ng initially at 2.95 m/s on rough horizontal ice comes to rest uniformly in 4.00 s

1. For the purposes of this problem make sure you remember that the positive x direction is to the right. A 0.500 kg crash cart was rolling to the left at &; = -1.00 m/s. It was hit with a rubber hammer. Just afterwards the cart was rolling to the right with Uf = +2.50 m/s. The hammer was in contact with the cart for only 5.00 milliseconds. Remember to specify the direction in your answers as either postive or negative. (a) What is the change in momentum, Ap, for the cart? (b) What is the Impulse, I, applied by the hammer to the cart? (c) What is the average force, F, applied by the hammer to the cart? +x X+ Vf +X

1. A 32.00kg child runs with a speed of 6.00m and jumps onto a 20.00kg sled initially at rest on a flat bed of snow (no friction). What is the resultant speed of the child and sled after the child is atop the sled? S m S 2. The child-sled combo travel at velocity 12.00 and collide with a large snow bank, coming to rest after a 0.37s collision. What is the magnitude of the average force exerted on the child-sled combo by the snow bank during the collision? O 1037.84 N 518.59 N 1686.49 N 648.65 N m S

15. A pilot of mass 75 k plane is flying man normal? the she nears it feels four times heav diagram. 41.6657 FC V-1.54.10² 9.d (= 75 radius = 150 1.2 m 59m/ radiusis 54m T 3.6 kmph tmps 39 16. A ball of mass 4.0 kg is attached to the end of a 1.2 m long string and whirled around as shown at a velocity of 3.4 m/s. If the ball is rotated in a horizontal circle what angle does the string make with the horizontal? 0 r R 3g r= 2 V FTsino 2 Fg 41.66/2 3x9.8 FT F cose

A trap-jaw ant snaps its mandibles shut at very high speed, a good trait for catching small prey. But an ant can also slam its mandibles into the ground; the resulting force can launch the ant into the air for a quick escape. A 12 mgmg ant hits the ground with an average force of 47 mNmN for a time of 0.13 msms; these are all typical values.

8. You toss a 52.1 g ball straight up. The ball leaves your hand at 7.53 m/s. How high above your hand does the ball go?

ФЫ В А ПРО В А П Р О Л ДЗАПРОЛДЖЭ ЯЧСМИТНЧСМИТЬБНСМИТЬБЮ SOLVE STEP BY STEP IN DIGITAL FORMAT Two identical particles have the following speeds before the collision v_(0_A )=-20r m/s and v_(0_B )=20j m/s. They collide at the origin of coordinates in such a way that after the collision the speed of the ball A is v_A-10 m/s. What is the magnitude and direction of ball B after the collision? What is the torque around the origin in a particle located at x = 1.5m, y = -2 m, z=1.6 m, and due te a force fuerza F = 3.51-2.4j+ 4.3k [N? Express the result in unit vector notation, ИЦУКЕНГ ШУКЕНІ ШщЗЕНТ Шщзхь

A 61.0-kg athlete leaps straight up into the air from a trampoline with an initial speed of 9.7 m/s. The goal of this problem is to find the maximum height she attains and her speed at half maximum height. (a) What are the.interacting.objects and how.do.they.interact? This answer has not been graded yet (b) Select the height at which the athlete's speed is 9.7 m/s as y = 0. What is her kinetic energy at this point? What is the gravitational potential energy associated with the athlete? (c) What is her kinetic energy at maximum height? What is the gravitational potential energy associated with the athlete? (d) Write a general equation for energy conservation in this case and solve for the maximum height. Substitute and obtain a numerical answer. m (e) Write the general equation for energy conservation and solve for the velocity at half the maximum height. Substitute and obtain a numerical answer. m/s