PA PL ¹½/2 x 6 3″ 2 PL ¾/16 x 3 P

Q: The welded girder shown in the accompanying illustration has an external shear VD = 300 k and VL =…

A: VD=300 kVL=350 k

Q: Two plates of Steel A72 Gr 50 are connected with each as shown in Figure 5. E70XX Electrodes were…

A: Given:- Steel A72Gr500 fillet weld=7/16 To find:- design strength by LRFD and ASD

Q: For the connection shown, the load is 70% live load and 30% dead load. What weld size is needed if…

A: Solution: Given: LL = 70% x 8 = 5.6 kips DL = 30 % x 8 = 2.4 kips A 36 steel Assume t = 1/2 in E70…

Q: PROBLEM 9.9 9.10 In the bolted connection of Figure 9.12, assume that the bolts are in. in diameter…

A:

Q: app 3.0. Investigate all limit states. The tension m gusset plate is A36. The weld is a 1/8-inch fil…

A:

Q: Determine the total LFRD design strength and the total ASD allowable strength of the 5/16 – in E70…

A: We will solve this question in step no. 2

Q: 6. Design the tension plate attached to the wide-flange (W) section as well the welds, assuming the…

A: Step 1:

Q: o normal temperatures but wet in-service conditions. Assume =0.95 and the geometry factor is CA=1.…

A: 1 Area of the plate Ag     Ag = 4×10 = 40 in2for A36 grade steel   fy =36000…

Q: Determine the design tensile strength, Pn, of a 3/8 x 6 plate tension member shown in the figure.…

A: 38×6 plateFu = Ultimate strength = 58 ksiFy = Yield strength = 36 ksi

Q: Fillet Welds Oriented Longitudinally and Transversely to the Load The two 4 x 4x3/8 angles shown in…

A:

Q: Compute the maximum acceptable tensile SERVICE LOAD that may act on a single tee section that is…

A: Given- Properties of WT- 12×38Ag=11.2 in2y'=3.0 inbf=8.99 inA992 steel-fy=50 ksiFu=65 ksiLL=3DL

Q: The connection of the drawbar and tie plate combination given below will be made by welding with two…

A: Welded connections: The point at which two or more pieces of metal are joined together is known as…

Q: Two steel plates are lap jointed in a workshop using 6 mm thick fillet weld as shown in the figure…

A: Two steel plates are lap jointed in a workshop using 6 mm thick fillet weld The ultimate strength of…

Q: 7. Design the welds indicated to develop the full strength of the angles and minimize eccentricity.…

A: Problem Statement:Design the welds indicated to develop the full strength of the angles and minimize…

Q: A hanger is suspended from a plate that is welded to a wide flange beam as shown. The plate requires…

A: Hi! Thank you for the question As per the honor code, We’ll answer the first question since the…

Q: Two 3/16" E70 fillet welds of 15 in. Iong are subjected to a load P. Using LRFD, compute the…

A: Answer (a) Minimum weld length requirement Minimum weld length may not be less than 4 times the…

Q: The details of an end bearing stiffener are shown in Figure . The stiffener plates are 9⁄16-inch…

A: A572 Grade 50:Fy=50 ksi   Calculating the bearing strength: Apb=6-0.5×916×4=12.38 in2Rn=1.8 Fy Apb…

Q: Determine the design strength for C-shaped welds. USE E70 electrodes and 5/16" weld. 2011d

A: Given, E70 electrodes Weld thickness (w) = 5/16"

Q: Material Strengths: Fy= 248 MPa, Fu= 400 MPa Method: Use ASD. A single angle L203X152X19 is welded…

A:

Q: The connection is shown in Fig. 3. Two cover plates are applied to connect the steel plates by…

A: Given data:- The given size of fillet weld hf = 10 mm The tensile strength of steel plate f = 215…

Q: can be decided as the Class b section. Determine the design value of axial load capacity.

A:

Q: A lap welded joint of A36 steel plates must hold a tensile load. The lower plate is .5 inches thick…

A: Lower plate tensile load = 0.5 inch thickWidth of lower plate = 7.7 inch wideUpper plate tensile…

Q: Q1 Two 3/16" E70 fillet welds of 15 in. long are subjected to a load P. Using LRFD, compute the…

A: Answer We are given  size of weld (w)= 3/16 in Length of weld L = 15 in E 70 electrode

Q: Q3: Design 5/16-in SMAW fillet welds for the plate shown in figure below if A36 steel and E70…

A: Given data : design a 5/16 -in SMAW fillet welds for the plate ( for the given figure)  use A36…

Q: An I-section bracket is connected to the column as shown. The size of weld is 6 mm on web and 10 mm…

A:

Q: A channel C250x37 mm section is welded to a 9 mm gusset plate. Welding is not permitted on the back…

A: Slot Weld : Slot weld is used to attach flat plates using one or more holes in the top part. To fuse…

Q: The equivalent stress for welding in given bracket connections would be if t = 5mm e i.e. Effective…

A: Effective throat thickness of weld te=5 mm,Fe410 steel & shop welding case,To Find-The value of…

Q: Compute the maximum acceptable tensile SERVICE LOAD that may act on a single tee section that is…

A: Answer In order to calculate the minimum acceptable tensile service load we need to first find the…

Q: 5-5: For the welded 1"x8" flat plate tension member shown, determine the design tensile capacity…

A: “Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: Use an elastic analysis and determine the maximum load in the weld (in kips per inch of length).

A: Given:- The magnitude of the load = 15 k To determine:- The maximum load in the weld (in kips per…

Q: and L = ( 6.5 + 1.5b) inches. Determine the design strength oR, for the concentrically loaded weld…

A: Fillet weld: - It is defined as the process in which two metal pieces join together perpendicularly…

Q: For the tension member shown, compute the following. a. The tensile design strength. b. The…

A:

Q: what is the available strength of the connection?

A:

Q: Design a double angle tension member that is fillet welded to a gusset plate. Assume that the angles…

A: 1).Design and select a trial tension member  See Table 5-8 on page 5-49 of the AISC manual. - Select…

Q: Determine the required diameter of a plug weld using E60 electrodes on A-36 steel to develop the…

A: We have to determine the value of required diameter of a plug weld using E60 electrodes on A36 steel…

Q: 5. Select a pair of channels and design the fillet welds using SMAW process. The loading is 85% live…

A: Step 1:For A36 SteelGiven:Live Load (LL) = 170 kipsDead Load (DL) = 30 kipsDesign Load…

Q: Problem 3. An un-equal leg angle L8x4x½ made of ASTM A242 steel (Fy = 50 ksi, Fu = 70 ksi) is used…

A: Unequal leg angle, L 8 x 4 x 1/2" of ASTM 242 steel, Fy=50 ksi , Fu= 70ksi To Find: (a) Factored…

Q: In an industrial shed an edge support consisting of 2L-110 x 110 mm is to be connected to a 16 mm…

A:

Q: Determine the size of the weld using E60 electrode. Dead Load = 38 kip and LL = 95 kips (Service…

A: Nominal strength of  weld is given by Rn = fnw*Anw fnw = Nominal weld strength fnw = 0.6*fEXX  fnw =…

Q: ickness (S=5/8") with "A36" member steel (fy=36 ksi & fu=58 ksi).

A:

Q: A C130x10 tension member is welded to a plate as shown in the figure. The channel is of Grade 350W…

A:

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.