Biochemistry
9th Edition
ISBN: 9781319114671
Author: Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher: W. H. Freeman
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- (a) 1 Normalized fluorescence 0.8 0.6 0.4 0.2 0 50 55 OM 0.100 M 0.200 M 0.300 M 0.500 M 1.00 M 2.00 M 60 113588 65 Temp. (°C) 70 75 80 Where is fully folded protein? • Where is fully unfolded protein? • Where is partially folded protein? • To what does SYPRO orange bind? • Why does fluorescence increase as a function of temperature? ● Define a melting temperature for a protein. • Demonstrate how an estimated melting temperature of the protein in zero molar ligand can be determined. • What is the effect of increasing the molar concentration on melting temperature for this protein? • Why is melting temperature a useful measurement to make for a protein especially if you are interested in protein aggregation?arrow_forwardWhat is the minimum length of the column required to completely separate the amino acids? What is the time required for solvent elution (i.e. time for all amino acids to exit the column)?arrow_forward80mL of a 0.3M solution of hexapeptide Leu-His-Cys-Glu-Asn-Arg is adjusted to pH=pI. The solution is then titrated with 0.2M HCL to a final pH of 2.1. Sketch the titration curve, labelling the pH and volume axes. Indicate the volume of HCL needed to reach relevant pKa value and equivalence point(s)z Relevant pKa values are: 2.1, 4.3, 6.0, 8.3, 9.8, and 12.5.arrow_forward
- This is a visible spectra between 390-590 nm obtained during the protein separation process of haemoglobin and cytochrome c using CM Sephadex chromatography. I'd like the results shown on the image interpreted. Look for characteristic peaks or patterns that correspond to the absorption properties of these proteins in the visible range.arrow_forwardDoes this calculation look correct? My goal isto have a target mass of 10 µg of my protein with a total volume of 30 µl. Protein was measured and found to have a concentration of at 308.35 µg/ml Recall, mass = concentration * volume 10 µg = 308.35 µg/ml * V V = 0.01 mg/ 0.30835 mg/mL = 0.032430679 mL = 32.43067942 µL Note: cannot measure this amount; two dilutions required. Dilute by 1/40: measure 2.5 µl of protein at 0.30835 µg/µl and add it to 97.5 diluent to prepare a solution of protein at 7.71 mg/ml. This diluted sample will be used further. Mass = concentration * volume 10 µg = 7.71 mg/ml * V V = 0.01 mg/ 7.71 mg/ml = 1.3 µL Therefore, will measure 1.3 µl of protein at 7.71 mg/ml and add it to 28.7 µl of diluent.arrow_forwardCan Hydrophobic Interaction Bead Chromatography be used to isolate Protein X from muscle tissue if Protein X contains many hydrophobic regions? Explain the process of how to isolate Protein X from muscle tissue.arrow_forward
- A purified protein sample was used in a reaction, resulting in an activity of 696.7 nmol min-1. The reaction volume was 145.0 µL and the final volume before loading the plate was 1,050 µL. The total reaction time was 4.25 min. The amount of protein used in the reaction was 4.270 µg. Calculate the specific activity of the sample (in nmol min-1 µg-1).arrow_forward5/ n SO a- 6.46 The following data show the binding of Mg2+ ions with a protein containing n equivalent sites: [Mg2+ ] total/μM [Mg2+ ]free/μM 108 Com 35 180 65 288 501 115 248 752 446 Apply the Scatchard plot to determine n and Ka. The protein concentration is 98 µM.arrow_forwardPlease don't provide handwritten solutionarrow_forward
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