p(1.28

Test the hypothesis using the P-value approach. Be sure to verify the requirements of the test. Ho: p=0.6 versus H₁: p > 0.6 n = 200; x = 135; α = 0.05 Click here to view page 1 of the table. Click here to view page 2 of the table. Calculate the test statistic, Zo. Zo = (Round to two decimal places as needed.)

The population mean annual salary for environmental compliance specialists μ = $63,500. A random sample of 35 specialists is drawn from this population. Assume σ = 6100 (adopted from salary.com). What is the probability that the mean annual salary of the sample is less than $60,000? Interpret the results and show all work.

Q2) The following is the frequency distribution of temperature of some certain days: Temperature: 0-10 Frequency: a) b) c) 10-20 20 -30 30-40 40-50 6 3 7 2 Calculate mean and SD of the above frequency distribution. Write the formula of mean and SD. Write a summary based on these two measures.

The Normal distribution is an example of a Distribution. Discrete Continuous Neither

Find the indicated z score. The graph depicts the standard normal distribution with mean 0 and standard deviation 1. The indicated z score is ​(Round to two decimal places as​ needed.)

using the standard normal distribution what is the correct value for p(z>-1.85)

Using the standard normal distribution, find the two z-scores that that form the middle shaded region. The shaded region is symmetric about z=0z=0. Round your z-scores to two decimal places. -4 -3 -2 -1 0 1 2 3 4z Shaded Area = 0.96-zz Negative z-score = Positive z-score =

Tables of Areas under the Normal Curve 0 Area z TABLE V Standard Normal Distribution .02 .03 .04 .05 .06 .07 .08 .00 .01 -3.4 0.0003 0.0003 0.0003 0.0003 0.0003 <<-3.3 0.0005 0.0005 0.0005 0.0004 0.0004 <<-3.2 0.0007 0.0007 0.0006 0.0006 0.0006 -3.1 0.0010 0.0009 0.0009 0.0009 0.0008 <-3.0 0.0013 0.0013 0.0013 0.0012 0.0012 .09 0.0048 0.0003 0.0003 0.0003 0.0003 0.0002 0.0004 0.0004 0.0004 0.0004 0.0003 0.0006 0.0006 0.0005 0.0005 0.0005 0.0008 0.0008 0.0008 0.0007 0.0007 0.0011 0.0011 0.0011 0.0010 0.0010 -2.9 0.0019 0.0018 0.0018 0.0017 0.0016 0.0016 0.0015 0.0015 0.0014 0.0014 -2.8 0.0026 0.0025 0.0024 0.0023 0.0023 0.0022 0.0021 0.0021 0.0020 0.0019 -2.7 0.0035 0.0034 0.0033 0.0032 0.0031 0.0030 0.0029 0.0028 0.0027 0.0026 -2.6 0.0047 0.0045 0.0044 0.0043 0.0041 0.0040 0.0039 0.0038 0.0037 0.0036 -2.5 0.0062 0.0060 0.0059 0.0057 0.0055 0.0054 0.0052 0.0051 0.0049 -2.4 0.0082 0.0080 0.0078 0.0075 0.0073 0.0071 0.0069 0.0068 0.0066 -2.3 0.0107 0.0104 0.0102 0.0099 0.0096 0.0094…

An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 130 Ib and 171 lb. The new population of pilots has normally distributed weights with a mean of 140 lb and a standard deviation of 27.4 lb. Click here to view page 1 of the standard normal distribution. Click here to view page 2 of the standard normal distribution. a. If a pilot is randomly selected, find the probability that his weight is between 130 lb and 171 Ib. The probability is approximately (Round to four decimal places as needed.) b. If 36 different pilots are randomly selected, find the probability that their mean weight is between 130 Ib and 171 lb. The probability is approximately (Round to four decimal places as needed.) c. When redesigning the ejection seat, which probability is more relevant? O A. Part (a) because the seat performance for a sample of pilots is more important. O B. Part (a) because the seat performance for a single pilot is more important.…