femol/L) 5.00*10* 5.00-10 Y=3362x-0.0083 R² = 0.9993 5.00-10 5.00*10* k 8 (9 – 11's values are in the spreadsheet) Ratio so 71% Molarity of Fe(NO3))3 = 0.2M Volume of Fe(NO3))3 = 5.00mL Moles of Fe = Molarity x volume(L) Fe 0.2M x 0.005L 1x 10 mole [SCN (mol/ 4 x 10-4 5x10-1 7*10* 1*10* Concentration of Fe³ =? mole of F Volume 8. Average absorbance for solution 8 (same for 9 - 11) Average absorbance for flask 8 = sum of all absorbances / number of readings 9. X = (0.145+0.147 +0.148) 1×10=0.002M 3 Using equation of calibration curve's line(slope) of best fit, the average absorbances of the unknown concentrations to determine (FeSCN-Jat equilibrium in solution 8: quation of line Y=3362x -0.0083 For 8 with an average absorbance of 0.146 0.146 = 3362X-0.0083 (0.146 +0.0083) 3362 0.0054 = 0.146 10, [Fe³] =25mlFe³x0.002mol/l-1 100ml -=4.59 x 10- -= 5.00 x 10-*mol/l-¹ 11. Place the results from calculations 9 and 10 into individual ICE tables. Calculate the equilibrium concentration of Feland SCN-in solutions 8 to 11. 12. a) Calculate K, for each solution using the results of calculations 9 and 11. Calculate the average value of K b) One published value of K, for the equilibrium system under consideration is 146 at room temperature (Journal of Chemical Education. 75. pp 90). Determine a percent error for your average calculated value of K, based on this literature value. TABLE 2-COMPOSITION OF SOLUTIONS REQUIRED FOR CALCULATION OF EQUILIBRIUM CONSTANT Volume of 0.002 mol L-¹ Volume of 0.002 mol L Flask # Fe(NO3)2(aq) / ml. KSCN[an) / ml W 7 (blank) 8 9 10 11 25.00 25.00 5.png 25.00 25.00 25.00 Ensure your Thermo Scientific Spectronic 200 spectrophotometer is powered on so that it is warmed up by the time you use it later in the procedure. Pipette 5.00 mL of 0.2 mol L4 Fe(NO)(aq) into a clean 500-mL volumetric flask. Fill the flask carefully to the calibration mark with 1.0 mol L-¹ HNO3(aq). stopper it, and mix well by inversion (25 times). Pour about 175 mL of the solution you just prepared into a clean, dry 250-mL beaker. The concentration of Fe(NO):(aq) in this solution is approximately 0.002 mol LA, Pipette the required volumes of 0.002 mol L4 Fe(NO3)(aq) and then 0.002 mol L4 KSCN(aq) into five clean. labelled 100-mL volumetric flasks. Before using the 25-mL pipette to deliver KSCN(aq) solution, remember to rinse it with this solution three times to remove any traces of Fe(NO1)(aq) that might be in it. Fill the flasks precisely to the calibration marks with deionized water. Remove any water droplets above the marks with a Kimwipe. Stopper the flask and mix each thoroughly by inverting it 25 times. Measure the absorbance of the solutions in flasks 8 through 11 as outlined in part 3 of the procedure. ... Q 0.00 20.00 25.00 35.00 KAN 50.00 61% Fe²(aq) + SCN- (aq) un FeSCN²(aq) The equilibrium constant K, is a ratio of the product of the concentrations of the products to that of the reactants, with the concentrations raised to the power of their stoichiometric coefficients. So, for the reaction under consideration In Part 1. solutions will be prepared with known concentrations of FeSCN³, a coloured species that can absorb light of a particular wavelength. The portion of incident light absorbed-called the absorbance-can be determined using an instrument called a spectrophotometer. The absorbance of the solutions will be plotted against [FeSCN³ resulting in a graph known as a calibration curve (even though the data is linear). By performing a linear regression analysis, it can be determined if the data conforms to Beer's Law. This law is used in spectroscopy to determine concentrations of species in solution. It can be expressed as A = ebe where A is the absorbance. e is the molar absorptivity of the absorbing species. b is the length of solution through which the light passes (also called the path length), and c is the concentration of the absorbing species. In Part 2. the absorbance of solutions with unknown concentrations of FeSCN will be measured. Using these measurements and the equation of the calibration curve line, the equilibrium concentration of FeSCN³(aq) in each solution can be determined. ICE tables are then used to find the equilibrium concentrations of all species present in Equation (2) and the equilibrium constant for Reaction (1) will be determined.

