Part 2. PCR 1) In one color, write out the forward primer (5’ GATAC 3’) in the correct position relative to the given template DNA sequence.  In a second color, act as the polymerase and fill in the rest of the new strand of DNA       Primer/New Strand Template DNA:               3’ TAGCTATGCGGACCTCATGCATTAGAGTAG 5’

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Chapter15: Studying And Manipulating Genomes
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Problem 16SQ: Match the method with the appropriate enzyme. _____ PCR a. Taq polymerase _____ cutting DNA b. DNA...
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Part 2. PCR

1) In one color, write out the forward primer (5’ GATAC 3’) in the correct position relative to the given template DNA sequence.  In a second color, act as the polymerase and fill in the rest of the new strand of DNA

 

 

 

Primer/New Strand

Template DNA:               3’ TAGCTATGCGGACCTCATGCATTAGAGTAG 5’

 

Part 3. Restriction Enzymes

1) Consider the sequence of DNA given below and answer the following questions

 

5’ ATTGAGGATCCGTAATGTGTCCTGATCACGCTCCACG 3’

3’ TAACTCCTAGGCATTACACAGGACTAGTGCGAGGTGC 5’

 

  1. a) You cut the sequence of DNA shown above using BamHI (see table 19.1 from the text). How many fragments of DNA would you expect to result from this restriction digest?

 

 

  1. b) If you cut the sequence of DNA shown above using BclI (recognition sequence = 5’ TGATCA 3’, enzyme cuts after the first T) instead of BamHI how many fragments do you expect?

 

2) For each given sequence/restriction enzyme pair, determine how many pieces of DNA would result form the digest and indicate whether those pieces would have blunt or sticky ends. NOTE: in the given recognition sites, the dash represents where the cut is made.

a)  HpaI, recognizes 5’ GTT – AAC 3’

 

5’ GGATGTTAACAATCTCTACGGGTTAACACCCTTGGGTTAACATCCGCGG 3’

3’ CCTACAATTGTTAGAGATGCCCAATTGTGGGAACCCAATTGTAGGCGCC 5’

 

Number of fragments of DNA:                      Type of end:

 

  1. b) EcoRI, recognizes 5’ G – AATTC 3’

 

5’ ACGACGTATTAGAATTCTTATCCGCCGCCGGAATTCTCATCA 3’

3’ TGCTGCATAATCTTAAGAATAGGCGGCGGCCTTAAGAGTAGT 5’

 

Number of fragments of DNA:                      Type of end:

 

  1. c) HpaI, recognizes 5’ GTT – AAC 3’ AND SspI, recognizes 5’ AAT – ATT 3’

 

5’ AGTTAACCGACAATATTGTATTATATCCGCCGCCGTCGTTAACATCA 3’

3’ TCAATTGGCTGTTATAACATAATATAGGCGGCGGCAGCAATTGTAGT 5’

 

Number of fragments of DNA:                      Type of end:

 

  1. d) HindII, recognizes 5’ GTC – GAC 3’, AND HaeIII, recognizes 5’ CC – GG 3’, AND BamHI, recognizes 5’ CCTAG – G 3’

 

5’ ACGCCGGACGTACCTAGGTTTAGTCGACTCCGCCGCCCCTAGGGTCATCA 3’

3’ TGCGGCCTGCATGGATCCAAATCAGCTGAGGCGGCGGGATCCCAGTAGT 5’

 

Number of fragments of DNA:                      Type of end:

 

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