An object of mass M-40 kg is pushed up an inclined plane with an acceleration of 0.5 m/s by a force T. The force T is parallel to the horizontal. The inclined plane forms an angle of 0-37 with the horizontal. The coefficient of kinetic friction of an object with an inclined plane is 0.20. a. Draw a free-body diagram of the forces acting on the block as it is pushed up an inclined plane. b. Determine the magnitude of the force T.

1. A car of mass 1000.0 kg is stationary on a slope forming an angle = 20° with the horizontal line. The car is located at a distance of 50 m from the foot of the slope. The coefficient of static friction between the tires and the road is μ = 0.20. a. Draw a free-body-diagram of the problem including all the information that is provided. b. Will the car slide down the slope? Motivate your answer to obtain any points. Once the car starts sliding down the slope, the coefficient of dynamic friction becomes μ = 0.15. c. Calculate the acceleration of the car. d. Calculate the velocity of the car at the foot of the slope. e. Calculate the kinetic energy of the car at the beginning and at the end of the motion. f. Calculate the total work done on the car. g. Calculate the gravitational potential energy of the car at the beginning and at the end of the motion. h. Calculate the work done on the car by the gravitational force. i. Calculate the work done on the car by the frictional force.

A physics major is cooking breakfast when he notices that the frictional force between the steel spatula and the Oiled Steel frying pan is only 0.150 N. Knowing the coefficient of kinetic friction between the two materials (0.03), he quickly calculates the normal force. What is it? N

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Calculate the magnitude of a normal force on a 22.7 kg block in the following circumstances. a. the block is resting on a level surface. b. the block is resting on a surface tilted up at 40.8 degrees with respect to the horizontal. c. the block is resting on the floor of an elevator that is accelerating upward at 2.53 m.s^2 d. the block is on the level surface and a force of 115 N is exerted on it at an angle of 40.8 degrees below the horizontal.

a. According to Newton's Second Law, the acceleration is directly proportional to the sum of the forces acting on the body. If M1 is less than M2, at what direction does the force due to M1 acts on M2? b. According to Newton's Second Law, the acceleration is directly proportional to the sum of the forces acting on the body. If M1 is greater than M2, at what direction does the force due to M2 acts on M1? c. If M1 < M2, what will be the direction of the acceleration of M1? d. If M1 > M2, what will be the direction of the acceleration of M2? e. If M1 is equal to M2, what will be the acceleration of the system?

e. A block with a mass of 25.5 kg is moving at constant velocity because a force of 138 N is applied to the right at an upward angle of 29.9 degrees as shown. Use g%3D10 N/kg. What is the magnitude of the friction force? units What is the magnitude of the normal force? units

The block shown in figure #1 above has a mass of 4.30 kg. The applied force (? ⃑ ) has a magnitude of 31.2 N and is 32.0° above the horizontal, frictionless surface the block in on.  a. What is the normal force (magnitude and direction) that acts on the block? b. What is the acceleration (magnitude and direction) that is experienced by the block?

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In the figure puck 1 of mass m₁ = 0.50 kg is sent sliding across a frictionless lab bench, to undergo a one-dimensional elastic collision with stationary puck 2. Puck 2 then slides off the bench and lands a distance d from the base of the bench. Puck 1 rebounds from the collision and slides off the opposite edge of the bench, landing a distance 5d from the base of the bench. What is the mass of puck 2? (Hint: Be careful with signs.) -5 d- Number i |d- Units