Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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- The KM values for the reaction of chymotrypsin with two different substrates are given in the table below. Considering this information, which substrate has the lower apparent affinity for the enzyme? Which substrate is likely to give a lower value for Vmax? Substrate N-acetylvaline ethyl ester N-acetyltyrosine ethyl ester KM (M) 8.8 X 10-² 6.6 X 10-4 N-acetylvaline ethyl ester has the lower apparent affinity for the enzyme; it will also likely to give a lower Vmax: N-acetyltyrosine ethyl ester has the lower apparent affinity for the enzyme; it will also likely to give the lower V₁ max. N-acetylvaline ethyl ester has the lower apparent affinity for the enzyme; N- acetyltyrosine ethyl ester is likely to give the lower Vmax: N-acetyltyrosine ethyl ester has the lower apparent affinity for the enzyme; N- acetylvaline will likely to give the lower Vmax. None of the above statements are correct.arrow_forwardIn glycolysis, fructose 1,6-bisphosphate is converted to two products with a standard free- energy change (AG) of 23.8 kJ/mol. Under what cellular conditions will the free-energy change be negative, enabling the reaction to proceed spontaneously to form products? O In a cell where the concentrations of products and reactants yield a low value of the mass-action ratio Q ○ The reaction will not go to the right spontaneously under any conditions because the AG is positive ○ The reaction will proceed spontaneously to the right if there is a high concentration of products relative to the concentration of fructose 1,6-bisphosphate ○ The reaction will proceed spontaneously to the right if there is a high concentration of enzyme to catalyze the reaction O None of these conditions is sufficientarrow_forwardPlease provide an explanation for how to work through this practice problem: Using table 12.1, calculate the free energy change for the synthesis of ATP from cAMP and inorganic phosphate. (Note: cAMP is hydolyzed to AMP, and the free engery of hydrolysis for ATP and ADP is approximately equal.) Table 12.1: (Compound: Change in Free Energy in kJ/mol) cAMP: -50.4 Creatine phosphate: -43.3 ATP: -30.5 Glucose 6-phosphate: -13.9 AMP: -9.2arrow_forward
- This is a picture of the catalysis of alcohol by ADH with an inhibitor binding as an aldehyde analog. I have two questions. First, what would the enzyme be classified as and why? Also, what would the steps of this mechanism be?arrow_forward24. Hexokinase catalyzes the phosphorylation of glucose from ATP, yielding glucose-6-P and ADP. The standard-state free energy change for hydrolysis of glucose-6-P is -13.9 kJ/mol. Calculate the standard-state free energy change and equilibrium constant for the hexokinase reaction. AG" for ATP hydrolysis -31.5 kJ/molarrow_forwardChymotrypsin has the highest affinity for which of the following substrates: Table. The values of KM and kcat for some Enzymes and Substrates Enzyme Chymotrypsin Ки (М) 4.4 x 10-1 8.8 x 10-2 6.6 x 104 Kcat (S-1) 5.1 x 10-2 1.7 x 10-1 1.9 x 102 Substrate N-acetylglycine ethyl ester N-acetylvaline ethyl ester N-acetyltyrosine ethyl ester Catalase H2O2 2.5 x 10-2 1.0 x 107 Urease Urea 2.5 x 10-2 4.0 x 105 OA. N-acetylglycine ethyl ester OB. N-acetylvaline ethyl ester OC. N-acetyltyrosine ethyl ester D. Ureaarrow_forward
- NOTE: the enzyme-inhibitor complex requires 450 joule/mol to dissociateJOULE/MOLarrow_forwardProline racemase catalyzes the conversion between L-proline and D-proline. The Km and kcat for this reaction are 0.15 M and 550/sec respectively. If the enzyme concentration is 1.45 X 10-5 mmole/ml what is the Vmax of this reaction?arrow_forwardThe AG of the reaction C6H12O6 + 60₂ --> 6CO₂ + 6H₂O is -686 kcal/mol glucose oxidized. The AG of the reaction ADP + P₁ --> ATP + H₂O is + 7.3 kcal/mol ATP synthesized. The oxidation of glucose can be coupled to the synthesis of ATP. If the coupling is 50% efficient, how many molecules of ATP can be synthesized per molecule of glucose oxidized? Round your answer to the nearest whole number.arrow_forward
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