Database System Concepts
Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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Functions that return the value of a base and an exponent is very common so I want to switch it up.

This time, we’re going to try to reverse-engineer these functions and find out the exponent of a certain number based on the value of the result and the base used to get that value.

 

For example, if the base is 2 and the result is 8, then the output should be 3 because the exponent needed for 2 to become 8 is 3 (i.e. 23 = 8)

 

Instructions:

  1. In the code editor, you are provided with a main() function that asks the user for two integer inputs:
    1. The first integer is the base
    2. The second integer is the result
  2. Furthermore, you are provided with the getExponent() function which is partially implemented. The details of this function are the following:
    1. Return type - int
    2. Name - getExponent
    3. Parameters
      1. int - base
      2. int - result
    4. Description - this recursive function returns the exponent
  3. Your task is to add the base case of this recursive function so that it will work properly.

Input

1. The base

2. The result

Output

Enter the base: 2
Enter the result: 8
Exponent = 3
 
IN C LANGUAGE PLEASE, THANK YOU.
main.c 2. Reverse Engineering by CodeChum Admin 1 Finctutestrio.ts 3 int ge texporent(int, int): Functions that return the value of a base and an exponent is very comman so I want to switch it up. int nainvoid) { int bose, result: This time, we're going to try to reverse-engincer these functions printfC Enter the tese i): scanfCse, akse): and find out the exponent of a certain number based on the valuc of the result and the base used to get that value. 18 prirtfC Enter the resulti ): scarfC e", aresult): 11 For example, if the base is 2 and the result is 8, then the output should be 3 because the exponent neoded for 2 to become 8 is 3 0.c. 2 - 8) prirtfC Bxporent - 5d". petexponent(se, result)): 10 return 2: Instructions: 18 1. In the code editor, you are provided with a main) function 19 - int ge tBxporent(int b:se, int result) 20 that asks the user for two integer inputs: if(ese> resilt) { 1. The first integer is the base 2. The second integer is the result 21 return 0: 22 2. Furthermore, you are provided wnh the getixponent0 function which is partially implomented. Thc details of this function are tha following 1. Heturn type int 23 24 // TODO I Ing lenent the base cose here ifO { 23 20 return } e lse { return 1 + ge tExporent(bese, (int) result / tose): 27 2. Name - getExponent 3. Parameters 1. int - base 2. int - result 28 23 31 H 4. Description - this recursive function returns thc exponent 3. Your task is to add the base case of this rocursive function so that it will work property. Input 1. The base 2. The result Output Enter the base: 2 Enter the result: 8 Exponent 3
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Transcribed Image Text:main.c 2. Reverse Engineering by CodeChum Admin 1 Finctutestrio.ts 3 int ge texporent(int, int): Functions that return the value of a base and an exponent is very comman so I want to switch it up. int nainvoid) { int bose, result: This time, we're going to try to reverse-engincer these functions printfC Enter the tese i): scanfCse, akse): and find out the exponent of a certain number based on the valuc of the result and the base used to get that value. 18 prirtfC Enter the resulti ): scarfC e", aresult): 11 For example, if the base is 2 and the result is 8, then the output should be 3 because the exponent neoded for 2 to become 8 is 3 0.c. 2 - 8) prirtfC Bxporent - 5d". petexponent(se, result)): 10 return 2: Instructions: 18 1. In the code editor, you are provided with a main) function 19 - int ge tBxporent(int b:se, int result) 20 that asks the user for two integer inputs: if(ese> resilt) { 1. The first integer is the base 2. The second integer is the result 21 return 0: 22 2. Furthermore, you are provided wnh the getixponent0 function which is partially implomented. Thc details of this function are tha following 1. Heturn type int 23 24 // TODO I Ing lenent the base cose here ifO { 23 20 return } e lse { return 1 + ge tExporent(bese, (int) result / tose): 27 2. Name - getExponent 3. Parameters 1. int - base 2. int - result 28 23 31 H 4. Description - this recursive function returns thc exponent 3. Your task is to add the base case of this rocursive function so that it will work property. Input 1. The base 2. The result Output Enter the base: 2 Enter the result: 8 Exponent 3
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