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
Question
em1.png
chem3.png
Part 3: Q9 Average absorbance
Flask 8
Flask 9
Flask 10
Flask 11
Part 3: Q9
Flask 8
Flask 9
Flask 10
Flask 11
Part 3: Q10
Flask 8
Flask 9
Flask 10
Flask 11
Q
Part 3
0.146
[Fe] -0.002mol/L
0.166
volume 5.00mL
0.215
0.294
[FESCN mol/L)
✪
4.59* 10
5.18*10*
6.64 x 10
9.08*10*
[Fe(mol/L)
5.00 x 10
5.00*10*
Y=3362x -0.0083 R¹ 0.9993
5.00 x 10
5.00*10*
(Amounts of flask 8 (9 - 11's values are in the spreadsheet)
1:1 Ratio so,
Molarity of Fe(NO3))3 = 0.2M
Volume of Fe(NO3))3 = 5.00mL
71%
Moles of Fe³= Molarity x volume(L)
Moles of Fe = 0.2M × 0.005L = 1× 10-³mole
68%
[SCN ](mol/
4 x 10-4
5 x 10-4
7*10*
1*10*
الخا
chem2.png
Concentration of Fe³
9,
X =
mole of Fe³1x10³ mole
Volume
0.0054
Ⓒ
8, Average absorbance for solution 8 (same for 9 - 11)
Average absorbance for flask 8 = sum of all absorbances / number of readings
(0.145 +0.147 +0.148)
3
Using equation
of calibration curve's line(slope) of best fit, the average absorbances of the
unknown concentrations to determine [FeSCN-]at equilibrium in solution 8:
quation of line Y=3362x-0.0083
For 8 with an average absorbance of 0.146
(0.146 +0.0083)
3362
0.146 = 3362X - 0.0083
= 0.146
10, [Fe] =25mlFe³ x 0.002mol/l-1
100ml
= 4.59 x 10-5
82%
0.002M
= 5.00 x 10-*mol/l-1
11. Place the results from calculations 9 and 10 into individual ICE tables. Calculate the equilibrium concentration of
Fe³+ and SCN-in solutions 8 to 11.
12. a) Calculate K, for each solution using the results of calculations 9 and 11. Calculate the average value of K
b) One published value of Ke for the equilibrium system under consideration is 146 at room temperature (Journal
of Chemical Education, 75. pp 90). Determine a percent error for your average calculated value of K, based on this
literature value.
W
6.png
7 (blank)
8
9
10
11
E
Q
TABLE 2-COMPOSITION OF SOLUTIONS REQUIRED FOR CALCULATION OF EQUILIBRIUM CONSTANT
Volume of 0.002 mol L-1 Volume of 0.002 mol L-1
Flask #
Fe(NO3)³(aq) / ml.
KSCN(aq) / ml
5.png
25.00
25.00
25.00
25.00
25.00
Ⓒ
71%
K₂
0.00
20.00
25.00
Ensure your Thermo Scientific Spectronic 200 spectrophotometer is powered on so that it is warmed up by the
time you use it later in the procedure.
