7. Design the welds indicated to develop the full strength of the angles and minimize eccentricity. Assume service load is 20% dead load and 80% live load. Use the SAW welding process. a- Use A36 steel b- Use A572 Grade 50 steel 2-15×3×

If the design tensile strength Phi Pn of a tension member is controlled by rupture failure. Which of the following actions will NOT increase its capacity?   using welds instead of bolts using larger cross section of the member increasing strength of steel using thicker gusset plate

See the image. Two steel plates are welded together. The thickness of the bottom plate is 10mm and the thickness of the top plate is 8mm. What is the maximum and minimum sizes of the weld.

Design calculations for a certain 1/2 in fillet weld show that the effective length required is 7 in. If allowance is made for defects at the ends of the weld, the actual length should be NOT less than  A. 9 in. B. 8 1/2 in C.8 in. D. 7 1/2 in.

A tension member splice is made with 14-inch E70 fillet welds as shown in Figure 5. Each side of the splice is welded as shown. All steel is A36. Determine the maximum service load, P, that can be applied if the live load to dead load ratio is 1.5. Note: Assume that the base metal shear strength is adequate (check the yielding strength for the gross area, fracture strength for the effective net area, weld strength and block shear strength). PL 5/8x8 4 in. Figure 5 2 PL 7/16x4