Determine the design tensile strength, Pn, of a 3/8 x 6 plate tension member shown in the figure. A36 steel with Fu = 58 ksi is used. The connection consists of two longitudinal welds shown. Use the AISC specification to calculate the value of U, if necessary. Neglect block shear. %3D Longitudinal weld PL38X6 PL 6 in
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- What is the safe load "P" that can be transmitted by the fillet-weld joint shown in figure below if allowable shear stress in the fillet weld is 108 MPa and F.O.S. for load is 1.5? P4 www 60mm 777 50mm 8mm PConsidering the following steel connection. The plates in Pink are 9mm steel plates. The middle plate (Yellow) is 18mm thick. The width of the plate is 100mm. The maximum allowable tension stresses on any of the plates is 100Mpa in Gross Area Yielding and 150 Mpa for Net Area or Tension Rupture. The bolts used are 8mm in diameter, the holes are 10mm in diameter, no need to add 1.6mm. The bolts allow a maximum of 280 Mpa of shear. Determine the maximum allowable "P" of the connection in kN.Determine the design tensile strength of plate (200x8 mm) connected to 10-mm thick gusset using 20 mm bolts as shown in the figure, if the yield and the ultimate stress of the steel used are 250 MPa and 410 MPa, respectively. Add 1mm around the bolt for the hole. Use LRFD method. Plate 8-mm thick 2 3 40+ 30 301 T 200 mm Gusset 10-mm thick 3af 30 2_3 *40 40+ 50,54 +40
- Topic:Welded Connection - Civil Engineering -Steel Design *Use latest NSCP/NSCP 2015 formula to solve this problem *Please use hand written to solve this problem A tension member consists of a double angle section with long legs back to back. The angles are attached to a 9.5 mm thick gusset plate. Fu = 400 MPa Fy = 248 MPa for angular section. Fw = 480 MPa for 8 mm fillet weld. Reduction factor U = 0.80 Prop. of One Angle L 125m x 75m x 12.7 m A= 2419 mm2 y=44.45 mm Questions: a) Compute the design strength capacity of one angle. b) Compute the base metal shear strength (gusset plate) per unit length. c) Compute the length L1 and L2.Assume that the gusset plate and welds are satisfied. A gap allowance of 1/16 inch is to be considered to fit the gusset plate in the HSS. The steel used in the tension member is ASTM A500 Grade C HSS 6 x 0.5 with a length of 30 feet. a.) Find the shear lag factor b.) Find the Effective net area (Ae) c.) Solve for the tensile strenngth 16-inch-long fillet weld HSS 6 x 0.5 1/2 in. thick gusset plate 17 inch longA channel C250x37 mm section is welded to a 9 mm gusset plate. Welding is not permitted on the back of the channel. All steel is A36 with Fy=250 MPa and Fu=400 MPa. Use E70electrodes having and Fu=485 MPa (SMAW) process. The maximum length of lap is 250mm. The size of fillet weld is 8mm. Assume the width of slot weld is 22 mm. Size of slot weld is 13mm Properties of C250x37 A = 4750 mm2 tw = 13.0 mm2 d = 254 mm a. Determine the force resisted by the slot weld in kN, when the full tensile capacity is 712.5 KN (from the gross yielding capacity using ASD) Hint: Full tensile Capacity = Force Resisted by Fillet and Slot Weld Round your answer to 3 decimal places.
- The tension member is a PL 1⁄2 × 6. It is connected to a 3⁄8-inch-thick gusset plate with 7⁄8-inch-diameter bolts. Both components are of A242 steel. Note: A242 Fu = 70ksi dh = db + 1/16’’ Use: Consider deformation at the bolt hole what is the: minimum spacing as per AISC code provisions maximum spacing as per AISC code provisions minimum edge distance as per AISC code provisions maximum edge distance as per AISC code provisionsQ1:A: The Ix6 in. plate shown in Figure below is connected to a lx10 in. plate with longitudinal fillet welds to transfer a tensile load. Determine the LRFD design tensile strength of the member if F, = 50 ksi and Fu = 65 ksi. PLI X 10 in PL1 x 6 in P P w= 6 in Longitudinal fillet welds L=8 inA PL 38 X 6 tension member is welded to a gusset plate as shown. The steel is A36 (Fy = 36ksi, Fu = 58ksi). a. The design strength, Pu based on gross area b. The design strength, Pu based on effective area PL % x 6 3/8" 6" Cross Sectional area of PL3/8x6 a) Blank 1 b) Blank 2 Blank 1 Add your answer Blank 2 Add your answer
- The plate with dimension 18 mm x 400 mm (thickness by width) is to be connected to a gusset plate using 6-Ø24 mm bolts in arrange in 3 row (2 each row) along the x-axis. The plate is to be design for tension. Using A36 steel and assuming Ae= An. Use NSCP 2015. a. Compute the design strength considering yielding and tensile rupture. (LRFD) b. Compute the allowable strength considering yielding and tensile rupture. (ASD)A tie member of a roof truss consists of 21SA 100 x 75 x 8 mm. The angles are connected by fillet weld as shown in figure on either side of a 10 mm gusset plate and the member is subjected to a factored pull of 450 kN. Take size of weld as 6 mm and connections are made in workshop. [Use Fe410 grade of steel] 75 m L. C. = 31mm 16A (100 x 75 x 8) mm Choose the nearest correct statements: L1 = 390.5 mm L1 = 195.25 mm Correct Option L2 = 87.75 mm Correct Option L2 = 175.5 mmSituation 5. The angular section shown below is welded to a 12 mm gusset plate. Both materials are A36 steel with Fy = 250 MPa. The allowable tensile stress is 0.6Fy. The weld is E80 Electrode and 12 mm thickness. INNOVATIONS Properties of L 150x90x12: y = 50 shear stress of weld = 0.3Fu A = 2750 Allowable REVIEW INNOVATIE a K ➜ www A. 234 KN B. 349 KN b 13. What is the value of P without exceeding the allowable tensile the angle? C. 382 kN p. 413 kN 14. Find required length of the weld based on shear? A. 280 mm C. 300 mm D. 380 mm B. 320 mm 15. Find the required value of a? A. 108 mm B. 97.9 mm D. 185 mm NEW INNOVATIONS REVIEW INNOVATIOf REVIEW NEW INNOVATIONS