Pipette 5.00 mL of 0.2 mol L-4 Fe(NO3)³(aq) into a clean 500-mL volumetric flask. Fill the flask carefully to the
calibration mark with 1.0 mol L-¹ HNO3(aq). stopper it, and mix well by inversion (25 times). Pour about 175 mL
of the solution you just prepared into a clean, dry 250-mL beaker. The concentration of Fe(NO3):(aq) in this
solution is approximately 0.002 mol L-4,
Pipette the required volumes of 0.002 mol L-¹ Fe(NO3)3(aq) and then 0.002 mol L-4 KSCN(aq) into five clean,
labelled 100-mL volumetric flasks. Before using the 25-mL pipette to deliver KSCN(aq) solution, remember to rinse
it with this solution three times to remove any traces of Fe(NO3)(aq) that might be in it.
Fill the flasks precisely to the calibration marks with deionized water. Remove any water droplets above the marks
with a Kimwipe. Stopper the flask and mix each thoroughly by inverting it 25 times.
Measure the absorbance of the solutions in flasks 8 through 11 as outlined in part 3 of the procedure.
[F+SCN3
[FON
35.00
50.00
Fe (aq) + SCN- (aq) FeSCN²(aq)
The equilibrium constant K, is a ratio of the product of the concentrations of the products to that of the
reactants, with the concentrations raised to the power of their stoichiometric coefficients. So, for the reaction under
consideration
61%
In Part 1. solutions will be prepared with known concentrations of FeSCN³, a coloured species that can absorb
light of a particular wavelength. The portion of incident light absorbed - called the absorbance - can be determined
using an instrument called a spectrophotometer. The absorbance of the solutions will be plotted against [FeSCN³].
resulting in a graph known as a calibration curve (even though the data is linear). By performing a linear regression
analysis, it can be determined if the data conforms to Beer's Law. This law is used in spectroscopy to determine
concentrations of species in solution. It can be expressed as
A = tbc
where A is the absorbance. e is the molar absorptivity of the absorbing species. b is the length of solution through which
the light passes (also called the path length), and c is the concentration of the absorbing species.
In Part 2, the absorbance of solutions with unknown concentrations of FeSCN2 will be measured. Using these
measurements and the equation of the calibration curve line, the equilibrium concentration of FeSCN²(aq) in each
solution can be determined. ICE tables are then used to find the equilibrium concentrations of all species present in
Equation (2) and the equilibrium constant for Reaction (1) will be determined.
Transcribed Image Text:em1.png chem3.png Part 3: Q9 Average absorbance Flask 8 Flask 9 Flask 10 Flask 11 Part 3: Q9 Flask 8 Flask 9 Flask 10 Flask 11 Part 3: Q10 Flask 8 Flask 9 Flask 10 Flask 11 Q Part 3 0.146 [Fe] -0.002mol/L 0.166 volume 5.00mL 0.215 0.294 [FESCN mol/L) ✪ 4.59* 10 5.18*10* 6.64 x 10 9.08*10* [Fe(mol/L) 5.00 x 10 5.00*10* Y=3362x -0.0083 R¹ 0.9993 5.00 x 10 5.00*10* (Amounts of flask 8 (9 - 11's values are in the spreadsheet) 1:1 Ratio so, Molarity of Fe(NO3))3 = 0.2M Volume of Fe(NO3))3 = 5.00mL 71% Moles of Fe³= Molarity x volume(L) Moles of Fe = 0.2M × 0.005L = 1× 10-³mole 68% [SCN ](mol/ 4 x 10-4 5 x 10-4 7*10* 1*10* الخا chem2.png Concentration of Fe³ 9, X = mole of Fe³1x10³ mole Volume 0.0054 Ⓒ 8, Average absorbance for solution 8 (same for 9 - 11) Average absorbance for flask 8 = sum of all absorbances / number of readings (0.145 +0.147 +0.148) 3 Using equation of calibration curve's line(slope) of best fit, the average absorbances of the unknown concentrations to determine [FeSCN-]at equilibrium in solution 8: quation of line Y=3362x-0.0083 For 8 with an average absorbance of 0.146 (0.146 +0.0083) 3362 0.146 = 3362X - 0.0083 = 0.146 10, [Fe] =25mlFe³ x 0.002mol/l-1 100ml = 4.59 x 10-5 82% 0.002M = 5.00 x 10-*mol/l-1 11. Place the results from calculations 9 and 10 into individual ICE tables. Calculate the equilibrium concentration of Fe³+ and SCN-in solutions 8 to 11. 12. a) Calculate K, for each solution using the results of calculations 9 and 11. Calculate the average value of K b) One published value of Ke for the equilibrium system under consideration is 146 at room temperature (Journal of Chemical Education, 75. pp 90). Determine a percent error for your average calculated value of K, based on this literature value. W 6.png 7 (blank) 8 9 10 11 E Q TABLE 2-COMPOSITION OF SOLUTIONS REQUIRED FOR CALCULATION OF EQUILIBRIUM CONSTANT Volume of 0.002 mol L-1 Volume of 0.002 mol L-1 Flask # Fe(NO3)³(aq) / ml. KSCN(aq) / ml 5.png 25.00 25.00 25.00 25.00 25.00 Ⓒ 71% K₂ 0.00 20.00 25.00 Ensure your Thermo Scientific Spectronic 200 spectrophotometer is powered on so that it is warmed up by the time you use it later in the procedure. Pipette 5.00 mL of 0.2 mol L-4 Fe(NO3)³(aq) into a clean 500-mL volumetric flask. Fill the flask carefully to the calibration mark with 1.0 mol L-¹ HNO3(aq). stopper it, and mix well by inversion (25 times). Pour about 175 mL of the solution you just prepared into a clean, dry 250-mL beaker. The concentration of Fe(NO3):(aq) in this solution is approximately 0.002 mol L-4, Pipette the required volumes of 0.002 mol L-¹ Fe(NO3)3(aq) and then 0.002 mol L-4 KSCN(aq) into five clean, labelled 100-mL volumetric flasks. Before using the 25-mL pipette to deliver KSCN(aq) solution, remember to rinse it with this solution three times to remove any traces of Fe(NO3)(aq) that might be in it. Fill the flasks precisely to the calibration marks with deionized water. Remove any water droplets above the marks with a Kimwipe. Stopper the flask and mix each thoroughly by inverting it 25 times. Measure the absorbance of the solutions in flasks 8 through 11 as outlined in part 3 of the procedure. [F+SCN3 [FON 35.00 50.00 Fe (aq) + SCN- (aq) FeSCN²(aq) The equilibrium constant K, is a ratio of the product of the concentrations of the products to that of the reactants, with the concentrations raised to the power of their stoichiometric coefficients. So, for the reaction under consideration 61% In Part 1. solutions will be prepared with known concentrations of FeSCN³, a coloured species that can absorb light of a particular wavelength. The portion of incident light absorbed - called the absorbance - can be determined using an instrument called a spectrophotometer. The absorbance of the solutions will be plotted against [FeSCN³]. resulting in a graph known as a calibration curve (even though the data is linear). By performing a linear regression analysis, it can be determined if the data conforms to Beer's Law. This law is used in spectroscopy to determine concentrations of species in solution. It can be expressed as A = tbc where A is the absorbance. e is the molar absorptivity of the absorbing species. b is the length of solution through which the light passes (also called the path length), and c is the concentration of the absorbing species. In Part 2, the absorbance of solutions with unknown concentrations of FeSCN2 will be measured. Using these measurements and the equation of the calibration curve line, the equilibrium concentration of FeSCN²(aq) in each solution can be determined. ICE tables are then used to find the equilibrium concentrations of all species present in Equation (2) and the equilibrium constant for Reaction (1) will be determined.
Expert Solution
steps

Step by step

Solved in 4 steps

Blurred answer
Knowledge Booster
UV and Visible Spectroscopy
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY